Learn on PengiSaxon Algebra 2Chapter 1: Lessons 1-10, Investigation 1

Lesson 7: Solving Linear Equations (Exploration: Solving Equations Using Algebra Tiles)

In this Grade 10 Saxon Algebra 2 lesson, students learn to solve linear equations using the four properties of equality — addition, subtraction, multiplication, and division — including equations with variables on both sides, the distributive property, and fractional coefficients. The lesson introduces algebra tiles as a visual exploration tool and emphasizes transforming equations into equivalent forms by applying inverse operations in the correct order. Students also practice writing and solving equations from real-world word problems, reinforcing how solution sets are verified by substitution.

Section 1

📘 Solving Linear Equations

New Concept

An equation is a statement which indicates that two expressions are equal.

Why it matters

Equations are the language used to describe relationships in everything from physics to finance. Mastering the properties of equality is your first step toward building complex models and solving for unknown variables in any system.

What’s next

Next, you’ll apply the properties of equality to solve equations with variables on one or both sides, and even those involving fractions.

Section 2

Solution of an equation

A number is a solution of an equation in one variable if substituting the number for the variable results in a true statement.

Is x=5x = 5 a solution to 3x2=133x - 2 = 13? Check: 3(5)2=152=133(5) - 2 = 15 - 2 = 13. Yes, it's a true statement!|Is y=2y = -2 a solution to 4y+10=34y + 10 = 3? Check: 4(2)+10=8+10=24(-2) + 10 = -8 + 10 = 2. No, because 232 \neq 3.|To confirm the solution to 6n+1=136n+1=13 is n=2n=2, substitute it back: 6(2)+1=12+1=136(2)+1 = 12+1 = 13. It checks out!

Finding a solution is like discovering the secret code that opens a lock! You are hunting for that one specific number that you can substitute for the variable to make both sides of the equation perfectly equal. If they match after you plug it in, you have successfully found the code. If they do not, the mystery remains unsolved.

Section 3

Properties of Equality

Addition: If a=ba = b then a+c=b+ca + c = b + c. Subtraction: If a=ba = b then ac=bca - c = b - c. Multiplication: If a=ba = b then ac=bcac = bc. Division: If a=ba = b and c0c \neq 0 then ac=bc\frac{a}{c} = \frac{b}{c}.

To solve x8=10x - 8 = 10, use the Addition Property: x8+8=10+8x - 8 + 8 = 10 + 8, which simplifies to x=18x = 18.
To solve 4y=244y = 24, use the Division Property: 4y4=244\frac{4y}{4} = \frac{24}{4}, which simplifies to y=6y = 6.
To solve 2x+5=15-2x + 5 = 15, first subtract 5: 2x=10-2x = 10. Then divide by -2: x=5x = -5.

Imagine an equation is a perfectly balanced seesaw. To keep it level, whatever you do to one side, you must do the exact same thing to the other. Whether you add, subtract, multiply, or divide by a number, applying the action to both sides ensures the equation remains true, helping you isolate the variable and solve the puzzle.

Section 4

Solving Equations with Variables on Both Sides

To solve equations with variables on both sides, first use the Addition or Subtraction Property of Equality to collect the variable terms on one side of the equation. Then, use the properties of equality to isolate the variable.

Solve 5x4=2x+115x - 4 = 2x + 11. First, subtract 2x2x from both sides to get 3x4=113x - 4 = 11.|Continuing from 3x4=113x - 4 = 11, add 4 to both sides: 3x=153x = 15. Now, divide by 3 to get x=5x = 5.|For 8y+5=10y18y + 5 = 10y - 1, subtract 8y8y from both sides: 5=2y15 = 2y - 1. Then add 1: 6=2y6 = 2y, so y=3y = 3.

When variables appear on both sides of an equation, it is like a mathematical tug-of-war. Your first move is to gather all the variable terms onto one team by adding or subtracting them from both sides. Once all variables are grouped together, you can combine them and use the properties of equality to find out who wins!

Book overview

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Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Using Properties of Real Numbers

  2. Lesson 2

    Lesson 2: Evaluating Expressions and Combining Like Terms

  3. Lesson 3

    Lesson 3: Using Rules of Exponents

  4. Lesson 4

    LAB 1: Graphing Calculator: Graphing a Function and Building a Table

  5. Lesson 5

    Lesson 4: Identifying Functions and Using Function Notation

  6. Lesson 6

    LAB 2: Graphing Calculator: Storing and Recalling Data in a Matrix

  7. Lesson 7

    Lesson 5: Using Matrices to Organize Data and to Solve Problems

  8. Lesson 8

    Lesson 6: Finding Percent of Change

  9. Lesson 9Current

    Lesson 7: Solving Linear Equations (Exploration: Solving Equations Using Algebra Tiles)

  10. Lesson 10

    Lesson 8: Finding Direct Variation

  11. Lesson 11

    Lesson 9: Multiplying Matrices

  12. Lesson 12

    Lesson 10: Solving and Graphing Inequalities

  13. Lesson 13

    Investigation 1: Logic and Truth Tables

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Solving Linear Equations

New Concept

An equation is a statement which indicates that two expressions are equal.

