Learn on PengiSaxon Algebra 2Chapter 1: Lessons 1-10, Investigation 1

Lesson 9: Multiplying Matrices

In this Grade 10 Saxon Algebra 2 lesson, students learn how to multiply matrices by applying the row-by-column method, where each element of the product matrix is found by summing the products of corresponding row and column entries. The lesson covers how to determine whether matrix multiplication is defined using inner dimensions, how to find the dimensions of the resulting product matrix, and why matrix multiplication is not commutative. Students also explore square matrices, the main diagonal, and the multiplicative identity matrix and its property that AI equals IA equals A.

Section 1

πŸ“˜ Multiplying Matrices

New Concept

A=[abcd]βˆ™[efgh]=[ae+bgaf+bhce+dgcf+dh]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \bullet \begin{bmatrix} e & f \\ g & h \end{bmatrix} = \begin{bmatrix} ae + bg & af + bh \\ ce + dg & cf + dh \end{bmatrix}

What’s next

Next, you’ll use this process to solve problems, explore matrix properties, and apply multiplication to a real-world shopping scenario.

Section 2

Matrix Multiplication

A matrix AA can be multiplied by a matrix BB if the number of columns in AA equals the number of rows in BB. To find an element in the product matrix, multiply the elements of a row from the first matrix by the corresponding elements of a column from the second matrix, then add the products.

A=[abcd]βˆ™[efgh]=[ae+bgaf+bhce+dgcf+dh]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \bullet \begin{bmatrix} e & f \\ g & h \end{bmatrix} = \begin{bmatrix} ae + bg & af + bh \\ ce + dg & cf + dh \end{bmatrix}

Find ABAB if A=[1βˆ’24023]A = \begin{bmatrix} 1 & -2 \\ 4 & 0 \\ 2 & 3 \end{bmatrix} and B=[512βˆ’4]B = \begin{bmatrix} 5 & 1 \\ 2 & -4 \end{bmatrix}. The product is AB=[1(5)+(βˆ’2)(2)1(1)+(βˆ’2)(βˆ’4)4(5)+0(2)4(1)+0(βˆ’4)2(5)+3(2)2(1)+3(βˆ’4)]=[1920416βˆ’10]AB = \begin{bmatrix} 1(5)+(-2)(2) & 1(1)+(-2)(-4) \\ 4(5)+0(2) & 4(1)+0(-4) \\ 2(5)+3(2) & 2(1)+3(-4) \end{bmatrix} = \begin{bmatrix} 1 & 9 \\ 20 & 4 \\ 16 & -10 \end{bmatrix}.
Find XYXY if X=[2βˆ’135]X = \begin{bmatrix} 2 & -1 \\ 3 & 5 \end{bmatrix} and Y=[041βˆ’2]Y = \begin{bmatrix} 0 & 4 \\ 1 & -2 \end{bmatrix}. The product is XY=[2(0)+(βˆ’1)(1)2(4)+(βˆ’1)(βˆ’2)3(0)+5(1)3(4)+5(βˆ’2)]=[βˆ’11052]XY = \begin{bmatrix} 2(0)+(-1)(1) & 2(4)+(-1)(-2) \\ 3(0)+5(1) & 3(4)+5(-2) \end{bmatrix} = \begin{bmatrix} -1 & 10 \\ 5 & 2 \end{bmatrix}.

Think of it as a 'row-hugs-column' dance! Each number in a row from the first matrix finds a partner in the corresponding column of the second matrix. They multiply, and all the pairs in that dance sum up to create one number in the final matrix. This repeats for every row and every column until the new matrix is complete.

Section 3

Product Matrix

When two matrices can be multiplied, the resulting matrix is called the product matrix. If an mΓ—nm \times n matrix is multiplied by an nΓ—pn \times p matrix, the dimensions of the product matrix are determined by the 'outside' numbers, resulting in an mΓ—pm \times p matrix.

Matrix AA is 2Γ—52 \times 5 and Matrix BB is 5Γ—45 \times 4. The product ABAB is defined and the product matrix will have dimensions 2Γ—42 \times 4.
Matrix CC is 3Γ—13 \times 1 and Matrix DD is 2Γ—32 \times 3. The product CDCD is not defined because the inner dimensions (1 and 2) do not match.
Matrix XX is 1Γ—71 \times 7 and Matrix YY is 7Γ—17 \times 1. The product XYXY is defined and the product matrix will have dimensions 1Γ—11 \times 1.

