Learn on PengiSaxon Algebra 1Chapter 9: Quadratic Functions and Equations

Lesson 90: Adding and Subtracting Rational Expressions

In Saxon Algebra 1 Lesson 90, Grade 9 students learn to add and subtract rational expressions with both like and unlike denominators. The lesson covers finding the least common multiple to create common denominators, combining numerators, and simplifying results by factoring and canceling common factors, including cases with opposite denominators. Students also apply these skills to real-world problems using the distance formula.

Section 1

πŸ“˜ Adding and Subtracting Rational Expressions

New Concept

Adding and subtracting rational expressions follow the same rules as adding and subtracting fractions.

What’s next

Next, you’ll apply these rules, starting with common denominators and then tackling expressions that require finding the least common multiple to combine them.

Section 2

Adding With Common Denominators

Property

If the denominators are the same, add or subtract the numerators and keep the common denominator. For example, AC+BC=A+BC \frac{A}{C} + \frac{B}{C} = \frac{A+B}{C} .

Explanation

Think of it like adding pizza slices! If the slices are the same size (common denominator), you just count up how many you have (the numerators). The slice size doesn't change, so the denominator stays the same. Simple!

Examples

4x225x+6x225x=10x225x=2x5 \frac{4x^2}{25x} + \frac{6x^2}{25x} = \frac{10x^2}{25x} = \frac{2x}{5}
d2dβˆ’9+3ddβˆ’9=d2+3ddβˆ’9=d(d+3)dβˆ’9 \frac{d^2}{d-9} + \frac{3d}{d-9} = \frac{d^2+3d}{d-9} = \frac{d(d+3)}{d-9}

Section 3

Example Card: Subtracting Expressions with Common Denominators

Subtracting fractions can sometimes lead to a surprisingly simple whole numberβ€”let's see how. This example shows our first key idea: combining rational expressions that already have a common denominator.

Example Problem

Subtract and simplify:

4bβˆ’3b+5βˆ’bβˆ’18b+5\frac{4b - 3}{b + 5} - \frac{b - 18}{b + 5}

Section 4

Finding a Common Denominator

Property

When denominators are different, find the least common multiple (LCM) and rename each expression to have the same denominator before adding or subtracting.

Explanation

You can't add fifths and thirds directly! First, you have to find a common ground, like fifteenths. By multiplying the top and bottom by the "missing piece," you make the denominators match so you can finally combine them.

Examples

xx+2βˆ’4(x+2)(xβˆ’3)=x(xβˆ’3)(x+2)(xβˆ’3)βˆ’4(x+2)(xβˆ’3)=x2βˆ’3xβˆ’4(x+2)(xβˆ’3) \frac{x}{x+2} - \frac{4}{(x+2)(x-3)} = \frac{x(x-3)}{(x+2)(x-3)} - \frac{4}{(x+2)(x-3)} = \frac{x^2-3x-4}{(x+2)(x-3)}
3h4h+5hh2=3h(h)4h(h)+5h(4)h2(4)=3h2+20h4h2=3h+204h \frac{3h}{4h} + \frac{5h}{h^2} = \frac{3h(h)}{4h(h)} + \frac{5h(4)}{h^2(4)} = \frac{3h^2+20h}{4h^2} = \frac{3h+20}{4h}

Section 5

Example Card: Subtracting Expressions with Unlike Denominators

What happens when denominators don't match? We just need to build a common ground. This example demonstrates our second key idea: combining expressions with different denominators.

Example Problem

Subtract and simplify:

y+2yβˆ’3βˆ’7y2+2yβˆ’15\frac{y + 2}{y - 3} - \frac{7}{y^2 + 2y - 15}

Section 6

Caution

Property

Not enclosing the numerator of the subtrahend in parentheses may result in sign errors. ACβˆ’B+DC=Aβˆ’(B+D)C=Aβˆ’Bβˆ’DC \frac{A}{C} - \frac{B+D}{C} = \frac{A-(B+D)}{C} = \frac{A-B-D}{C} .

Explanation

That minus sign is a ninja, trying to attack everything that follows. Parentheses act like a shield, reminding you to distribute the negative sign to every single term inside, flipping all their signs. Don't fall into the trap!

Examples

7aβˆ’3a+4βˆ’aβˆ’5a+4=7aβˆ’3βˆ’(aβˆ’5)a+4=6a+2a+4 \frac{7a-3}{a+4} - \frac{a-5}{a+4} = \frac{7a-3-(a-5)}{a+4} = \frac{6a+2}{a+4}
12xβˆ’6βˆ’x+4xβˆ’6=12βˆ’(x+4)xβˆ’6=12βˆ’xβˆ’4xβˆ’6=8βˆ’xxβˆ’6 \frac{12}{x-6} - \frac{x+4}{x-6} = \frac{12-(x+4)}{x-6} = \frac{12-x-4}{x-6} = \frac{8-x}{x-6}

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10Current

    Lesson 90: Adding and Subtracting Rational Expressions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Adding and Subtracting Rational Expressions

New Concept

Adding and subtracting rational expressions follow the same rules as adding and subtracting fractions.

