Learn on PengiSaxon Math, Course 3Chapter 7: Algebra

Lesson 69: Direct Variation

In this Grade 8 Saxon Math Course 3 lesson, students learn the concept of direct variation, expressed as y = kx, where k is the constant of proportionality linking two proportional variables. Students identify direct variation relationships by checking for a constant ratio in tables and by recognizing graphs that form a straight line passing through the origin. The lesson also introduces the roles of independent and dependent variables within real-world contexts such as pay rates and perimeter formulas.

Section 1

📘 Direct Variation

New Concept

Direct variation describes a relationship where two quantities increase or decrease together at a constant rate. When two variables are proportional, the value of one variable can be found by multiplying the other by a constant factor. We call this relationship between the variables direct variation.

y=kxy = kx

In this equation, xx and yy are the variables, and kk is the constant multiplier, called the constant of proportionality.

What’s next

Now that you have the basics, you'll learn to identify direct variation from tables and graphs and solve problems using the constant of proportionality.

Section 2

Direct variation

Property

When two variables are proportional, one value is found by multiplying the other by a constant factor, kk. This relationship is defined by the equation:

y=kxy = kx

Examples

Your pay depends on hours worked: TotalPay=12 dollars×hoursTotal Pay = 12 \text{ dollars} \times hours.
The perimeter of a square depends on its side length: P=4×sP = 4 \times s.

Explanation

Think of it like this: whatever the independent variable (x) does, the dependent variable (y) copies it, but scaled by the special number k. If x doubles, y doubles. If x is cut in half, so is y. Their ratio is always constant and predictable.

Section 3

Constant of proportionality

Property

The constant of proportionality, kk, is the fixed ratio in a direct variation, calculated as the dependent variable (yy) divided by the independent variable (xx).

k=yxk = \frac{y}{x}

Examples

If pay is 36 dollars for 3 hours, the constant is k=363=12k = \frac{36}{3} = 12.
If Eunice says -2 and Doubleday replies -4 in the equation d=ked=ke, then k=−4−2=2k = \frac{-4}{-2} = 2.

Explanation

This is the relationship's "magic number"! It’s the one value that connects the two variables and tells you their secret. To find it, just divide the output (y) by the input (x). It never, ever changes for that specific relationship.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Algebra

  1. Lesson 1

    Lesson 61: Sequences

  2. Lesson 2

    Lesson 62: Graphing Solutions to Inequalities on a Number Line

  3. Lesson 3

    Lesson 63: Rational Numbers, Non-Terminating Decimals, and Percents and Fractions with Negative Exponents

  4. Lesson 4

    Lesson 64: Using a Unit Multiplier to Convert a Rate

  5. Lesson 5

    Lesson 65: Applications Using Similar Triangles

  6. Lesson 6

    Lesson 66: Special Right Triangles

  7. Lesson 7

    Lesson 67: Percent of Change

  8. Lesson 8

    Lesson 68: Probability Multiplication Rule

  9. Lesson 9Current

    Lesson 69: Direct Variation

  10. Lesson 10

    Lesson 70: Solving Direct Variation Problems

  11. Lesson 11

    Investigation 7: Probability Simulation

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Direct Variation

New Concept

Direct variation describes a relationship where two quantities increase or decrease together at a constant rate. When two variables are proportional, the value of one variable can be found by multiplying the other by a constant factor. We call this relationship between the variables direct variation.

y=kxy = kx

In this equation, xx and yy are the variables, and kk is the constant multiplier, called the constant of proportionality.

What’s next

Now that you have the basics, you'll learn to identify direct variation from tables and graphs and solve problems using the constant of proportionality.

Section 2

Direct variation

Property

When two variables are proportional, one value is found by multiplying the other by a constant factor, kk. This relationship is defined by the equation:

y=kxy = kx

Examples

Your pay depends on hours worked: TotalPay=12 dollars×hoursTotal Pay = 12 \text{ dollars} \times hours.
The perimeter of a square depends on its side length: P=4×sP = 4 \times s.

Explanation

Think of it like this: whatever the independent variable (x) does, the dependent variable (y) copies it, but scaled by the special number k. If x doubles, y doubles. If x is cut in half, so is y. Their ratio is always constant and predictable.

Section 3

Constant of proportionality

Property

The constant of proportionality, kk, is the fixed ratio in a direct variation, calculated as the dependent variable (yy) divided by the independent variable (xx).

k=yxk = \frac{y}{x}

Examples

If pay is 36 dollars for 3 hours, the constant is k=363=12k = \frac{36}{3} = 12.
If Eunice says -2 and Doubleday replies -4 in the equation d=ked=ke, then k=−4−2=2k = \frac{-4}{-2} = 2.

Explanation

This is the relationship's "magic number"! It’s the one value that connects the two variables and tells you their secret. To find it, just divide the output (y) by the input (x). It never, ever changes for that specific relationship.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Algebra

  1. Lesson 1

    Lesson 61: Sequences

  2. Lesson 2

    Lesson 62: Graphing Solutions to Inequalities on a Number Line

  3. Lesson 3

    Lesson 63: Rational Numbers, Non-Terminating Decimals, and Percents and Fractions with Negative Exponents

  4. Lesson 4

    Lesson 64: Using a Unit Multiplier to Convert a Rate

  5. Lesson 5

    Lesson 65: Applications Using Similar Triangles

  6. Lesson 6

    Lesson 66: Special Right Triangles

  7. Lesson 7

    Lesson 67: Percent of Change

  8. Lesson 8

    Lesson 68: Probability Multiplication Rule

  9. Lesson 9Current

    Lesson 69: Direct Variation

  10. Lesson 10

    Lesson 70: Solving Direct Variation Problems

  11. Lesson 11

    Investigation 7: Probability Simulation