Learn on PengiSaxon Algebra 1Chapter 7: Rational Expressions and Radicals

Lesson 70: Solving Inequalities by Multiplying or Dividing

In this Grade 9 Saxon Algebra 1 lesson, students learn how to solve one-variable inequalities using the Multiplication and Division Properties of Inequality, including the critical rule that multiplying or dividing by a negative number reverses the inequality symbol. The lesson covers solving, graphing on a number line, and checking solutions for inequalities with positive and negative coefficients. It is part of Chapter 7 on Rational Expressions and Radicals and builds on students' prior work with graphing inequalities.

Section 1

πŸ“˜ Solving Inequalities by Multiplying or Dividing

New Concept

When dividing an inequality by a negative value, the order of the inequality changes. If a>ba > b and c<0c < 0, then ac<bc\frac{a}{c} < \frac{b}{c}.

What’s next

Next, you'll apply this rule to solve, graph, and check various inequalities, including those in real-world application problems.

Section 2

Multiplication Property of Inequality for c > 0

Property

For every real number aa and bb, and for c>0c > 0: If a>ba > b, then ac>bcac > bc. If a<ba < b, then ac<bcac < bc.

Explanation

Think of this as scaling up! If you have more cookies than your friend (a>ba > b) and you both get five times as many (c=5c=5), you still have more cookies. Multiplying by a positive number keeps the relationship the same, so the inequality sign doesn't change. It’s a fair game!

Examples

To solve 13x≀7\frac{1}{3}x \le 7, multiply by 3: (3)13x≀7(3)(3)\frac{1}{3}x \le 7(3), so x≀21x \le 21.
Since 8>58 > 5, then 8(2)>5(2)8(2) > 5(2) because 16>1016 > 10.

Section 3

Multiplication Property of Inequality for c < 0

Property

For every real number aa and bb, and for c<0c < 0: If a>ba > b, then ac<bcac < bc. If a<ba < b, then ac>bcac > bc.

Explanation

This is the big twist! Multiplying by a negative number flips everything across zero on the number line. A bigger positive number becomes a smaller (more negative) number. Because the order reverses, you MUST flip the inequality sign to keep the statement true. Don't forget this crucial step!

Examples

To solve βˆ’x4<2\frac{-x}{4} < 2, multiply by -4 and flip the sign: (βˆ’4)βˆ’x4>2(βˆ’4)(-4)\frac{-x}{4} > 2(-4), so x>βˆ’8x > -8.
Since 5>35 > 3, then 5(βˆ’2)<3(βˆ’2)5(-2) < 3(-2) because βˆ’10<βˆ’6-10 < -6.

Section 4

Example Card: Multiplying by a Negative Number

A single negative sign can flip this entire problem on its head. Let's see how the Multiplication Property of Inequality for c<0c < 0 works.

Example Problem

Solve, graph, and check the solution for the inequality βˆ’x3<4\frac{-x}{3} < 4.

Step-by-Step

  1. Start with the given inequality.
βˆ’x3<4 \frac{-x}{3} < 4
  1. To isolate xx, we need to multiply both sides by βˆ’3-3. Because we are multiplying by a negative number, we must reverse the inequality symbol.
(βˆ’3)βˆ’x3>4(βˆ’3)MultiplicationΒ PropertyΒ ofΒ InequalityΒ forΒ c<0 (-3)\frac{-x}{3} > 4(-3) \quad \text{Multiplication Property of Inequality for } c < 0
  1. Simplify the expression to find the solution.
x>βˆ’12Simplify. x > -12 \quad \text{Simplify.}
  1. Graph the solution on a number line. This requires an open circle at βˆ’12-12 and an arrow pointing to the right, indicating all numbers greater than βˆ’12-12.

Section 5

Division Property of Inequality for c > 0

Property

For every real number aa and bb, and for c>0c > 0: If a>ba > b, then ac>bc\frac{a}{c} > \frac{b}{c}. If a<ba < b, then ac<bc\frac{a}{c} < \frac{b}{c}.

Explanation

Dividing by a positive number is like sharing equally. If you have a bigger pile of candy and you split it among your friends, your share is still bigger than your sibling's smaller pile split the same way. The inequality stays the same because the relationship doesn't change. No tricks here!

