Learn on PengiSaxon Math, Course 2Chapter 1: Lessons 1-10, Investigation 1

Lesson 3: Unknown Numbers in Addition, Subtraction, Multiplication, and Division

In this Grade 7 Saxon Math Course 2 lesson, students learn how to find unknown numbers represented by variables in addition, subtraction, multiplication, and division equations using inverse operations. The lesson covers identifying unknown sums, addends, minuends, subtrahends, and differences, and teaches students to check their solutions by substituting answers back into the original equation. Part of Chapter 1, it builds foundational algebra skills essential for working with equations throughout the course.

Section 1

πŸ“˜ Unknown Numbers in Addition, Subtraction, Multiplication, and Division

New Concept

An equation is a statement that two quantities are equal. Here we show two equations:

3+4=75+a=9 3+4=7 \quad 5+a=9

What’s next

This is just the start of your journey with equations. Next, you'll tackle worked examples for finding unknowns in addition, subtraction, multiplication, and division problems.

Section 2

Equation

Property

An equation is a statement that two quantities are equal, like 5+a=95+a=9.

Examples

An addition equation with an unknown addend: x+10=25x + 10 = 25.
An subtraction equation with an unknown subtrahend: 50βˆ’y=3050 - y = 30.
A multiplication equation with an unknown factor: 8k=648k = 64.

Explanation

Think of an equation as a perfectly balanced scale. Whatever is on the left side must equal the right side. If a number is missing (represented by a variable), your job is to figure out what that number must be to keep the scale from tipping. It’s all about finding that magic number to maintain balance!

Section 3

Finding an Unknown Addend

Property

We can find an unknown addend by subtracting the known addend from the sum.

Examples

Find the unknown number: a+25=70β€…β€ŠβŸΉβ€…β€Ša=70βˆ’25β€…β€ŠβŸΉβ€…β€Ša=45a + 25 = 70 \implies a = 70 - 25 \implies a = 45.
Find the unknown number: 10+n+20=55β€…β€ŠβŸΉβ€…β€Š30+n=55β€…β€ŠβŸΉβ€…β€Šn=55βˆ’30β€…β€ŠβŸΉβ€…β€Šn=2510 + n + 20 = 55 \implies 30 + n = 55 \implies n = 55 - 30 \implies n = 25.

Explanation

Think of this as a number mystery! You know the final total (the sum) and one of the pieces (an addend). To find the secret number, simply subtract the known piece from the total. Subtraction is the inverse of addition, making it the perfect tool to work backward and solve for the unknown value!

Section 4

Finding an Unknown Factor

Property

To find an unknown factor, we divide the product by the known factor(s).

Examples

Find the unknown number: 9k=81β€…β€ŠβŸΉβ€…β€Šk=81Γ·9β€…β€ŠβŸΉβ€…β€Šk=99k = 81 \implies k = 81 \div 9 \implies k = 9.
Find the unknown number: mΓ—6=120β€…β€ŠβŸΉβ€…β€Šm=120Γ·6β€…β€ŠβŸΉβ€…β€Šm=20m \times 6 = 120 \implies m = 120 \div 6 \implies m = 20.

Explanation

When a number is hiding in a multiplication problem, division is your secret weapon! Since division is the inverse of multiplication, you can undo the problem by dividing the total product by the factor you already know. This powerful move isolates the mystery factor and reveals its true identity every single time.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Arithmetic with Whole Numbers and Money

  2. Lesson 2

    Lesson 2: Properties of Operations

  3. Lesson 3Current

    Lesson 3: Unknown Numbers in Addition, Subtraction, Multiplication, and Division

  4. Lesson 4

    Lesson 4: Number Line, Sequences

  5. Lesson 5

    Lesson 5: Place Value Through Hundred Trillions, Reading and Writing Whole Numbers

