Learn on PengiSaxon Algebra 1Chapter 7: Rational Expressions and Radicals

Lesson 64: Identifying, Writing, and Graphing Inverse Variation

New Concept Inverse variation is a relationship between two variables whose product is a constant. The equation is $xy = k$ or $y = \frac{k}{x}$. What’s next Next, you’ll use this definition to identify inverse variations, find missing values in a relationship, and graph the resulting curves.

Section 1

📘 Identifying, Writing, and Graphing Inverse Variation

New Concept

Inverse variation is a relationship between two variables whose product is a constant. The equation is xy=kxy = k or y=kxy = \frac{k}{x}.

What’s next

Next, you’ll use this definition to identify inverse variations, find missing values in a relationship, and graph the resulting curves.

Section 2

Inverse variation

Property

An Inverse variation is a relationship between two variables whose product is a constant. The equation xy=kxy = k or y=kxy = \frac{k}{x}, where kk is a nonzero constant, defines an inverse variation between xx and yy.

Explanation

Think of it like a seesaw! As one variable goes up, the other must go down to keep their product, kk, perfectly balanced and constant. Unlike direct variation where they rise and fall together, in an inverse relationship, they move in opposite directions to ensure that the value of xyxy always stays the same magical number.

Examples

  • The relationship xy=15xy = 15 is an inverse variation because the product of xx and yy is a constant, 15.
  • The relationship y=3xy = 3x is a direct variation, not an inverse variation, because it's in the form y=kxy=kx.
  • If 3 people take 8 hours to paint a fence, how long will it take 4 people? Here, the number of people and time vary inversely.

Section 3

Example Card: Identifying an Inverse Variation

Isolating the variable yy is the key to determining if a relationship is an inverse variation. This example demonstrates one of the key ideas in this lesson, identifying an inverse variation.

Example Problem

Tell whether the relationship 3xy=213xy = 21 is an inverse variation. Explain why.

Step-by-Step

  1. Start with the given equation: 3xy=213xy = 21.
  2. To check if this is an inverse variation, we need to see if it can be written in the form y=kxy = \frac{k}{x}, where kk is a non-zero constant.
  3. First, isolate the product xyxy by dividing both sides by 33: xy=213xy = \frac{21}{3}.
  4. Simplify the right side: xy=7xy = 7.
  5. Now, solve for yy by dividing both sides by xx: y=7xy = \frac{7}{x}.
  6. This equation matches the form y=kxy = \frac{k}{x}, with the constant of variation k=7k=7. Therefore, the relationship is an inverse variation.

Section 4

Constant of variation

Property

The letter kk represents the constant of variation. In an inverse relationship, you can always find it using the formula k=xyk=xy.

Explanation

The constant of variation, kk, is the secret code of the relationship! It's the one number that never changes, representing the fixed product of xx and yy. If you can find kk by multiplying any known (x,y)(x, y) pair, you unlock the ability to write the master equation and solve for any other value in the relationship.

Examples

  • If yy varies inversely with xx, and y=5y=5 when x=4x=4, the constant of variation is k=(4)(5)=20k = (4)(5) = 20.
  • To write an inverse variation equation where y=2y=2 when x=9x=9, first find kk. k=(9)(2)=18k = (9)(2)=18. The equation is y=18xy = \frac{18}{x}.

Section 5

Product Rule for Inverse Variation

Property

If (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are solutions of an inverse variation, then their products are equal: x1y1=x2y2x_1y_1 = x_2y_2.

Explanation

This is your ultimate shortcut! Since x1y1x_1y_1 and x2y2x_2y_2 both equal the same constant, kk, they must equal each other. This lets you find a missing value in a new pair without first solving for kk. Just set the product of the first pair equal to the product of the second and solve for the unknown value.

Examples

  • If y=5y=5 when x=6x=6, find xx when y=10y=10. Using the rule: (6)(5)=x2(10)    30=10x2    x2=3(6)(5) = x_2(10) \implies 30 = 10x_2 \implies x_2 = 3.
  • A teen earns 14 dollars an hour and works 10 hours. How many hours must they work to earn the same amount if their pay is 20 dollars an hour? (14)(10)=(20)y2    140=20y2    y2=7(14)(10) = (20)y_2 \implies 140 = 20y_2 \implies y_2 = 7 hours.

Book overview

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Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4Current

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10

    Lesson 70: Solving Inequalities by Multiplying or Dividing

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Identifying, Writing, and Graphing Inverse Variation

New Concept

Inverse variation is a relationship between two variables whose product is a constant. The equation is xy=kxy = k or y=kxy = \frac{k}{x}.

