Learn on PengiSaxon Algebra 1Chapter 7: Rational Expressions and Radicals

Lesson 66: Solving Inequalities by Adding or Subtracting

In this Grade 9 Saxon Algebra 1 lesson from Chapter 7, students learn how to solve one-variable inequalities using the Addition Property of Inequality and the Subtraction Property of Inequality. The lesson covers isolating the variable by adding or subtracting the same number from both sides, graphing solutions on a number line using open and closed circles, and verifying answers by checking the endpoint and the direction of the inequality symbol. Real-world applications, such as calculating maximum packing weight, reinforce how these algebraic skills apply in practical contexts.

Section 1

📘 Solving Inequalities by Adding or Subtracting

New Concept

When the same number is added to both sides of an inequality, the statement remains true. If a>ba > b, then a+c>b+ca + c > b + c.

What’s next

Next, you’ll apply this rule to solve for a variable in an inequality and graph the infinite solutions on a number line.

Section 2

Addition Property of Inequality

Property

For any real numbers aa, bb, and cc:

  • If a<ba < b, then a+c<b+ca + c < b + c.
  • If a>ba > b, then a+c>b+ca + c > b + c.
  • If aba \leq b, then a+cb+ca + c \leq b + c.
  • If aba \geq b, then a+cb+ca + c \geq b + c.

Explanation

Think of an inequality as a wobbly seesaw. As long as you add the same weight (or number) to both sides, it stays tilted in the same direction! This property is your secret weapon for solving inequalities. It lets you isolate the variable by adding the same value to both sides without messing up the inequality’s truth.

Examples

  • To solve x12<8x - 12 < -8, we add 12 to both sides: x12+12<8+12x - 12 + 12 < -8 + 12, which simplifies to x<4x < 4.
  • To solve y52y - 5 \geq 2, we use the same magic: y5+52+5y - 5 + 5 \geq 2 + 5, which simplifies to y7y \geq 7.
  • For a fractional challenge like z12>5z - \frac{1}{2} > 5, just add 12\frac{1}{2} to each side: z12+12>5+12z - \frac{1}{2} + \frac{1}{2} > 5 + \frac{1}{2}, resulting in z>512z > 5\frac{1}{2}.

Section 3

Example Card: Using the Addition Property of Inequality

Just like with equations, our first step is to isolate the variable. This first key idea from our lesson, the Addition Property of Inequality, is the perfect tool for the job.

Example Problem

Solve the inequality x12<5x - 12 < -5 and graph the solution on a number line.

Step-by-Step

  1. Start with the given inequality.
x12<5x - 12 < -5
  1. Use the Addition Property of Inequality by adding 1212 to both sides.
x12+12<5+12x - 12 + 12 < -5 + 12
  1. Simplify the expression to find the solution.
x<7x < 7
  1. To graph this, we place an open circle at 77 because 77 is not included in the solution. We then shade the number line to the left of 77.

Section 4

Subtraction Property of Inequality

Property

For any real numbers aa, bb, and cc:

  • If a<ba < b, then ac<bca - c < b - c.
  • If a>ba > b, then ac>bca - c > b - c.
  • If aba \leq b, then acbca - c \leq b - c.
  • If aba \geq b, then acbca - c \geq b - c.

Explanation

Just like adding, subtracting the same amount from both sides of our trusty inequality seesaw keeps it balanced in the same way. This lets you clear out extra numbers that are added to your variable, getting you one step closer to solving the puzzle. It’s the perfect partner to the addition property, helping you isolate that sneaky variable!

Examples

  • To solve x+7>10x + 7 > 10, you subtract 7 from both sides: x+77>107x + 7 - 7 > 10 - 7, which gives you the solution x>3x > 3.
  • For an inequality with decimals like k+3.35.5k + 3.3 \leq 5.5, you do the same: k+3.33.35.53.3k + 3.3 - 3.3 \leq 5.5 - 3.3, which simplifies to k2.2k \leq 2.2.
  • If your allowance plus 5 dollars is at least 15 dollars (a+515a+5 \geq 15), solve by subtracting 5: a10a \geq 10 dollars.

Section 5

Example Card: Using the Subtraction Property of Inequality

Now, let's tackle an inequality where the variable has something added to it. Here we apply the second key idea from our lesson, the Subtraction Property of Inequality.

Example Problem

Solve the inequality y+5>8y + 5 > 8. Then graph and check the solution.