Why it matters

Equations are the language used to describe relationships in everything from physics to finance. Mastering the properties of equality is your first step toward building complex models and solving for unknown variables in any system.

What’s next

Next, you’ll apply the properties of equality to solve equations with variables on one or both sides, and even those involving fractions.

Section 2

Solution of an equation

A number is a solution of an equation in one variable if substituting the number for the variable results in a true statement.

Is x=5x = 5 a solution to 3x2=133x - 2 = 13? Check: 3(5)2=152=133(5) - 2 = 15 - 2 = 13. Yes, it's a true statement!|Is y=2y = -2 a solution to 4y+10=34y + 10 = 3? Check: 4(2)+10=8+10=24(-2) + 10 = -8 + 10 = 2. No, because 232 \neq 3.|To confirm the solution to 6n+1=136n+1=13 is n=2n=2, substitute it back: 6(2)+1=12+1=136(2)+1 = 12+1 = 13. It checks out!

Finding a solution is like discovering the secret code that opens a lock! You are hunting for that one specific number that you can substitute for the variable to make both sides of the equation perfectly equal. If they match after you plug it in, you have successfully found the code. If they do not, the mystery remains unsolved.

Section 3

Properties of Equality

Addition: If a=ba = b then a+c=b+ca + c = b + c. Subtraction: If a=ba = b then ac=bca - c = b - c. Multiplication: If a=ba = b then ac=bcac = bc. Division: If a=ba = b and c0c \neq 0 then ac=bc\frac{a}{c} = \frac{b}{c}.

To solve x8=10x - 8 = 10, use the Addition Property: x8+8=10+8x - 8 + 8 = 10 + 8, which simplifies to x=18x = 18.
To solve 4y=244y = 24, use the Division Property: 4y4=244\frac{4y}{4} = \frac{24}{4}, which simplifies to y=6y = 6.
To solve 2x+5=15-2x + 5 = 15, first subtract 5: 2x=10-2x = 10. Then divide by -2: x=5x = -5.

Imagine an equation is a perfectly balanced seesaw. To keep it level, whatever you do to one side, you must do the exact same thing to the other. Whether you add, subtract, multiply, or divide by a number, applying the action to both sides ensures the equation remains true, helping you isolate the variable and solve the puzzle.

Section 4

Solving Equations with Variables on Both Sides

To solve equations with variables on both sides, first use the Addition or Subtraction Property of Equality to collect the variable terms on one side of the equation. Then, use the properties of equality to isolate the variable.

Solve 5x4=2x+115x - 4 = 2x + 11. First, subtract 2x2x from both sides to get 3x4=113x - 4 = 11.|Continuing from 3x4=113x - 4 = 11, add 4 to both sides: 3x=153x = 15. Now, divide by 3 to get x=5x = 5.|For 8y+5=10y18y + 5 = 10y - 1, subtract 8y8y from both sides: 5=2y15 = 2y - 1. Then add 1: 6=2y6 = 2y, so y=3y = 3.

When variables appear on both sides of an equation, it is like a mathematical tug-of-war. Your first move is to gather all the variable terms onto one team by adding or subtracting them from both sides. Once all variables are grouped together, you can combine them and use the properties of equality to find out who wins!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Lessons 1-10, Investigation 1

  1. Lesson 1

    Lesson 1: Using Properties of Real Numbers

  2. Lesson 2

    Lesson 2: Evaluating Expressions and Combining Like Terms

  3. Lesson 3

    Lesson 3: Using Rules of Exponents

  4. Lesson 4

    LAB 1: Graphing Calculator: Graphing a Function and Building a Table

  5. Lesson 5

    Lesson 4: Identifying Functions and Using Function Notation

  6. Lesson 6

    LAB 2: Graphing Calculator: Storing and Recalling Data in a Matrix

  7. Lesson 7

    Lesson 5: Using Matrices to Organize Data and to Solve Problems

  8. Lesson 8

    Lesson 6: Finding Percent of Change

  9. Lesson 9Current

    Lesson 7: Solving Linear Equations (Exploration: Solving Equations Using Algebra Tiles)

  10. Lesson 10

    Lesson 8: Finding Direct Variation

  11. Lesson 11

    Lesson 9: Multiplying Matrices

  12. Lesson 12

    Lesson 10: Solving and Graphing Inequalities

  13. Lesson 13

    Investigation 1: Logic and Truth Tables