What’s next

Next, you’ll apply these rules, starting with common denominators and then tackling expressions that require finding the least common multiple to combine them.

Section 2

Adding With Common Denominators

Property

If the denominators are the same, add or subtract the numerators and keep the common denominator. For example, AC+BC=A+BC \frac{A}{C} + \frac{B}{C} = \frac{A+B}{C} .

Explanation

Think of it like adding pizza slices! If the slices are the same size (common denominator), you just count up how many you have (the numerators). The slice size doesn't change, so the denominator stays the same. Simple!

Examples

4x225x+6x225x=10x225x=2x5 \frac{4x^2}{25x} + \frac{6x^2}{25x} = \frac{10x^2}{25x} = \frac{2x}{5}
d2dβˆ’9+3ddβˆ’9=d2+3ddβˆ’9=d(d+3)dβˆ’9 \frac{d^2}{d-9} + \frac{3d}{d-9} = \frac{d^2+3d}{d-9} = \frac{d(d+3)}{d-9}

Section 3

Example Card: Subtracting Expressions with Common Denominators

Subtracting fractions can sometimes lead to a surprisingly simple whole numberβ€”let's see how. This example shows our first key idea: combining rational expressions that already have a common denominator.

Example Problem

Subtract and simplify:

4bβˆ’3b+5βˆ’bβˆ’18b+5\frac{4b - 3}{b + 5} - \frac{b - 18}{b + 5}

Section 4

Finding a Common Denominator

Property

When denominators are different, find the least common multiple (LCM) and rename each expression to have the same denominator before adding or subtracting.

Explanation

You can't add fifths and thirds directly! First, you have to find a common ground, like fifteenths. By multiplying the top and bottom by the "missing piece," you make the denominators match so you can finally combine them.

Examples

xx+2βˆ’4(x+2)(xβˆ’3)=x(xβˆ’3)(x+2)(xβˆ’3)βˆ’4(x+2)(xβˆ’3)=x2βˆ’3xβˆ’4(x+2)(xβˆ’3) \frac{x}{x+2} - \frac{4}{(x+2)(x-3)} = \frac{x(x-3)}{(x+2)(x-3)} - \frac{4}{(x+2)(x-3)} = \frac{x^2-3x-4}{(x+2)(x-3)}
3h4h+5hh2=3h(h)4h(h)+5h(4)h2(4)=3h2+20h4h2=3h+204h \frac{3h}{4h} + \frac{5h}{h^2} = \frac{3h(h)}{4h(h)} + \frac{5h(4)}{h^2(4)} = \frac{3h^2+20h}{4h^2} = \frac{3h+20}{4h}

Section 5

Example Card: Subtracting Expressions with Unlike Denominators

What happens when denominators don't match? We just need to build a common ground. This example demonstrates our second key idea: combining expressions with different denominators.

Example Problem

Subtract and simplify:

y+2yβˆ’3βˆ’7y2+2yβˆ’15\frac{y + 2}{y - 3} - \frac{7}{y^2 + 2y - 15}

Section 6

Caution

Property

Not enclosing the numerator of the subtrahend in parentheses may result in sign errors. ACβˆ’B+DC=Aβˆ’(B+D)C=Aβˆ’Bβˆ’DC \frac{A}{C} - \frac{B+D}{C} = \frac{A-(B+D)}{C} = \frac{A-B-D}{C} .

Explanation

That minus sign is a ninja, trying to attack everything that follows. Parentheses act like a shield, reminding you to distribute the negative sign to every single term inside, flipping all their signs. Don't fall into the trap!

Examples

7aβˆ’3a+4βˆ’aβˆ’5a+4=7aβˆ’3βˆ’(aβˆ’5)a+4=6a+2a+4 \frac{7a-3}{a+4} - \frac{a-5}{a+4} = \frac{7a-3-(a-5)}{a+4} = \frac{6a+2}{a+4}
12xβˆ’6βˆ’x+4xβˆ’6=12βˆ’(x+4)xβˆ’6=12βˆ’xβˆ’4xβˆ’6=8βˆ’xxβˆ’6 \frac{12}{x-6} - \frac{x+4}{x-6} = \frac{12-(x+4)}{x-6} = \frac{12-x-4}{x-6} = \frac{8-x}{x-6}

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10Current

    Lesson 90: Adding and Subtracting Rational Expressions