Learn on PengiSaxon Algebra 1Chapter 8: Advanced Factoring and Functions

Lesson 79: Factoring Trinomials by Using the GCF

In this Grade 9 Saxon Algebra 1 lesson, students learn how to factor trinomials completely by first identifying and factoring out the greatest common factor (GCF), including cases with negative leading coefficients, two variables, and terms that must be rearranged into standard form. The lesson covers multi-step factoring strategies applied to polynomials such as expressions with higher-degree terms and real-world contexts like projectile motion.

Section 1

πŸ“˜ Factoring Trinomials by Using the GCF

New Concept

The terms of a polynomial that is factored completely will have no common factors other than 1.

What’s next

Next, you will apply this principle to factor various trinomials, starting by identifying and extracting the greatest common factor (GCF).

Section 2

Factoring Out The GCF

Property

To factor a polynomial completely, first identify and factor out the Greatest Common Factor (GCF) from all terms. The GCF is the largest monomial that divides into each term of the polynomial.

Explanation

Think of the GCF as the biggest shared ingredient in every term. Before you start solving the main trinomial puzzle, pull that GCF out to the front! This step simplifies the remaining expression, making it much smaller and easier to work with. It's like tidying up your desk before starting homeworkβ€”it just makes everything clearer and simpler.

Examples

x5+6x4+8x3=x3(x2+6x+8)=x3(x+2)(x+4)x^5 + 6x^4 + 8x^3 = x^3(x^2 + 6x + 8) = x^3(x + 2)(x + 4)
5x3βˆ’10x2βˆ’120x=5x(x2βˆ’2xβˆ’24)=5x(x+4)(xβˆ’6)5x^3 - 10x^2 - 120x = 5x(x^2 - 2x - 24) = 5x(x + 4)(x - 6)

Section 3

Example Card: Factoring with a GCF

Always look for a common factor first; it simplifies the entire puzzle. This example shows how to use the greatest common factor (GCF) to make factoring easier.

Example Problem

Factor the expression 3x3+9x2βˆ’30x3x^3 + 9x^2 - 30x completely.

Step-by-Step

  1. First, find the greatest common factor (GCF) of all the terms in the polynomial. The GCF of 3x33x^3, 9x29x^2, and βˆ’30x-30x is 3x3x.
  2. Factor out the GCF from the expression:
3x3+9x2βˆ’30x=3x(x2+3xβˆ’10) 3x^3 + 9x^2 - 30x = 3x(x^2 + 3x - 10)
  1. Now, focus on the trinomial inside the parentheses, x2+3xβˆ’10x^2 + 3x - 10. Find two numbers that have a product of βˆ’10-10 and a sum of 33.
5imes(βˆ’2)=βˆ’10extand5+(βˆ’2)=3 5 imes (-2) = -10 ext{ and } 5 + (-2) = 3
  1. Use these two numbers, 55 and βˆ’2-2, to write the trinomial as a product of two binomials.
3x(x2+3xβˆ’10)=3x(x+5)(xβˆ’2) 3x(x^2 + 3x - 10) = 3x(x + 5)(x - 2)

Section 4

Negative Leading Coefficient

Property

When the leading coefficient of a trinomial is negative, it is standard practice to factor out a βˆ’1-1 along with any other common factors.

Explanation

Nobody likes starting a problem with a negative attitude! If your polynomial's first term is grumpy and negative, factor out a βˆ’1-1 to flip all the signs inside the parentheses. This makes the new leading term positive and cheerful, which makes finding your factor pairs so much simpler. It's a quick trick to turn a frown upside down!

Examples

βˆ’x2+2x+48=βˆ’1(x2βˆ’2xβˆ’48)=βˆ’(x+6)(xβˆ’8)-x^2 + 2x + 48 = -1(x^2 - 2x - 48) = -(x + 6)(x - 8)
βˆ’2x3βˆ’10x2+48x=βˆ’2x(x2+5xβˆ’24)=βˆ’2x(x+8)(xβˆ’3)-2x^3 - 10x^2 + 48x = -2x(x^2 + 5x - 24) = -2x(x + 8)(x - 3)

Section 5

Example Card: Factoring with a Negative Leading Coefficient

When the leading term is negative, it's a sign to pull out the negative along with the GCF. Let's see how this works.

Example Problem

Factor the expression βˆ’2x3βˆ’10x2+48x-2x^3 - 10x^2 + 48x completely.

