Learn on PengiSaxon Algebra 1Chapter 6: Polynomials and Factoring

Lesson 51: Simplifying Rational Expressions with Like Denominators

In this Grade 9 Saxon Algebra 1 lesson from Chapter 6, students learn how to simplify rational expressions by identifying excluded values, factoring out the GCF, and canceling common factors in the numerator and denominator. The lesson also covers adding and subtracting rational expressions with like denominators, including expressions containing negative integer exponents. Real-world applications, such as calculating perimeter using rational expressions, reinforce the algebraic concepts introduced.

Section 1

πŸ“˜ Simplifying Rational Expressions with Like Denominators

New Concept

All values that would make the denominator equal zero are excluded.

What’s next

Next, you'll practice identifying these excluded values and use factoring to simplify rational expressions to their most basic forms.

Section 2

Identifying Excluded Values

Property

To find the excluded values of a rational expression, set the denominator equal to zero and solve for the variable. Any value that makes the denominator zero is excluded.

Examples

For the expression 73x\frac{7}{3x}, set 3x=03x=0. The excluded value is x≠0x \neq 0.
For the expression kβˆ’2k+5\frac{k-2}{k+5}, set k+5=0k+5=0. The excluded value is kβ‰ βˆ’5k \neq -5.
For the expression m2mβˆ’8\frac{m}{2m-8}, set 2mβˆ’8=02m-8=0. The excluded value is mβ‰ 4m \neq 4.

Explanation

Think of the denominator as the ground floor of a building; it can't be zero, or everything collapses! We find the numbers that would cause this math disaster and ban them from the expression. It’s like being a bouncer for your fraction, keeping out the troublemaking zeros.

Section 3

Simplifying Rational Expressions

Property

To simplify a rational expression, factor the numerator and denominator. Then, divide out any common factors that appear in both.

Examples

10x315x=5x(2x2)5x(3)=2x23\frac{10x^3}{15x} = \frac{5x(2x^2)}{5x(3)} = \frac{2x^2}{3}
3yβˆ’9yβˆ’3=3(yβˆ’3)(yβˆ’3)=3\frac{3y-9}{y-3} = \frac{3(y-3)}{(y-3)} = 3
5z2+10zz+2=5z(z+2)(z+2)=5z\frac{5z^2+10z}{z+2} = \frac{5z(z+2)}{(z+2)} = 5z

Explanation

This is like a mathematical magic trick where you make things disappear! By factoring, you reveal the secret identical parts of the top and bottom. Once you find a matching pair, you can cancel them out, leaving you with a much simpler, tidier expression. Presto, chango, simplified!

Section 4

Simplifying Expressions with Integer Exponents

Property

Rewrite terms with negative exponents as fractions, such as xβˆ’n=1xnx^{-n} = \frac{1}{x^n}. Once all terms have positive exponents and common denominators, combine them by adding or subtracting the numerators.

Examples

4cd2βˆ’7cd2=4cβˆ’7cd2=βˆ’3cd2\frac{4c}{d^2} - \frac{7c}{d^2} = \frac{4c-7c}{d^2} = -\frac{3c}{d^2}
xyβˆ’2+5xy2=xy2+5xy2=x+5xy2=6xy2xy^{-2} + \frac{5x}{y^2} = \frac{x}{y^2} + \frac{5x}{y^2} = \frac{x+5x}{y^2} = \frac{6x}{y^2}

Explanation

Negative exponents are just shy and hiding in the wrong spot! A negative exponent in the numerator wants to be in the denominator. Move it to its happy place, and then you can combine terms that share the same denominator. It's all about getting everyone to the right party.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Polynomials and Factoring

  1. Lesson 1Current

    Lesson 51: Simplifying Rational Expressions with Like Denominators

  2. Lesson 2

    Lesson 52: Determining the Equation of a Line Given Two Points

  3. Lesson 3

    Lesson 53: Adding and Subtracting Polynomials

  4. Lesson 4

    Lesson 54: Displaying Data in a Box-and-Whisker Plot

  5. Lesson 5

    Lesson 55: Solving Systems of Linear Equations by Graphing

  6. Lesson 6

    Lesson 56: Identifying, Writing, and Graphing Direct Variation

  7. Lesson 7

    Lesson 57: Finding the Least Common Multiple

  8. Lesson 8

    Lesson 58: Multiplying Polynomials

  9. Lesson 9

    Lesson 59: Solving Systems of Linear Equations by Substitution

  10. Lesson 10

    Lesson 60: Finding Special Products of Binomials

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Simplifying Rational Expressions with Like Denominators

New Concept

All values that would make the denominator equal zero are excluded.