Examples

To solve 5r<305r < 30, divide by 5: 5r5<305\frac{5r}{5} < \frac{30}{5}, which simplifies to r<6r < 6.
Since 20>1220 > 12, then 204>124\frac{20}{4} > \frac{12}{4} because 5>35 > 3.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10Current

    Lesson 70: Solving Inequalities by Multiplying or Dividing

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Solving Inequalities by Multiplying or Dividing

New Concept

When dividing an inequality by a negative value, the order of the inequality changes. If a>ba > b and c<0c < 0, then ac<bc\frac{a}{c} < \frac{b}{c}.

What’s next

Next, you'll apply this rule to solve, graph, and check various inequalities, including those in real-world application problems.

Section 2

Multiplication Property of Inequality for c > 0

Property

For every real number aa and bb, and for c>0c > 0: If a>ba > b, then ac>bcac > bc. If a<ba < b, then ac<bcac < bc.

Explanation

Think of this as scaling up! If you have more cookies than your friend (a>ba > b) and you both get five times as many (c=5c=5), you still have more cookies. Multiplying by a positive number keeps the relationship the same, so the inequality sign doesn't change. It’s a fair game!

Examples

To solve 13x≀7\frac{1}{3}x \le 7, multiply by 3: (3)13x≀7(3)(3)\frac{1}{3}x \le 7(3), so x≀21x \le 21.
Since 8>58 > 5, then 8(2)>5(2)8(2) > 5(2) because 16>1016 > 10.

Section 3

Multiplication Property of Inequality for c < 0

Property

For every real number aa and bb, and for c<0c < 0: If a>ba > b, then ac<bcac < bc. If a<ba < b, then ac>bcac > bc.

Explanation

This is the big twist! Multiplying by a negative number flips everything across zero on the number line. A bigger positive number becomes a smaller (more negative) number. Because the order reverses, you MUST flip the inequality sign to keep the statement true. Don't forget this crucial step!

Examples

To solve βˆ’x4<2\frac{-x}{4} < 2, multiply by -4 and flip the sign: (βˆ’4)βˆ’x4>2(βˆ’4)(-4)\frac{-x}{4} > 2(-4), so x>βˆ’8x > -8.
Since 5>35 > 3, then 5(βˆ’2)<3(βˆ’2)5(-2) < 3(-2) because βˆ’10<βˆ’6-10 < -6.

Section 4

Example Card: Multiplying by a Negative Number

A single negative sign can flip this entire problem on its head. Let's see how the Multiplication Property of Inequality for c<0c < 0 works.

Example Problem

Solve, graph, and check the solution for the inequality βˆ’x3<4\frac{-x}{3} < 4.

Step-by-Step

  1. Start with the given inequality.
βˆ’x3<4 \frac{-x}{3} < 4
  1. To isolate xx, we need to multiply both sides by βˆ’3-3. Because we are multiplying by a negative number, we must reverse the inequality symbol.
(βˆ’3)βˆ’x3>4(βˆ’3)MultiplicationΒ PropertyΒ ofΒ InequalityΒ forΒ c<0 (-3)\frac{-x}{3} > 4(-3) \quad \text{Multiplication Property of Inequality for } c < 0
  1. Simplify the expression to find the solution.
x>βˆ’12Simplify. x > -12 \quad \text{Simplify.}
  1. Graph the solution on a number line. This requires an open circle at βˆ’12-12 and an arrow pointing to the right, indicating all numbers greater than βˆ’12-12.

Section 5

Division Property of Inequality for c > 0

Property

For every real number aa and bb, and for c>0c > 0: If a>ba > b, then ac>bc\frac{a}{c} > \frac{b}{c}. If a<ba < b, then ac<bc\frac{a}{c} < \frac{b}{c}.

Explanation

Dividing by a positive number is like sharing equally. If you have a bigger pile of candy and you split it among your friends, your share is still bigger than your sibling's smaller pile split the same way. The inequality stays the same because the relationship doesn't change. No tricks here!

Examples

To solve 5r<305r < 30, divide by 5: 5r5<305\frac{5r}{5} < \frac{30}{5}, which simplifies to r<6r < 6.
Since 20>1220 > 12, then 204>124\frac{20}{4} > \frac{12}{4} because 5>35 > 3.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10Current

    Lesson 70: Solving Inequalities by Multiplying or Dividing