Step-by-Step

  1. Notice the leading coefficient is negative (βˆ’2-2). The GCF of the terms is 2x2x. To make the new leading term positive, we factor out βˆ’2x-2x.
  2. Factor out the negative GCF from the expression. Remember that dividing by a negative changes the signs of the remaining terms.
βˆ’2x3βˆ’10x2+48x=βˆ’2x(x2+5xβˆ’24) -2x^3 - 10x^2 + 48x = -2x(x^2 + 5x - 24)
  1. Now, factor the trinomial x2+5xβˆ’24x^2 + 5x - 24. We need two numbers that have a product of βˆ’24-24 and a sum of 55.
8imes(βˆ’3)=βˆ’24extand8+(βˆ’3)=5 8 imes (-3) = -24 ext{ and } 8 + (-3) = 5
  1. Use these numbers, 88 and βˆ’3-3, to write the final factored form, keeping the GCF out front.
βˆ’2x(x2+5xβˆ’24)=βˆ’2x(x+8)(xβˆ’3) -2x(x^2 + 5x - 24) = -2x(x + 8)(x - 3)

Section 6

Factoring With Multiple Variables

Property

For polynomials with multiple variables, the GCF may include variables as well as numbers. Factor out the entire GCF first to simplify the expression.

Explanation

Don't be scared when you see more letters in the mix! The GCF can include variables like aa, bb, or kk if they appear in every single term. Just find all the common ingredients, both numbers and variables, and pull them out together. The trinomial that's left over will behave just like the simpler ones you know.

Examples

ax4+10ax3+21ax2=ax2(x2+10x+21)=ax2(x+3)(x+7)ax^4 + 10ax^3 + 21ax^2 = ax^2(x^2 + 10x + 21) = ax^2(x + 3)(x + 7)
7ky3+14ky2βˆ’105ky=7ky(y2+2yβˆ’15)=7ky(y+5)(yβˆ’3)7ky^3 + 14ky^2 - 105ky = 7ky(y^2 + 2y - 15) = 7ky(y + 5)(y - 3)

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Advanced Factoring and Functions

  1. Lesson 1

    Lesson 71: Making and Analyzing Scatter Plots

  2. Lesson 2

    Lesson 72: Factoring Trinomials: xΒ² + bx + c

  3. Lesson 3

    Lesson 73: Solving Compound Inequalities

  4. Lesson 4

    Lesson 74: Solving Absolute-Value Equations

  5. Lesson 5

    Lesson 75: Factoring Trinomials: axΒ² + bx + c

  6. Lesson 6

    Lesson 76: Multiplying Radical Expressions

  7. Lesson 7

    Lesson 77: Solving Two-Step and Multi-Step Inequalities

  8. Lesson 8

    Lesson 78: Graphing Rational Functions

  9. Lesson 9Current

    Lesson 79: Factoring Trinomials by Using the GCF

  10. Lesson 10

    Lesson 80: Calculating Frequency Distributions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Factoring Trinomials by Using the GCF

New Concept

The terms of a polynomial that is factored completely will have no common factors other than 1.

What’s next

Next, you will apply this principle to factor various trinomials, starting by identifying and extracting the greatest common factor (GCF).

Section 2

Factoring Out The GCF

Property

To factor a polynomial completely, first identify and factor out the Greatest Common Factor (GCF) from all terms. The GCF is the largest monomial that divides into each term of the polynomial.

Explanation

Think of the GCF as the biggest shared ingredient in every term. Before you start solving the main trinomial puzzle, pull that GCF out to the front! This step simplifies the remaining expression, making it much smaller and easier to work with. It's like tidying up your desk before starting homeworkβ€”it just makes everything clearer and simpler.

Examples

x5+6x4+8x3=x3(x2+6x+8)=x3(x+2)(x+4)x^5 + 6x^4 + 8x^3 = x^3(x^2 + 6x + 8) = x^3(x + 2)(x + 4)
5x3βˆ’10x2βˆ’120x=5x(x2βˆ’2xβˆ’24)=5x(x+4)(xβˆ’6)5x^3 - 10x^2 - 120x = 5x(x^2 - 2x - 24) = 5x(x + 4)(x - 6)

Section 3

Example Card: Factoring with a GCF

Always look for a common factor first; it simplifies the entire puzzle. This example shows how to use the greatest common factor (GCF) to make factoring easier.

Example Problem

Factor the expression 3x3+9x2βˆ’30x3x^3 + 9x^2 - 30x completely.

