Learn on PengiSaxon Math, Course 1Chapter 2: Problem Solving with Number and Operations

Lesson 13: Problems About Comparing

In Saxon Math Course 1 Lesson 13, Grade 6 students learn to solve comparison problems and elapsed-time problems using a subtraction pattern. Students apply the equations greater minus lesser equals difference and later minus earlier equals difference to find how much more or less one quantity is than another, or how much time has passed between two events. The lesson uses a four-step problem-solving process with real-world examples such as comparing school populations and calculating years between historical dates.

Section 1

πŸ“˜ Problems About ComparingElapsed-Time Problems

New Concept

Comparison and elapsed-time problems use a subtraction pattern to find the difference between two values, whether they are quantities or points in time.

Problems About Comparing
Comparison problems have a subtraction pattern. We write the numbers in the equation in this order:

Greaterβˆ’lesser=difference \text{Greater} - \text{lesser} = \text{difference}

Or, using letters:

gβˆ’l=d g - l = d

Elapsed-Time Problems
Elapsed time is the length of time between two events. Elapsed-time problems also have a subtraction pattern:

Laterβˆ’earlier=difference \text{Later} - \text{earlier} = \text{difference}

Or, using letters:

lβˆ’e=d l - e = d

What’s next

This card introduces the core subtraction pattern. Next, you'll apply this pattern by solving worked examples involving populations, historical dates, and personal ages.

Section 2

Comparing Numbers with Subtraction

Property

To compare two groups and find the difference, use subtraction:

Greaterβˆ’lesser=difference \text{Greater} - \text{lesser} = \text{difference}
gβˆ’l=d g - l = d

Explanation

Ever wondered who has more stuff? This is how you find out! Comparison problems use subtraction to find the 'how many more' or 'how many fewer' between two groups. Just take the bigger number, subtract the smaller one, and boomβ€”you have the difference! It's like a math showdown to see who wins.

Full Example

Problem: The Red Team scored 415 points and the Blue Team scored 378 points. How many more points did the Red Team score?
Step 1: This is a comparison problem, so we use the subtraction pattern.
Step 2: We write the equation: Greater βˆ’- lesser == difference, which becomes 415βˆ’378=d415 - 378 = d.
Step 3: We solve by subtracting: 415βˆ’378=37415 - 378 = 37.
Step 4: The Red Team scored 37 more points than the Blue Team.

Section 3

Time Travel with Subtraction

Property

To find the amount of time that has passed (elapsed time), use this subtraction pattern:

Laterβˆ’earlier=difference \text{Later} - \text{earlier} = \text{difference}
lβˆ’e=d l - e = d

Explanation

Want to know how long a movie is or how many years passed between historical events? That's elapsed time! Think of it as a time machine powered by subtraction. You take the later date (when an event ended) and subtract the earlier date (when it started) to find out exactly how much time passed.

Full Example

Problem: The telephone was invented in 1876. The first smartphone was released in 1994. How many years passed between these two inventions?
Step 1: This is an elapsed-time problem with a subtraction pattern: lβˆ’e=dl - e = d.
Step 2: The later year is 1994 and the earlier year is 1876. The equation is 1994βˆ’1876=d1994 - 1876 = d.
Step 3: We subtract to find the difference: 1994βˆ’1876=1181994 - 1876 = 118.
Step 4: There were 118 years between the invention of the telephone and the first smartphone.

Section 4

Thinking Skill: Verify

Contextual Explanation

Just subtracting years to find someone's age can trick you! This is because the person might not have had their birthday yet in the current year. 'Verifying' means you double-check the details, like the month and day, to make sure your answer is actually correct and not just a quick guess.

Full Example

Problem: It's October 2025. Your friend was born in December 2013. Is your friend 12 years old?
Step 1: Calculate the difference in years: 2025βˆ’2013=122025 - 2013 = 12.
Step 2: Verify the months. The current month is October (Month 10). The birth month is December (Month 12).
Step 3: Analyze the result. Since your friend's birthday in December hasn't happened yet, they haven't completed their 12th year. They are still 11 years old. Verification saved you from being wrong!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Problem Solving with Number and Operations

  1. Lesson 1

    Lesson 11: Problems About Combining & Separating

  2. Lesson 2

    Lesson 12: Place Value Through Trillions

  3. Lesson 3Current

    Lesson 13: Problems About Comparing

  4. Lesson 4

    Lesson 14: The Number Line: Negative Numbers

  5. Lesson 5

    Lesson 15: Problems About Equal Groups

  6. Lesson 6

    Lesson 16: Rounding Whole Numbers

  7. Lesson 7

    Lesson 17: The Number Line: Fractions and Mixed Numbers

  8. Lesson 8

    Lesson 18: Average

  9. Lesson 9

    Lesson 19: Factors

  10. Lesson 10

    Lesson 20: Greatest Common Factor (GCF)

  11. Lesson 11

    Investigation 2: Investigating Fractions with Manipulatives

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Problems About ComparingElapsed-Time Problems

New Concept

Comparison and elapsed-time problems use a subtraction pattern to find the difference between two values, whether they are quantities or points in time.

