Learn on PengiReveal Math, Course 3Module 4: Linear Relationships and Slope

Lesson 4-3: Similar Triangles and Slope

In this Grade 8 lesson from Reveal Math, Course 3, students learn how to use slope triangles and the properties of similar figures to prove that the slope of a line is constant between any two points. By identifying similar right triangles along a line and showing that the ratios of their corresponding sides — rise over run — are proportional, students connect geometric reasoning to the concept of slope. The lesson builds key vocabulary including similar figures, corresponding parts, and slope triangles within Module 4's focus on linear relationships.

Section 1

Similar Figures

Property

Two figures are similar if, and only if:

  1. Their corresponding angles are equal, and
  2. Their corresponding sides are proportional.

Examples

  • A rectangle with sides 4 cm and 6 cm is similar to a rectangle with sides 8 cm and 12 cm. The scale factor is 2.
  • A photograph measuring 4 inches by 6 inches is enlarged to 8 inches by 12 inches. The enlarged photo is similar to the original.

Section 2

Proportions in Similar Triangles

Property

If two triangles are similar, then the ratios of their corresponding side lengths are equal.

For similar triangles ΔABC\Delta ABC and ΔDEF\Delta DEF, the proportion of corresponding sides is written as:

ABDE=BCEF=ACDF\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}

Section 3

Find Slope from a Graph

Property

To find the slope of a line from its graph:

  1. Locate two points on the graph whose coordinates are integers.
  2. Starting with the point on the left, sketch a right triangle, going from the first point to the second point.
  3. Count the rise and the run on the legs of the triangle.
  4. Take the ratio of rise to run to find the slope, m=riserunm = \frac{\operatorname{rise}}{\operatorname{run}}.

Examples

  • A line passes through (1,2)(1, 2) and (4,8)(4, 8). The rise is 82=68 - 2 = 6 and the run is 41=34 - 1 = 3. The slope is m=63=2m = \frac{6}{3} = 2.
  • A line passes through (0,6)(0, 6) and (2,2)(2, 2). The rise is 26=42 - 6 = -4 and the run is 20=22 - 0 = 2. The slope is m=42=2m = \frac{-4}{2} = -2.
  • A line on a graph connects points (3,1)(-3, 1) and (5,7)(5, 7). The rise is 71=67-1=6 and the run is 5(3)=85-(-3)=8. The slope is m=68=34m = \frac{6}{8} = \frac{3}{4}.

Explanation

To find slope from a graph, pick two easy-to-read points. Count the vertical distance (rise) and horizontal distance (run) to get from one point to the other. The slope is simply the rise divided by the run.

Book overview

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Module 4: Linear Relationships and Slope

  1. Lesson 1

    Lesson 4-1: Proportional Relationships and Slope

  2. Lesson 2

    Lesson 4-2: Slope of a Line

  3. Lesson 3Current

    Lesson 4-3: Similar Triangles and Slope

  4. Lesson 4

    Lesson 4-4: Direct Variation

  5. Lesson 5

    Lesson 4-5: Slope-Intercept Form

  6. Lesson 6

    Lesson 4-6: Graph Linear Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Similar Figures

Property

Two figures are similar if, and only if:

  1. Their corresponding angles are equal, and
  2. Their corresponding sides are proportional.

Examples

  • A rectangle with sides 4 cm and 6 cm is similar to a rectangle with sides 8 cm and 12 cm. The scale factor is 2.
  • A photograph measuring 4 inches by 6 inches is enlarged to 8 inches by 12 inches. The enlarged photo is similar to the original.

Section 2

Proportions in Similar Triangles

Property

If two triangles are similar, then the ratios of their corresponding side lengths are equal.

For similar triangles ΔABC\Delta ABC and ΔDEF\Delta DEF, the proportion of corresponding sides is written as:

ABDE=BCEF=ACDF\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}

Section 3

Find Slope from a Graph

Property

To find the slope of a line from its graph:

  1. Locate two points on the graph whose coordinates are integers.
  2. Starting with the point on the left, sketch a right triangle, going from the first point to the second point.
  3. Count the rise and the run on the legs of the triangle.
  4. Take the ratio of rise to run to find the slope, m=riserunm = \frac{\operatorname{rise}}{\operatorname{run}}.

Examples

  • A line passes through (1,2)(1, 2) and (4,8)(4, 8). The rise is 82=68 - 2 = 6 and the run is 41=34 - 1 = 3. The slope is m=63=2m = \frac{6}{3} = 2.
  • A line passes through (0,6)(0, 6) and (2,2)(2, 2). The rise is 26=42 - 6 = -4 and the run is 20=22 - 0 = 2. The slope is m=42=2m = \frac{-4}{2} = -2.
  • A line on a graph connects points (3,1)(-3, 1) and (5,7)(5, 7). The rise is 71=67-1=6 and the run is 5(3)=85-(-3)=8. The slope is m=68=34m = \frac{6}{8} = \frac{3}{4}.

Explanation

To find slope from a graph, pick two easy-to-read points. Count the vertical distance (rise) and horizontal distance (run) to get from one point to the other. The slope is simply the rise divided by the run.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Module 4: Linear Relationships and Slope

  1. Lesson 1

    Lesson 4-1: Proportional Relationships and Slope

  2. Lesson 2

    Lesson 4-2: Slope of a Line

  3. Lesson 3Current

    Lesson 4-3: Similar Triangles and Slope

  4. Lesson 4

    Lesson 4-4: Direct Variation

  5. Lesson 5

    Lesson 4-5: Slope-Intercept Form

  6. Lesson 6

    Lesson 4-6: Graph Linear Equations