Before you do any math, play matchmaker with the dimensions! If you have a 4Γ—34 \times 3 matrix and a 3Γ—53 \times 5 matrix, the inner '3s' match, so multiplication is possible. The outer numbers, 4 and 5, give you a sneak peek at the answer's size: your final product matrix will be a glorious 4Γ—54 \times 5 matrix.

Section 4

Multiplicative Identity Matrix

The multiplicative identity matrix, denoted as II, is a square matrix where all elements on the main diagonal are ones and all other elements are zeros. The product of any matrix AA and the appropriate identity matrix II is always AA.

AI=IA=AAI = IA = A

For A=[51βˆ’28]A = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix} and I=[1001]I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}, then AI=[51βˆ’28][1001]=[51βˆ’28]AI = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix}\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix}.
For B=[4βˆ’1720βˆ’5]B = \begin{bmatrix} 4 & -1 & 7 \\ 2 & 0 & -5 \end{bmatrix} and I=[100010001]I = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}, then BI=[4βˆ’1720βˆ’5]BI = \begin{bmatrix} 4 & -1 & 7 \\ 2 & 0 & -5 \end{bmatrix}.

Meet the superhero of matrices: the Identity Matrix, or II! It's the matrix version of the number 1. Multiplying any matrix by II is like giving it a high-fiveβ€”it leaves the original matrix completely unchanged. This special square matrix has a slick diagonal of ones and is your go-to for preserving a matrix's identity during calculations.

Section 5

Consumer Math Application

Matrix multiplication is a powerful tool for organizing and solving real-world problems involving multiple quantities and costs. By setting up a quantity matrix and a cost matrix, their product can efficiently calculate total expenses for different categories or individuals in a single, structured operation.

Three friends buy school supplies. Ann buys 2 pens, 1 notebook. Ben buys 1 pen, 3 notebooks. Pens are 2 dollars, notebooks are 4 dollars. [2113][24]=[2(2)+1(4)1(2)+3(4)]=[814]\begin{bmatrix} 2 & 1 \\ 1 & 3 \end{bmatrix}\begin{bmatrix} 2 \\ 4 \end{bmatrix} = \begin{bmatrix} 2(2)+1(4) \\ 1(2)+3(4) \end{bmatrix} = \begin{bmatrix} 8 \\ 14 \end{bmatrix}. Ann spends 8 dollars, Ben spends 14 dollars.
Uniforms cost 30 dollars for jerseys and 20 dollars for shorts. Team A needs 10 of each. Team B needs 12 of each. [10101212][3020]=[500600]\begin{bmatrix} 10 & 10 \\ 12 & 12 \end{bmatrix}\begin{bmatrix} 30 \\ 20 \end{bmatrix} = \begin{bmatrix} 500 \\ 600 \end{bmatrix}. Team A spends 500 dollars, Team B spends 600 dollars.

Who knew matrices could manage your shopping trip? Imagine you have a list of items each friend wants (the quantity matrix) and a list of prices (the cost matrix). Multiplying them together instantly calculates the total bill for each person! It's like having a super-organized personal shopper that handles all the money math in one clean step.

Book overview

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Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Using Properties of Real Numbers

  2. Lesson 2

    Lesson 2: Evaluating Expressions and Combining Like Terms

  3. Lesson 3

    Lesson 3: Using Rules of Exponents

  4. Lesson 4

    LAB 1: Graphing Calculator: Graphing a Function and Building a Table

  5. Lesson 5

    Lesson 4: Identifying Functions and Using Function Notation

  6. Lesson 6

    LAB 2: Graphing Calculator: Storing and Recalling Data in a Matrix

  7. Lesson 7

    Lesson 5: Using Matrices to Organize Data and to Solve Problems

  8. Lesson 8

    Lesson 6: Finding Percent of Change

  9. Lesson 9

    Lesson 7: Solving Linear Equations (Exploration: Solving Equations Using Algebra Tiles)

