Learn on PengiSaxon Algebra 1Chapter 9: Quadratic Functions and Equations

Lesson 89: Identifying Characteristics of Quadratic Functions

New Concept The axis of symmetry for the graph of a quadratic equation $y = ax^2 + bx + c$ is $x = \frac{b}{2a}$. What’s next Next, you’ll apply this formula and other tools to analyze the key features of parabolas, like their vertex and zeros.

Section 1

📘 Identifying Characteristics of Quadratic Functions

New Concept

The axis of symmetry for the graph of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}.

What’s next

Next, you’ll apply this formula and other tools to analyze the key features of parabolas, like their vertex and zeros.

Section 2

Vertex of a parabola

Property

The vertex of a parabola is the highest or lowest point on a parabola. It is the parabola's 'turning point.' The minimum or maximum is the y-coordinate of the vertex.

Explanation

Imagine a roller coaster track shaped like a 'U'. The vertex is the very bottom of the dip (a minimum) or the top of the hill (a maximum). It's the point where the ride changes direction, telling you the absolute lowest or highest the coaster goes on its path!

Examples

  • For the parabola y=x26y=x^2-6, the vertex at (0,6)(0, -6) is the lowest point, so the minimum value is 6-6.
  • For the parabola y=x2+2x+7y=-x^2+2x+7, the vertex at (1,8)(1, 8) is the highest point, so the maximum value is 88.

Section 3

Zero of a function

Property

A zero of a function is the value of xx that makes f(x)=0f(x) = 0. The zeros are the same as the x-intercepts because y=0y = 0 on the x-axis. These are also known as the function's roots.

Explanation

Think of zeros as the 'touchdown' points where the parabola hits the ground (the x-axis). At these spots, the function's value is exactly zero. Finding these roots is like solving a puzzle to discover where your graph crosses the horizontal line, a key clue to its location.

Examples

  • The function f(x)=x2+2x+3f(x) = -x^2 + 2x + 3 has zeros at x=1x=-1 and x=3x=3, where the graph crosses the x-axis.
  • The function f(x)=3x2+12x+12f(x) = 3x^2 + 12x + 12 has one zero at x=2x=-2, where the vertex touches the x-axis.
  • The function f(x)=x24x+6f(x) = x^2 - 4x + 6 has no real zeros because its graph never crosses the x-axis.

Section 4

Example Card: Finding the Axis of Symmetry from Zeros

A parabola's symmetry is perfectly balanced between its roots. Let's find that balance point using the key idea of finding the axis of symmetry from the zeros of a function.

Example Problem

Find the axis of symmetry for a parabola with zeros at (2,0)(-2, 0) and (8,0)(8, 0).

Step-by-step

  1. The axis of symmetry is a vertical line that passes through the vertex, exactly halfway between the zeros. We can find its x-coordinate by averaging the x-coordinates of the zeros.
  2. Average the zeros to find the x-coordinate of the vertex:
2+82=62=3\frac{-2+8}{2} = \frac{6}{2} = 3
  1. The x-coordinate of the vertex is 33.
  2. Since the axis of symmetry is the vertical line passing through the vertex, its equation is x=3x = 3.

Section 5

Axis of Symmetry Formula

Property

The axis of symmetry for the graph of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}.

Explanation

This formula is your secret weapon for finding the invisible line that splits a parabola into two perfect mirror images. This line always passes straight through the vertex, so the formula also gives you the x-coordinate of the vertex! Just plug in the 'a' and 'b' from your equation.

Examples

  • For y=x2+6x+5y = x^2 + 6x + 5, the axis of symmetry is x=62(1)=3x = -\frac{6}{2(1)} = -3.
  • For y=2x2+8x1y = -2x^2 + 8x - 1, the axis of symmetry is x=82(2)=2x = -\frac{8}{2(-2)} = 2.
  • For a golf ball's height y=16t2+160t+10y = -16t^2 + 160t + 10, the time to reach the max height is t=1602(16)=5t = -\frac{160}{2(-16)} = 5 seconds.