  6. Lesson 6

    Lesson 6: Factors, Divisibility

  7. Lesson 7

    Lesson 7: Lines, Angles and Planes

  8. Lesson 8

    Lesson 8: Fractions and Percents

  9. Lesson 9

    Lesson 9: Adding, Subtracting, and Multiplying Fractions

  10. Lesson 10

    Lesson 10: Writing Division Answers as Mixed Numbers

  11. Lesson 11

    Investigation 1: Investigating Fractions and Percents with Manipulatives

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Unknown Numbers in Addition, Subtraction, Multiplication, and Division

New Concept

An equation is a statement that two quantities are equal. Here we show two equations:

3+4=75+a=9 3+4=7 \quad 5+a=9

What’s next

This is just the start of your journey with equations. Next, you'll tackle worked examples for finding unknowns in addition, subtraction, multiplication, and division problems.

Section 2

Equation

Property

An equation is a statement that two quantities are equal, like 5+a=95+a=9.

Examples

An addition equation with an unknown addend: x+10=25x + 10 = 25.
An subtraction equation with an unknown subtrahend: 50βˆ’y=3050 - y = 30.
A multiplication equation with an unknown factor: 8k=648k = 64.

Explanation

Think of an equation as a perfectly balanced scale. Whatever is on the left side must equal the right side. If a number is missing (represented by a variable), your job is to figure out what that number must be to keep the scale from tipping. It’s all about finding that magic number to maintain balance!

Section 3

Finding an Unknown Addend

Property

We can find an unknown addend by subtracting the known addend from the sum.

Examples

Find the unknown number: a+25=70β€…β€ŠβŸΉβ€…β€Ša=70βˆ’25β€…β€ŠβŸΉβ€…β€Ša=45a + 25 = 70 \implies a = 70 - 25 \implies a = 45.
Find the unknown number: 10+n+20=55β€…β€ŠβŸΉβ€…β€Š30+n=55β€…β€ŠβŸΉβ€…β€Šn=55βˆ’30β€…β€ŠβŸΉβ€…β€Šn=2510 + n + 20 = 55 \implies 30 + n = 55 \implies n = 55 - 30 \implies n = 25.

Explanation

Think of this as a number mystery! You know the final total (the sum) and one of the pieces (an addend). To find the secret number, simply subtract the known piece from the total. Subtraction is the inverse of addition, making it the perfect tool to work backward and solve for the unknown value!

Section 4

Finding an Unknown Factor

Property

To find an unknown factor, we divide the product by the known factor(s).

Examples

Find the unknown number: 9k=81β€…β€ŠβŸΉβ€…β€Šk=81Γ·9β€…β€ŠβŸΉβ€…β€Šk=99k = 81 \implies k = 81 \div 9 \implies k = 9.
Find the unknown number: mΓ—6=120β€…β€ŠβŸΉβ€…β€Šm=120Γ·6β€…β€ŠβŸΉβ€…β€Šm=20m \times 6 = 120 \implies m = 120 \div 6 \implies m = 20.

Explanation

When a number is hiding in a multiplication problem, division is your secret weapon! Since division is the inverse of multiplication, you can undo the problem by dividing the total product by the factor you already know. This powerful move isolates the mystery factor and reveals its true identity every single time.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Arithmetic with Whole Numbers and Money

  2. Lesson 2

    Lesson 2: Properties of Operations

  3. Lesson 3Current

    Lesson 3: Unknown Numbers in Addition, Subtraction, Multiplication, and Division

  4. Lesson 4

    Lesson 4: Number Line, Sequences

  5. Lesson 5

    Lesson 5: Place Value Through Hundred Trillions, Reading and Writing Whole Numbers

  6. Lesson 6

    Lesson 6: Factors, Divisibility

  7. Lesson 7

    Lesson 7: Lines, Angles and Planes

  8. Lesson 8

    Lesson 8: Fractions and Percents

  9. Lesson 9

    Lesson 9: Adding, Subtracting, and Multiplying Fractions

  10. Lesson 10

    Lesson 10: Writing Division Answers as Mixed Numbers

  11. Lesson 11

    Investigation 1: Investigating Fractions and Percents with Manipulatives