Lesson 4-6: Graph Linear Equations — Practice Questions

1. 1. To graph a line with a slope of $m = \frac{4}{7}$, how should you move from one point on the line to find the next point?

   • A. Up 4 units and right 7 units
   • B. Down 4 units and right 7 units
   • C. Up 7 units and right 4 units
   • D. Down 4 units and left 7 units

2. 2. A line has a slope of $m = -5$. To find a new point from an existing one, you move down 5 units and right ___ units.

3. 3. Which pair of movements correctly describes how to plot a line with a slope of $m = -\frac{2}{9}$?

   • A. Up 2 units, right 9 units
   • B. Down 2 units, right 9 units
   • C. Down 2 units, left 9 units
   • D. Up 9 units, right 2 units

4. 4. When graphing a line with a slope of $m = -\frac{7}{3}$, the vertical change, or rise, is ___. (Use a negative sign for a downward change).

5. 5. A student graphs a line by moving down 3 units and left 4 units between points. What is the slope of the line they graphed?

   • A. $-\frac{3}{4}$
   • B. $-\frac{4}{3}$
   • C. $\frac{3}{4}$
   • D. $\frac{4}{3}$

6. 6. To graph the equation $y = -\frac{3}{4}x + 2$, you first plot the y-intercept at $(0, 2)$. What is the next step using the slope?

   • A. From (0, 2), move down 3 units and right 4 units.
   • B. From (0, 2), move up 3 units and right 4 units.
   • C. From (0, 2), move down 4 units and right 3 units.
   • D. From (0, 2), move up 4 units and right 3 units.

7. 7. To graph the line $y = 5x + 1$, you start by plotting the y-intercept. Using the slope to find a second point, you find the point $(1, \_\_\_)$.

8. 8. What is the first step when graphing the equation $y = 7x - 4$ using the slope-intercept method?

   • A. Plot a point at the origin, (0, 0).
   • B. Plot a point at the y-intercept, (0, -4).
   • C. Use the slope to count from the origin.
   • D. Plot a point at the x-intercept.

9. 9. The equation of a line is $y = -2x$. This line passes through the origin $(0, 0)$. Using the slope, another point on this line is $(1, \_\_\_)$.

10. 10. A line has the equation $y = \frac{1}{3}x - 5$. The y-intercept is at $(0, -5)$. Using the slope, a second point on the line is $(3, \_\_\_)$.