Book overview

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Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9Current

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10

    Lesson 90: Adding and Subtracting Rational Expressions

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

📘 Identifying Characteristics of Quadratic Functions

New Concept

The axis of symmetry for the graph of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}.

What’s next

Next, you’ll apply this formula and other tools to analyze the key features of parabolas, like their vertex and zeros.

Section 2

Vertex of a parabola

Property

The vertex of a parabola is the highest or lowest point on a parabola. It is the parabola's 'turning point.' The minimum or maximum is the y-coordinate of the vertex.

Explanation

Imagine a roller coaster track shaped like a 'U'. The vertex is the very bottom of the dip (a minimum) or the top of the hill (a maximum). It's the point where the ride changes direction, telling you the absolute lowest or highest the coaster goes on its path!

Examples

  • For the parabola y=x26y=x^2-6, the vertex at (0,6)(0, -6) is the lowest point, so the minimum value is 6-6.
  • For the parabola y=x2+2x+7y=-x^2+2x+7, the vertex at (1,8)(1, 8) is the highest point, so the maximum value is 88.

Section 3

Zero of a function

Property

A zero of a function is the value of xx that makes f(x)=0f(x) = 0. The zeros are the same as the x-intercepts because y=0y = 0 on the x-axis. These are also known as the function's roots.

Explanation

Think of zeros as the 'touchdown' points where the parabola hits the ground (the x-axis). At these spots, the function's value is exactly zero. Finding these roots is like solving a puzzle to discover where your graph crosses the horizontal line, a key clue to its location.

Examples

  • The function f(x)=x2+2x+3f(x) = -x^2 + 2x + 3 has zeros at x=1x=-1 and x=3x=3, where the graph crosses the x-axis.
  • The function f(x)=3x2+12x+12f(x) = 3x^2 + 12x + 12 has one zero at x=2x=-2, where the vertex touches the x-axis.
  • The function f(x)=x24x+6f(x) = x^2 - 4x + 6 has no real zeros because its graph never crosses the x-axis.

Section 4

Example Card: Finding the Axis of Symmetry from Zeros

A parabola's symmetry is perfectly balanced between its roots. Let's find that balance point using the key idea of finding the axis of symmetry from the zeros of a function.

Example Problem

Find the axis of symmetry for a parabola with zeros at (2,0)(-2, 0) and (8,0)(8, 0).

Step-by-step

  1. The axis of symmetry is a vertical line that passes through the vertex, exactly halfway between the zeros. We can find its x-coordinate by averaging the x-coordinates of the zeros.
  2. Average the zeros to find the x-coordinate of the vertex:
2+82=62=3\frac{-2+8}{2} = \frac{6}{2} = 3
  1. The x-coordinate of the vertex is 33.
  2. Since the axis of symmetry is the vertical line passing through the vertex, its equation is x=3x = 3.

Section 5

Axis of Symmetry Formula

Property

The axis of symmetry for the graph of a quadratic equation y=ax2+bx+cy = ax^2 + bx + c is x=b2ax = -\frac{b}{2a}.

Explanation

This formula is your secret weapon for finding the invisible line that splits a parabola into two perfect mirror images. This line always passes straight through the vertex, so the formula also gives you the x-coordinate of the vertex! Just plug in the 'a' and 'b' from your equation.

Examples

  • For y=x2+6x+5y = x^2 + 6x + 5, the axis of symmetry is x=62(1)=3x = -\frac{6}{2(1)} = -3.
  • For y=2x2+8x1y = -2x^2 + 8x - 1, the axis of symmetry is x=82(2)=2x = -\frac{8}{2(-2)} = 2.
  • For a golf ball's height y=16t2+160t+10y = -16t^2 + 160t + 10, the time to reach the max height is t=1602(16)=5t = -\frac{160}{2(-16)} = 5 seconds.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9Current

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10

    Lesson 90: Adding and Subtracting Rational Expressions