Learn on PengiSaxon Algebra 1Chapter 6: Polynomials and Factoring

Lesson 57: Finding the Least Common Multiple

In Saxon Algebra 1, Lesson 57, Grade 9 students learn how to find the least common multiple (LCM) of numbers, monomials, and polynomials by writing each expression as a product of its prime factors and selecting each factor the greatest number of times it appears in any single expression. The lesson extends LCM concepts from whole numbers to algebraic expressions involving variables with exponents, such as finding the LCM of monomials like 10a³c⁴ and 15a⁴c³. Students also practice factoring polynomials using the greatest common factor before determining the LCM of binomial expressions.

Section 1

📘 Finding the Least Common Multiple

New Concept

The least number that is evenly divisible by each of the numbers in a set of numbers is called the least common multiple or LCM.

What’s next

Next, you'll use prime factorization to find the LCM for sets of numbers and then for algebraic expressions.

Section 2

Least Common Multiple

Property

The least number that is evenly divisible by each of the numbers in a set of numbers. To find it, write each number as a product of prime factors. Then, use every prime factor the greatest number of times it appears in any single number's factorization.

Explanation

Think of it like building the ultimate playlist from your friends' favorite songs, which are the prime factors. Your LCM playlist must include the maximum number of times any one friend listed a particular song. This way, everyone's top hit is covered, and the playlist is as short as possible while still pleasing the whole group.

Examples

Find the LCM of 24 and 36. We have 24=23324 = 2^3 \cdot 3 and 36=223236 = 2^2 \cdot 3^2. The LCM needs the highest powers: 2332=722^3 \cdot 3^2 = 72.
Find the LCM of 11, 12, and 18. We have 11=1111=11, 12=22312 = 2^2 \cdot 3, and 18=23218 = 2 \cdot 3^2. The LCM is 223211=3962^2 \cdot 3^2 \cdot 11 = 396.

Section 3

Example Card: Finding the LCM of Two Numbers

Finding the smallest number two values share can be simple if you break them down first. Let's practice the first key idea from this lesson, identifying the LCM of a Set of Numbers.

Example Problem
Find the LCM of 30 and 45.

Step-by-Step

  1. First, write each number as a product of its prime factors.
30=235 30 = 2 \cdot 3 \cdot 5
45=335 45 = 3 \cdot 3 \cdot 5
  1. The number 2 is a factor of 30. It appears once, so it will appear once in the LCM.
2 2
  1. The number 3 is a factor of both numbers. The greatest number of times it appears is two times in 45, so it will appear in the LCM two times.
233 2 \cdot 3 \cdot 3
  1. The number 5 is a factor of both numbers, appearing one time in each. So, it will appear once in the LCM.
LCM=2335 \operatorname{LCM} = 2 \cdot 3 \cdot 3 \cdot 5
  1. Now, multiply the factors to find the LCM.
LCM=90 \operatorname{LCM} = 90

The LCM of 30 and 45 is 90.

Section 4

LCM of Algebraic Expressions

Property

To find the LCM of monomials, find the LCM of the coefficients. Then, for each variable, take the highest power that appears in any of the terms. The LCM is the product of the numerical LCM and the variables raised to their highest powers.

Explanation

This is just like our playlist example, but now we're adding different genres, which are the variables! Treat each variable like a unique artist. For your final LCM, you need the LCM of the numbers, or coefficients, and the "greatest hits" version of each artist, which means taking the highest power of each variable you can find.

Examples

Find the LCM of 10a3c510a^3c^5 and 15a2c415a^2c^4. The LCM of 10 and 15 is 30. The highest power of aa is a3a^3 and of cc is c5c^5. So, the LCM is 30a3c530a^3c^5.
Find the LCM of 6p2s36p^2s^3 and 8m3p8m^3p. The LCM of 6 and 8 is 24. The highest powers are p2p^2, s3s^3, and m3m^3. The LCM is 24m3p2s324m^3p^2s^3.

Section 5

Example Card: Finding the LCM of Polynomials

Factoring polynomials is the secret to finding their LCM. Let's try this with the second key idea from this lesson, identifying the LCM of polynomials.