  10. Lesson 10

    Lesson 8: Finding Direct Variation

  11. Lesson 11Current

    Lesson 9: Multiplying Matrices

  12. Lesson 12

    Lesson 10: Solving and Graphing Inequalities

  13. Lesson 13

    Investigation 1: Logic and Truth Tables

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

πŸ“˜ Multiplying Matrices

New Concept

A=[abcd]βˆ™[efgh]=[ae+bgaf+bhce+dgcf+dh]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \bullet \begin{bmatrix} e & f \\ g & h \end{bmatrix} = \begin{bmatrix} ae + bg & af + bh \\ ce + dg & cf + dh \end{bmatrix}

What’s next

Next, you’ll use this process to solve problems, explore matrix properties, and apply multiplication to a real-world shopping scenario.

Section 2

Matrix Multiplication

A matrix AA can be multiplied by a matrix BB if the number of columns in AA equals the number of rows in BB. To find an element in the product matrix, multiply the elements of a row from the first matrix by the corresponding elements of a column from the second matrix, then add the products.

A=[abcd]βˆ™[efgh]=[ae+bgaf+bhce+dgcf+dh]A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \bullet \begin{bmatrix} e & f \\ g & h \end{bmatrix} = \begin{bmatrix} ae + bg & af + bh \\ ce + dg & cf + dh \end{bmatrix}

Find ABAB if A=[1βˆ’24023]A = \begin{bmatrix} 1 & -2 \\ 4 & 0 \\ 2 & 3 \end{bmatrix} and B=[512βˆ’4]B = \begin{bmatrix} 5 & 1 \\ 2 & -4 \end{bmatrix}. The product is AB=[1(5)+(βˆ’2)(2)1(1)+(βˆ’2)(βˆ’4)4(5)+0(2)4(1)+0(βˆ’4)2(5)+3(2)2(1)+3(βˆ’4)]=[1920416βˆ’10]AB = \begin{bmatrix} 1(5)+(-2)(2) & 1(1)+(-2)(-4) \\ 4(5)+0(2) & 4(1)+0(-4) \\ 2(5)+3(2) & 2(1)+3(-4) \end{bmatrix} = \begin{bmatrix} 1 & 9 \\ 20 & 4 \\ 16 & -10 \end{bmatrix}.
Find XYXY if X=[2βˆ’135]X = \begin{bmatrix} 2 & -1 \\ 3 & 5 \end{bmatrix} and Y=[041βˆ’2]Y = \begin{bmatrix} 0 & 4 \\ 1 & -2 \end{bmatrix}. The product is XY=[2(0)+(βˆ’1)(1)2(4)+(βˆ’1)(βˆ’2)3(0)+5(1)3(4)+5(βˆ’2)]=[βˆ’11052]XY = \begin{bmatrix} 2(0)+(-1)(1) & 2(4)+(-1)(-2) \\ 3(0)+5(1) & 3(4)+5(-2) \end{bmatrix} = \begin{bmatrix} -1 & 10 \\ 5 & 2 \end{bmatrix}.

Think of it as a 'row-hugs-column' dance! Each number in a row from the first matrix finds a partner in the corresponding column of the second matrix. They multiply, and all the pairs in that dance sum up to create one number in the final matrix. This repeats for every row and every column until the new matrix is complete.

Section 3

Product Matrix

When two matrices can be multiplied, the resulting matrix is called the product matrix. If an mΓ—nm \times n matrix is multiplied by an nΓ—pn \times p matrix, the dimensions of the product matrix are determined by the 'outside' numbers, resulting in an mΓ—pm \times p matrix.

Matrix AA is 2Γ—52 \times 5 and Matrix BB is 5Γ—45 \times 4. The product ABAB is defined and the product matrix will have dimensions 2Γ—42 \times 4.
Matrix CC is 3Γ—13 \times 1 and Matrix DD is 2Γ—32 \times 3. The product CDCD is not defined because the inner dimensions (1 and 2) do not match.
Matrix XX is 1Γ—71 \times 7 and Matrix YY is 7Γ—17 \times 1. The product XYXY is defined and the product matrix will have dimensions 1Γ—11 \times 1.