Step-by-Step

  1. First, find the greatest common factor (GCF) of all the terms in the polynomial. The GCF of 3x33x^3, 9x29x^2, and βˆ’30x-30x is 3x3x.
  2. Factor out the GCF from the expression:
3x3+9x2βˆ’30x=3x(x2+3xβˆ’10) 3x^3 + 9x^2 - 30x = 3x(x^2 + 3x - 10)
  1. Now, focus on the trinomial inside the parentheses, x2+3xβˆ’10x^2 + 3x - 10. Find two numbers that have a product of βˆ’10-10 and a sum of 33.
5imes(βˆ’2)=βˆ’10extand5+(βˆ’2)=3 5 imes (-2) = -10 ext{ and } 5 + (-2) = 3
  1. Use these two numbers, 55 and βˆ’2-2, to write the trinomial as a product of two binomials.
3x(x2+3xβˆ’10)=3x(x+5)(xβˆ’2) 3x(x^2 + 3x - 10) = 3x(x + 5)(x - 2)

Section 4

Negative Leading Coefficient

Property

When the leading coefficient of a trinomial is negative, it is standard practice to factor out a βˆ’1-1 along with any other common factors.

Explanation

Nobody likes starting a problem with a negative attitude! If your polynomial's first term is grumpy and negative, factor out a βˆ’1-1 to flip all the signs inside the parentheses. This makes the new leading term positive and cheerful, which makes finding your factor pairs so much simpler. It's a quick trick to turn a frown upside down!

Examples

βˆ’x2+2x+48=βˆ’1(x2βˆ’2xβˆ’48)=βˆ’(x+6)(xβˆ’8)-x^2 + 2x + 48 = -1(x^2 - 2x - 48) = -(x + 6)(x - 8)
βˆ’2x3βˆ’10x2+48x=βˆ’2x(x2+5xβˆ’24)=βˆ’2x(x+8)(xβˆ’3)-2x^3 - 10x^2 + 48x = -2x(x^2 + 5x - 24) = -2x(x + 8)(x - 3)

Section 5

Example Card: Factoring with a Negative Leading Coefficient

When the leading term is negative, it's a sign to pull out the negative along with the GCF. Let's see how this works.

Example Problem

Factor the expression βˆ’2x3βˆ’10x2+48x-2x^3 - 10x^2 + 48x completely.

Step-by-Step

  1. Notice the leading coefficient is negative (βˆ’2-2). The GCF of the terms is 2x2x. To make the new leading term positive, we factor out βˆ’2x-2x.
  2. Factor out the negative GCF from the expression. Remember that dividing by a negative changes the signs of the remaining terms.
βˆ’2x3βˆ’10x2+48x=βˆ’2x(x2+5xβˆ’24) -2x^3 - 10x^2 + 48x = -2x(x^2 + 5x - 24)
  1. Now, factor the trinomial x2+5xβˆ’24x^2 + 5x - 24. We need two numbers that have a product of βˆ’24-24 and a sum of 55.
8imes(βˆ’3)=βˆ’24extand8+(βˆ’3)=5 8 imes (-3) = -24 ext{ and } 8 + (-3) = 5
  1. Use these numbers, 88 and βˆ’3-3, to write the final factored form, keeping the GCF out front.
βˆ’2x(x2+5xβˆ’24)=βˆ’2x(x+8)(xβˆ’3) -2x(x^2 + 5x - 24) = -2x(x + 8)(x - 3)

Section 6

Factoring With Multiple Variables

Property

For polynomials with multiple variables, the GCF may include variables as well as numbers. Factor out the entire GCF first to simplify the expression.

Explanation

Don't be scared when you see more letters in the mix! The GCF can include variables like aa, bb, or kk if they appear in every single term. Just find all the common ingredients, both numbers and variables, and pull them out together. The trinomial that's left over will behave just like the simpler ones you know.

Examples

ax4+10ax3+21ax2=ax2(x2+10x+21)=ax2(x+3)(x+7)ax^4 + 10ax^3 + 21ax^2 = ax^2(x^2 + 10x + 21) = ax^2(x + 3)(x + 7)
7ky3+14ky2βˆ’105ky=7ky(y2+2yβˆ’15)=7ky(y+5)(yβˆ’3)7ky^3 + 14ky^2 - 105ky = 7ky(y^2 + 2y - 15) = 7ky(y + 5)(y - 3)

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Advanced Factoring and Functions

  1. Lesson 1

    Lesson 71: Making and Analyzing Scatter Plots

  2. Lesson 2

    Lesson 72: Factoring Trinomials: xΒ² + bx + c

  3. Lesson 3

    Lesson 73: Solving Compound Inequalities

  4. Lesson 4

    Lesson 74: Solving Absolute-Value Equations

  5. Lesson 5

    Lesson 75: Factoring Trinomials: axΒ² + bx + c

  6. Lesson 6

    Lesson 76: Multiplying Radical Expressions

  7. Lesson 7

    Lesson 77: Solving Two-Step and Multi-Step Inequalities

  8. Lesson 8

    Lesson 78: Graphing Rational Functions

  9. Lesson 9Current

    Lesson 79: Factoring Trinomials by Using the GCF

  10. Lesson 10

    Lesson 80: Calculating Frequency Distributions