Example Problem
Find the LCM of (8x2+24x)(8x^2+24x) and (10x+30)(10x+30).

Step-by-Step

  1. First, factor each binomial to find its prime components.
  2. The Greatest Common Factor (GCF) of the terms in (8x2+24x)(8x^2+24x) is 8x8x. Factor it out.
(8x2+24x)=8x(x+3)=222x(x+3) (8x^2+24x) = 8x(x+3) = 2 \cdot 2 \cdot 2 \cdot x(x+3)
  1. The GCF of the terms in (10x+30)(10x+30) is 1010. Factor it out.
(10x+30)=10(x+3)=25(x+3) (10x+30) = 10(x+3) = 2 \cdot 5(x+3)
  1. Now, identify all the unique factors. We have the numeric factors 2 and 5, the variable factor xx, and the binomial factor (x+3)(x+3).
  2. To build the LCM, take the greatest number of times each factor appears in any single expression. The factor 2 appears most (three times). The factor 5 appears once. The factor xx appears once. The factor (x+3)(x+3) appears once in each.
LCM=2225x(x+3) \operatorname{LCM} = 2 \cdot 2 \cdot 2 \cdot 5 \cdot x(x+3)
  1. Multiply these factors to get the final LCM.
LCM=40x(x+3) \operatorname{LCM} = 40x(x+3)

The LCM is 40x(x+3)40x(x+3).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Polynomials and Factoring

  1. Lesson 1

    Lesson 51: Simplifying Rational Expressions with Like Denominators

  2. Lesson 2

    Lesson 52: Determining the Equation of a Line Given Two Points

  3. Lesson 3

    Lesson 53: Adding and Subtracting Polynomials

  4. Lesson 4

    Lesson 54: Displaying Data in a Box-and-Whisker Plot

  5. Lesson 5

    Lesson 55: Solving Systems of Linear Equations by Graphing

  6. Lesson 6

    Lesson 56: Identifying, Writing, and Graphing Direct Variation

  7. Lesson 7Current

    Lesson 57: Finding the Least Common Multiple

  8. Lesson 8

    Lesson 58: Multiplying Polynomials

  9. Lesson 9

    Lesson 59: Solving Systems of Linear Equations by Substitution

  10. Lesson 10

    Lesson 60: Finding Special Products of Binomials

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Finding the Least Common Multiple

New Concept

The least number that is evenly divisible by each of the numbers in a set of numbers is called the least common multiple or LCM.

What’s next

Next, you'll use prime factorization to find the LCM for sets of numbers and then for algebraic expressions.

Section 2

Least Common Multiple

Property

The least number that is evenly divisible by each of the numbers in a set of numbers. To find it, write each number as a product of prime factors. Then, use every prime factor the greatest number of times it appears in any single number's factorization.

Explanation

Think of it like building the ultimate playlist from your friends' favorite songs, which are the prime factors. Your LCM playlist must include the maximum number of times any one friend listed a particular song. This way, everyone's top hit is covered, and the playlist is as short as possible while still pleasing the whole group.

Examples

Find the LCM of 24 and 36. We have 24=23324 = 2^3 \cdot 3 and 36=223236 = 2^2 \cdot 3^2. The LCM needs the highest powers: 2332=722^3 \cdot 3^2 = 72.
Find the LCM of 11, 12, and 18. We have 11=1111=11, 12=22312 = 2^2 \cdot 3, and 18=23218 = 2 \cdot 3^2. The LCM is 223211=3962^2 \cdot 3^2 \cdot 11 = 396.

Section 3

Example Card: Finding the LCM of Two Numbers

Finding the smallest number two values share can be simple if you break them down first. Let's practice the first key idea from this lesson, identifying the LCM of a Set of Numbers.

Example Problem
Find the LCM of 30 and 45.