Before you do any math, play matchmaker with the dimensions! If you have a 4Γ—34 \times 3 matrix and a 3Γ—53 \times 5 matrix, the inner '3s' match, so multiplication is possible. The outer numbers, 4 and 5, give you a sneak peek at the answer's size: your final product matrix will be a glorious 4Γ—54 \times 5 matrix.

Section 4

Multiplicative Identity Matrix

The multiplicative identity matrix, denoted as II, is a square matrix where all elements on the main diagonal are ones and all other elements are zeros. The product of any matrix AA and the appropriate identity matrix II is always AA.

AI=IA=AAI = IA = A

For A=[51βˆ’28]A = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix} and I=[1001]I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}, then AI=[51βˆ’28][1001]=[51βˆ’28]AI = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix}\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix} = \begin{bmatrix} 5 & 1 \\ -2 & 8 \end{bmatrix}.
For B=[4βˆ’1720βˆ’5]B = \begin{bmatrix} 4 & -1 & 7 \\ 2 & 0 & -5 \end{bmatrix} and I=[100010001]I = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}, then BI=[4βˆ’1720βˆ’5]BI = \begin{bmatrix} 4 & -1 & 7 \\ 2 & 0 & -5 \end{bmatrix}.

Meet the superhero of matrices: the Identity Matrix, or II! It's the matrix version of the number 1. Multiplying any matrix by II is like giving it a high-fiveβ€”it leaves the original matrix completely unchanged. This special square matrix has a slick diagonal of ones and is your go-to for preserving a matrix's identity during calculations.

Section 5

Consumer Math Application

Matrix multiplication is a powerful tool for organizing and solving real-world problems involving multiple quantities and costs. By setting up a quantity matrix and a cost matrix, their product can efficiently calculate total expenses for different categories or individuals in a single, structured operation.

Three friends buy school supplies. Ann buys 2 pens, 1 notebook. Ben buys 1 pen, 3 notebooks. Pens are 2 dollars, notebooks are 4 dollars. [2113][24]=[2(2)+1(4)1(2)+3(4)]=[814]\begin{bmatrix} 2 & 1 \\ 1 & 3 \end{bmatrix}\begin{bmatrix} 2 \\ 4 \end{bmatrix} = \begin{bmatrix} 2(2)+1(4) \\ 1(2)+3(4) \end{bmatrix} = \begin{bmatrix} 8 \\ 14 \end{bmatrix}. Ann spends 8 dollars, Ben spends 14 dollars.
Uniforms cost 30 dollars for jerseys and 20 dollars for shorts. Team A needs 10 of each. Team B needs 12 of each. [10101212][3020]=[500600]\begin{bmatrix} 10 & 10 \\ 12 & 12 \end{bmatrix}\begin{bmatrix} 30 \\ 20 \end{bmatrix} = \begin{bmatrix} 500 \\ 600 \end{bmatrix}. Team A spends 500 dollars, Team B spends 600 dollars.

Who knew matrices could manage your shopping trip? Imagine you have a list of items each friend wants (the quantity matrix) and a list of prices (the cost matrix). Multiplying them together instantly calculates the total bill for each person! It's like having a super-organized personal shopper that handles all the money math in one clean step.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Using Properties of Real Numbers

  2. Lesson 2

    Lesson 2: Evaluating Expressions and Combining Like Terms

  3. Lesson 3

    Lesson 3: Using Rules of Exponents

  4. Lesson 4

    LAB 1: Graphing Calculator: Graphing a Function and Building a Table

  5. Lesson 5

    Lesson 4: Identifying Functions and Using Function Notation

  6. Lesson 6

    LAB 2: Graphing Calculator: Storing and Recalling Data in a Matrix

  7. Lesson 7

    Lesson 5: Using Matrices to Organize Data and to Solve Problems

  8. Lesson 8

    Lesson 6: Finding Percent of Change

  9. Lesson 9

    Lesson 7: Solving Linear Equations (Exploration: Solving Equations Using Algebra Tiles)

  10. Lesson 10

    Lesson 8: Finding Direct Variation

  11. Lesson 11Current

    Lesson 9: Multiplying Matrices

  12. Lesson 12

    Lesson 10: Solving and Graphing Inequalities

  13. Lesson 13

    Investigation 1: Logic and Truth Tables