What’s next

Next, you'll practice identifying these excluded values and use factoring to simplify rational expressions to their most basic forms.

Section 2

Identifying Excluded Values

Property

To find the excluded values of a rational expression, set the denominator equal to zero and solve for the variable. Any value that makes the denominator zero is excluded.

Examples

For the expression 73x\frac{7}{3x}, set 3x=03x=0. The excluded value is x≠0x \neq 0.
For the expression kβˆ’2k+5\frac{k-2}{k+5}, set k+5=0k+5=0. The excluded value is kβ‰ βˆ’5k \neq -5.
For the expression m2mβˆ’8\frac{m}{2m-8}, set 2mβˆ’8=02m-8=0. The excluded value is mβ‰ 4m \neq 4.

Explanation

Think of the denominator as the ground floor of a building; it can't be zero, or everything collapses! We find the numbers that would cause this math disaster and ban them from the expression. It’s like being a bouncer for your fraction, keeping out the troublemaking zeros.

Section 3

Simplifying Rational Expressions

Property

To simplify a rational expression, factor the numerator and denominator. Then, divide out any common factors that appear in both.

Examples

10x315x=5x(2x2)5x(3)=2x23\frac{10x^3}{15x} = \frac{5x(2x^2)}{5x(3)} = \frac{2x^2}{3}
3yβˆ’9yβˆ’3=3(yβˆ’3)(yβˆ’3)=3\frac{3y-9}{y-3} = \frac{3(y-3)}{(y-3)} = 3
5z2+10zz+2=5z(z+2)(z+2)=5z\frac{5z^2+10z}{z+2} = \frac{5z(z+2)}{(z+2)} = 5z

Explanation

This is like a mathematical magic trick where you make things disappear! By factoring, you reveal the secret identical parts of the top and bottom. Once you find a matching pair, you can cancel them out, leaving you with a much simpler, tidier expression. Presto, chango, simplified!

Section 4

Simplifying Expressions with Integer Exponents

Property

Rewrite terms with negative exponents as fractions, such as xβˆ’n=1xnx^{-n} = \frac{1}{x^n}. Once all terms have positive exponents and common denominators, combine them by adding or subtracting the numerators.

Examples

4cd2βˆ’7cd2=4cβˆ’7cd2=βˆ’3cd2\frac{4c}{d^2} - \frac{7c}{d^2} = \frac{4c-7c}{d^2} = -\frac{3c}{d^2}
xyβˆ’2+5xy2=xy2+5xy2=x+5xy2=6xy2xy^{-2} + \frac{5x}{y^2} = \frac{x}{y^2} + \frac{5x}{y^2} = \frac{x+5x}{y^2} = \frac{6x}{y^2}

Explanation

Negative exponents are just shy and hiding in the wrong spot! A negative exponent in the numerator wants to be in the denominator. Move it to its happy place, and then you can combine terms that share the same denominator. It's all about getting everyone to the right party.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Polynomials and Factoring

  1. Lesson 1Current

    Lesson 51: Simplifying Rational Expressions with Like Denominators

  2. Lesson 2

    Lesson 52: Determining the Equation of a Line Given Two Points

  3. Lesson 3

    Lesson 53: Adding and Subtracting Polynomials

  4. Lesson 4

    Lesson 54: Displaying Data in a Box-and-Whisker Plot

  5. Lesson 5

    Lesson 55: Solving Systems of Linear Equations by Graphing

  6. Lesson 6

    Lesson 56: Identifying, Writing, and Graphing Direct Variation

  7. Lesson 7

    Lesson 57: Finding the Least Common Multiple

  8. Lesson 8

    Lesson 58: Multiplying Polynomials

  9. Lesson 9

    Lesson 59: Solving Systems of Linear Equations by Substitution

  10. Lesson 10

    Lesson 60: Finding Special Products of Binomials