What’s next

Next, you’ll use this definition to identify inverse variations, find missing values in a relationship, and graph the resulting curves.

Section 2

Inverse variation

Property

An Inverse variation is a relationship between two variables whose product is a constant. The equation xy=kxy = k or y=kxy = \frac{k}{x}, where kk is a nonzero constant, defines an inverse variation between xx and yy.

Explanation

Think of it like a seesaw! As one variable goes up, the other must go down to keep their product, kk, perfectly balanced and constant. Unlike direct variation where they rise and fall together, in an inverse relationship, they move in opposite directions to ensure that the value of xyxy always stays the same magical number.

Examples

  • The relationship xy=15xy = 15 is an inverse variation because the product of xx and yy is a constant, 15.
  • The relationship y=3xy = 3x is a direct variation, not an inverse variation, because it's in the form y=kxy=kx.
  • If 3 people take 8 hours to paint a fence, how long will it take 4 people? Here, the number of people and time vary inversely.

Section 3

Example Card: Identifying an Inverse Variation

Isolating the variable yy is the key to determining if a relationship is an inverse variation. This example demonstrates one of the key ideas in this lesson, identifying an inverse variation.

Example Problem

Tell whether the relationship 3xy=213xy = 21 is an inverse variation. Explain why.

Step-by-Step

  1. Start with the given equation: 3xy=213xy = 21.
  2. To check if this is an inverse variation, we need to see if it can be written in the form y=kxy = \frac{k}{x}, where kk is a non-zero constant.
  3. First, isolate the product xyxy by dividing both sides by 33: xy=213xy = \frac{21}{3}.
  4. Simplify the right side: xy=7xy = 7.
  5. Now, solve for yy by dividing both sides by xx: y=7xy = \frac{7}{x}.
  6. This equation matches the form y=kxy = \frac{k}{x}, with the constant of variation k=7k=7. Therefore, the relationship is an inverse variation.

Section 4

Constant of variation

Property

The letter kk represents the constant of variation. In an inverse relationship, you can always find it using the formula k=xyk=xy.

Explanation

The constant of variation, kk, is the secret code of the relationship! It's the one number that never changes, representing the fixed product of xx and yy. If you can find kk by multiplying any known (x,y)(x, y) pair, you unlock the ability to write the master equation and solve for any other value in the relationship.

Examples

  • If yy varies inversely with xx, and y=5y=5 when x=4x=4, the constant of variation is k=(4)(5)=20k = (4)(5) = 20.
  • To write an inverse variation equation where y=2y=2 when x=9x=9, first find kk. k=(9)(2)=18k = (9)(2)=18. The equation is y=18xy = \frac{18}{x}.

Section 5

Product Rule for Inverse Variation

Property

If (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are solutions of an inverse variation, then their products are equal: x1y1=x2y2x_1y_1 = x_2y_2.

Explanation

This is your ultimate shortcut! Since x1y1x_1y_1 and x2y2x_2y_2 both equal the same constant, kk, they must equal each other. This lets you find a missing value in a new pair without first solving for kk. Just set the product of the first pair equal to the product of the second and solve for the unknown value.

Examples

  • If y=5y=5 when x=6x=6, find xx when y=10y=10. Using the rule: (6)(5)=x2(10)    30=10x2    x2=3(6)(5) = x_2(10) \implies 30 = 10x_2 \implies x_2 = 3.
  • A teen earns 14 dollars an hour and works 10 hours. How many hours must they work to earn the same amount if their pay is 20 dollars an hour? (14)(10)=(20)y2    140=20y2    y2=7(14)(10) = (20)y_2 \implies 140 = 20y_2 \implies y_2 = 7 hours.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Rational Expressions and Radicals

  1. Lesson 1

    Lesson 61: Simplifying Radical Expressions

  2. Lesson 2

    Lesson 62: Displaying Data in Stem-and-Leaf Plots and Histograms

  3. Lesson 3

    Lesson 63: Solving Systems of Linear Equations by Elimination

  4. Lesson 4Current

    Lesson 64: Identifying, Writing, and Graphing Inverse Variation

  5. Lesson 5

    Lesson 65: Writing Equations of Parallel and Perpendicular Lines

  6. Lesson 6

    Lesson 66: Solving Inequalities by Adding or Subtracting

  7. Lesson 7

    Lesson 67: Solving and Classifying Special Systems of Linear Equations

  8. Lesson 8

    Lesson 68: Mutually Exclusive and Inclusive Events

  9. Lesson 9

    Lesson 69: Adding and Subtracting Radical Expressions

  10. Lesson 10

    Lesson 70: Solving Inequalities by Multiplying or Dividing