Step-by-Step

  1. First, write each number as a product of its prime factors.
30=235 30 = 2 \cdot 3 \cdot 5
45=335 45 = 3 \cdot 3 \cdot 5
  1. The number 2 is a factor of 30. It appears once, so it will appear once in the LCM.
2 2
  1. The number 3 is a factor of both numbers. The greatest number of times it appears is two times in 45, so it will appear in the LCM two times.
233 2 \cdot 3 \cdot 3
  1. The number 5 is a factor of both numbers, appearing one time in each. So, it will appear once in the LCM.
LCM=2335 \operatorname{LCM} = 2 \cdot 3 \cdot 3 \cdot 5
  1. Now, multiply the factors to find the LCM.
LCM=90 \operatorname{LCM} = 90

The LCM of 30 and 45 is 90.

Section 4

LCM of Algebraic Expressions

Property

To find the LCM of monomials, find the LCM of the coefficients. Then, for each variable, take the highest power that appears in any of the terms. The LCM is the product of the numerical LCM and the variables raised to their highest powers.

Explanation

This is just like our playlist example, but now we're adding different genres, which are the variables! Treat each variable like a unique artist. For your final LCM, you need the LCM of the numbers, or coefficients, and the "greatest hits" version of each artist, which means taking the highest power of each variable you can find.

Examples

Find the LCM of 10a3c510a^3c^5 and 15a2c415a^2c^4. The LCM of 10 and 15 is 30. The highest power of aa is a3a^3 and of cc is c5c^5. So, the LCM is 30a3c530a^3c^5.
Find the LCM of 6p2s36p^2s^3 and 8m3p8m^3p. The LCM of 6 and 8 is 24. The highest powers are p2p^2, s3s^3, and m3m^3. The LCM is 24m3p2s324m^3p^2s^3.

Section 5

Example Card: Finding the LCM of Polynomials

Factoring polynomials is the secret to finding their LCM. Let's try this with the second key idea from this lesson, identifying the LCM of polynomials.

Example Problem
Find the LCM of (8x2+24x)(8x^2+24x) and (10x+30)(10x+30).

Step-by-Step

  1. First, factor each binomial to find its prime components.
  2. The Greatest Common Factor (GCF) of the terms in (8x2+24x)(8x^2+24x) is 8x8x. Factor it out.
(8x2+24x)=8x(x+3)=222x(x+3) (8x^2+24x) = 8x(x+3) = 2 \cdot 2 \cdot 2 \cdot x(x+3)
  1. The GCF of the terms in (10x+30)(10x+30) is 1010. Factor it out.
(10x+30)=10(x+3)=25(x+3) (10x+30) = 10(x+3) = 2 \cdot 5(x+3)
  1. Now, identify all the unique factors. We have the numeric factors 2 and 5, the variable factor xx, and the binomial factor (x+3)(x+3).
  2. To build the LCM, take the greatest number of times each factor appears in any single expression. The factor 2 appears most (three times). The factor 5 appears once. The factor xx appears once. The factor (x+3)(x+3) appears once in each.
LCM=2225x(x+3) \operatorname{LCM} = 2 \cdot 2 \cdot 2 \cdot 5 \cdot x(x+3)
  1. Multiply these factors to get the final LCM.
LCM=40x(x+3) \operatorname{LCM} = 40x(x+3)

The LCM is 40x(x+3)40x(x+3).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Polynomials and Factoring

  1. Lesson 1

    Lesson 51: Simplifying Rational Expressions with Like Denominators

  2. Lesson 2

    Lesson 52: Determining the Equation of a Line Given Two Points

  3. Lesson 3

    Lesson 53: Adding and Subtracting Polynomials

  4. Lesson 4

    Lesson 54: Displaying Data in a Box-and-Whisker Plot

  5. Lesson 5

    Lesson 55: Solving Systems of Linear Equations by Graphing

  6. Lesson 6

    Lesson 56: Identifying, Writing, and Graphing Direct Variation

  7. Lesson 7Current

    Lesson 57: Finding the Least Common Multiple

  8. Lesson 8

    Lesson 58: Multiplying Polynomials

  9. Lesson 9

    Lesson 59: Solving Systems of Linear Equations by Substitution

  10. Lesson 10

    Lesson 60: Finding Special Products of Binomials