Step-by-Step

  1. Begin with the inequality.
y+5>8y + 5 > 8
  1. Apply the Subtraction Property of Inequality. Subtract 55 from both sides.
y+55>85y + 5 - 5 > 8 - 5
  1. Simplify to find the solution.
y>3y > 3
  1. The solution is all numbers greater than 33. We graph this with an open circle at 33 and an arrow pointing to the right.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6Current

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10

    Lesson 70: Solving Inequalities by Multiplying or Dividing

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Solving Inequalities by Adding or Subtracting

New Concept

When the same number is added to both sides of an inequality, the statement remains true. If a>ba > b, then a+c>b+ca + c > b + c.

What’s next

Next, you’ll apply this rule to solve for a variable in an inequality and graph the infinite solutions on a number line.

Section 2

Addition Property of Inequality

Property

For any real numbers aa, bb, and cc:

  • If a<ba < b, then a+c<b+ca + c < b + c.
  • If a>ba > b, then a+c>b+ca + c > b + c.
  • If aba \leq b, then a+cb+ca + c \leq b + c.
  • If aba \geq b, then a+cb+ca + c \geq b + c.

Explanation

Think of an inequality as a wobbly seesaw. As long as you add the same weight (or number) to both sides, it stays tilted in the same direction! This property is your secret weapon for solving inequalities. It lets you isolate the variable by adding the same value to both sides without messing up the inequality’s truth.

Examples

  • To solve x12<8x - 12 < -8, we add 12 to both sides: x12+12<8+12x - 12 + 12 < -8 + 12, which simplifies to x<4x < 4.
  • To solve y52y - 5 \geq 2, we use the same magic: y5+52+5y - 5 + 5 \geq 2 + 5, which simplifies to y7y \geq 7.
  • For a fractional challenge like z12>5z - \frac{1}{2} > 5, just add 12\frac{1}{2} to each side: z12+12>5+12z - \frac{1}{2} + \frac{1}{2} > 5 + \frac{1}{2}, resulting in z>512z > 5\frac{1}{2}.

Section 3

Example Card: Using the Addition Property of Inequality

Just like with equations, our first step is to isolate the variable. This first key idea from our lesson, the Addition Property of Inequality, is the perfect tool for the job.

Example Problem

Solve the inequality x12<5x - 12 < -5 and graph the solution on a number line.

Step-by-Step

  1. Start with the given inequality.
x12<5x - 12 < -5
  1. Use the Addition Property of Inequality by adding 1212 to both sides.
x12+12<5+12x - 12 + 12 < -5 + 12
  1. Simplify the expression to find the solution.
x<7x < 7
  1. To graph this, we place an open circle at 77 because 77 is not included in the solution. We then shade the number line to the left of 77.

Section 4

Subtraction Property of Inequality

Property

For any real numbers aa, bb, and cc:

  • If a<ba < b, then ac<bca - c < b - c.
  • If a>ba > b, then ac>bca - c > b - c.
  • If aba \leq b, then acbca - c \leq b - c.
  • If aba \geq b, then acbca - c \geq b - c.

Explanation

Just like adding, subtracting the same amount from both sides of our trusty inequality seesaw keeps it balanced in the same way. This lets you clear out extra numbers that are added to your variable, getting you one step closer to solving the puzzle. It’s the perfect partner to the addition property, helping you isolate that sneaky variable!

Examples

  • To solve x+7>10x + 7 > 10, you subtract 7 from both sides: x+77>107x + 7 - 7 > 10 - 7, which gives you the solution x>3x > 3.
  • For an inequality with decimals like k+3.35.5k + 3.3 \leq 5.5, you do the same: k+3.33.35.53.3k + 3.3 - 3.3 \leq 5.5 - 3.3, which simplifies to k2.2k \leq 2.2.
  • If your allowance plus 5 dollars is at least 15 dollars (a+515a+5 \geq 15), solve by subtracting 5: a10a \geq 10 dollars.

Section 5

Example Card: Using the Subtraction Property of Inequality

Now, let's tackle an inequality where the variable has something added to it. Here we apply the second key idea from our lesson, the Subtraction Property of Inequality.

Example Problem

Solve the inequality y+5>8y + 5 > 8. Then graph and check the solution.

Step-by-Step

  1. Begin with the inequality.
y+5>8y + 5 > 8
  1. Apply the Subtraction Property of Inequality. Subtract 55 from both sides.
y+55>85y + 5 - 5 > 8 - 5
  1. Simplify to find the solution.
y>3y > 3
  1. The solution is all numbers greater than 33. We graph this with an open circle at 33 and an arrow pointing to the right.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6Current

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10

    Lesson 70: Solving Inequalities by Multiplying or Dividing