Problems About Comparing
Comparison problems have a subtraction pattern. We write the numbers in the equation in this order:

Greaterβˆ’lesser=difference \text{Greater} - \text{lesser} = \text{difference}

Or, using letters:

gβˆ’l=d g - l = d

Elapsed-Time Problems
Elapsed time is the length of time between two events. Elapsed-time problems also have a subtraction pattern:

Laterβˆ’earlier=difference \text{Later} - \text{earlier} = \text{difference}

Or, using letters:

lβˆ’e=d l - e = d

What’s next

This card introduces the core subtraction pattern. Next, you'll apply this pattern by solving worked examples involving populations, historical dates, and personal ages.

Section 2

Comparing Numbers with Subtraction

Property

To compare two groups and find the difference, use subtraction:

Greaterβˆ’lesser=difference \text{Greater} - \text{lesser} = \text{difference}
gβˆ’l=d g - l = d

Explanation

Ever wondered who has more stuff? This is how you find out! Comparison problems use subtraction to find the 'how many more' or 'how many fewer' between two groups. Just take the bigger number, subtract the smaller one, and boomβ€”you have the difference! It's like a math showdown to see who wins.

Full Example

Problem: The Red Team scored 415 points and the Blue Team scored 378 points. How many more points did the Red Team score?
Step 1: This is a comparison problem, so we use the subtraction pattern.
Step 2: We write the equation: Greater βˆ’- lesser == difference, which becomes 415βˆ’378=d415 - 378 = d.
Step 3: We solve by subtracting: 415βˆ’378=37415 - 378 = 37.
Step 4: The Red Team scored 37 more points than the Blue Team.

Section 3

Time Travel with Subtraction

Property

To find the amount of time that has passed (elapsed time), use this subtraction pattern:

Laterβˆ’earlier=difference \text{Later} - \text{earlier} = \text{difference}
lβˆ’e=d l - e = d

Explanation

Want to know how long a movie is or how many years passed between historical events? That's elapsed time! Think of it as a time machine powered by subtraction. You take the later date (when an event ended) and subtract the earlier date (when it started) to find out exactly how much time passed.

Full Example

Problem: The telephone was invented in 1876. The first smartphone was released in 1994. How many years passed between these two inventions?
Step 1: This is an elapsed-time problem with a subtraction pattern: lβˆ’e=dl - e = d.
Step 2: The later year is 1994 and the earlier year is 1876. The equation is 1994βˆ’1876=d1994 - 1876 = d.
Step 3: We subtract to find the difference: 1994βˆ’1876=1181994 - 1876 = 118.
Step 4: There were 118 years between the invention of the telephone and the first smartphone.

Section 4

Thinking Skill: Verify

Contextual Explanation

Just subtracting years to find someone's age can trick you! This is because the person might not have had their birthday yet in the current year. 'Verifying' means you double-check the details, like the month and day, to make sure your answer is actually correct and not just a quick guess.

Full Example

Problem: It's October 2025. Your friend was born in December 2013. Is your friend 12 years old?
Step 1: Calculate the difference in years: 2025βˆ’2013=122025 - 2013 = 12.
Step 2: Verify the months. The current month is October (Month 10). The birth month is December (Month 12).
Step 3: Analyze the result. Since your friend's birthday in December hasn't happened yet, they haven't completed their 12th year. They are still 11 years old. Verification saved you from being wrong!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Problem Solving with Number and Operations

  1. Lesson 1

    Lesson 11: Problems About Combining & Separating

  2. Lesson 2

    Lesson 12: Place Value Through Trillions

  3. Lesson 3Current

    Lesson 13: Problems About Comparing

  4. Lesson 4

    Lesson 14: The Number Line: Negative Numbers

  5. Lesson 5

    Lesson 15: Problems About Equal Groups

  6. Lesson 6

    Lesson 16: Rounding Whole Numbers

  7. Lesson 7

    Lesson 17: The Number Line: Fractions and Mixed Numbers

  8. Lesson 8

    Lesson 18: Average

  9. Lesson 9

    Lesson 19: Factors

  10. Lesson 10

    Lesson 20: Greatest Common Factor (GCF)

  11. Lesson 11

    Investigation 2: Investigating Fractions with Manipulatives