Learn on PengiSaxon Algebra 1Chapter 9: Quadratic Functions and Equations

Lesson 81: Solving Inequalities with Variables on Both Sides

In this Grade 9 Saxon Algebra 1 lesson, students learn to solve inequalities with variables on both sides by isolating the variable through addition, subtraction, multiplication, and division, including cases that require the distributive property and combining like terms. Students also identify special cases such as identities (always true) and contradictions (never true), and interpret solution sets using number line graphs. The lesson is part of Chapter 9 on Quadratic Functions and Equations and includes a real-world application connecting inequality solving to data trends.

Section 1

📘 Solving Inequalities with Variables on Both Sides

New Concept

An inequality or equation that is always true is called an identity. A contradiction is an inequality or an equation that is never true (false).

What’s next

Next, you’ll use familiar properties to solve these inequalities, including special cases that result in all or no solutions.

Section 2

Solving Inequalities with Variables on Both Sides

Property

To solve an inequality with variables on both sides, the goal is to transform it by isolating the variable. Use the properties of inequality to move all variable terms to one side and all constant terms to the other side.

Explanation

Think of it as a cosmic balance! To find the variable's true value, you must keep the inequality scale even. Whatever you do to one side—like adding 5x5x or subtracting 7—you must do to the other. Systematically clear away terms until the variable is left standing all by itself, revealing its secret identity.

Examples

To solve 4x+6>2x+244x + 6 > -2x + 24, first add 2x2x to both sides to get 6x+6>246x + 6 > 24.
Then, subtract 6 from both sides to get 6x>186x > 18.
Finally, divide by 6 to find the solution: x>3x > 3.

Section 3

Example Card: Solving an Inequality with Variables on Both Sides

Getting variables on one side is the first step to taming these tricky inequalities.

Example Problem

Solve the inequality 3x+5>4x+263x + 5 > -4x + 26.

Section 4

Simplifying Each Side Before Solving

Property

Before isolating the variable, you must first simplify each side of the inequality. Use the Distributive Property to remove parentheses and then combine any like terms to make the inequality as tidy as possible before you begin solving.

Explanation

Don't jump into solving a messy problem! It's like trying to cook without prepping your ingredients. First, 'chop' expressions by distributing, then 'mix' the like terms together. Once each side is neat and organized, solving for the variable becomes much simpler and you are less likely to make a mistake.

Examples

For 4(k2)5k>102(3k+1)4(k - 2) - 5k > 10 - 2(3k + 1), first distribute to get 4k85k>106k24k - 8 - 5k > 10 - 6k - 2.
Combine like terms on both sides to get k8>86k-k - 8 > 8 - 6k.
Now it's a simple inequality ready to be solved.

Section 5

Example Card: Simplifying Each Side Before Solving an Inequality

Let's see how simplifying each side first makes solving this inequality much clearer.

Example Problem

Solve the inequality 3(x5)4x82(3x+2)3(x - 5) - 4x \le 8 - 2(3x + 2).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1Current

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10

    Lesson 90: Adding and Subtracting Rational Expressions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Solving Inequalities with Variables on Both Sides

New Concept

An inequality or equation that is always true is called an identity. A contradiction is an inequality or an equation that is never true (false).

What’s next

Next, you’ll use familiar properties to solve these inequalities, including special cases that result in all or no solutions.

Section 2

Solving Inequalities with Variables on Both Sides

Property

To solve an inequality with variables on both sides, the goal is to transform it by isolating the variable. Use the properties of inequality to move all variable terms to one side and all constant terms to the other side.

Explanation

Think of it as a cosmic balance! To find the variable's true value, you must keep the inequality scale even. Whatever you do to one side—like adding 5x5x or subtracting 7—you must do to the other. Systematically clear away terms until the variable is left standing all by itself, revealing its secret identity.

Examples

To solve 4x+6>2x+244x + 6 > -2x + 24, first add 2x2x to both sides to get 6x+6>246x + 6 > 24.
Then, subtract 6 from both sides to get 6x>186x > 18.
Finally, divide by 6 to find the solution: x>3x > 3.

Section 3

Example Card: Solving an Inequality with Variables on Both Sides

Getting variables on one side is the first step to taming these tricky inequalities.

Example Problem

Solve the inequality 3x+5>4x+263x + 5 > -4x + 26.

Section 4

Simplifying Each Side Before Solving

Property

Before isolating the variable, you must first simplify each side of the inequality. Use the Distributive Property to remove parentheses and then combine any like terms to make the inequality as tidy as possible before you begin solving.

Explanation

Don't jump into solving a messy problem! It's like trying to cook without prepping your ingredients. First, 'chop' expressions by distributing, then 'mix' the like terms together. Once each side is neat and organized, solving for the variable becomes much simpler and you are less likely to make a mistake.

Examples

For 4(k2)5k>102(3k+1)4(k - 2) - 5k > 10 - 2(3k + 1), first distribute to get 4k85k>106k24k - 8 - 5k > 10 - 6k - 2.
Combine like terms on both sides to get k8>86k-k - 8 > 8 - 6k.
Now it's a simple inequality ready to be solved.

Section 5

Example Card: Simplifying Each Side Before Solving an Inequality

Let's see how simplifying each side first makes solving this inequality much clearer.

Example Problem

Solve the inequality 3(x5)4x82(3x+2)3(x - 5) - 4x \le 8 - 2(3x + 2).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Quadratic Functions and Equations

  1. Lesson 1Current

    Lesson 81: Solving Inequalities with Variables on Both Sides

  2. Lesson 2

    Lesson 82: Solving Multi-Step Compound Inequalities

  3. Lesson 3

    Lesson 83: Factoring Special Products

  4. Lesson 4

    Lesson 84: Identifying Quadratic Functions

  5. Lesson 5

    Lesson 85: Solving Problems Using the Pythagorean Theorem

  6. Lesson 6

    Lesson 86: Calculating the Midpoint and Length of a Segment

  7. Lesson 7

    Lesson 87: Factoring Polynomials by Grouping

  8. Lesson 8

    Lesson 88: Multiplying and Dividing Rational Expressions

  9. Lesson 9

    Lesson 89: Identifying Characteristics of Quadratic Functions

  10. Lesson 10

    Lesson 90: Adding and Subtracting Rational Expressions