Learn on PengiSaxon Math, Course 3Chapter 7: Algebra

Lesson 67: Percent of Change

In this Grade 8 lesson from Saxon Math, Course 3, students learn how to calculate percent of change, including both percent increase and percent decrease. They use ratio tables and proportions to find unknown original prices, new prices, or the dollar amount of change when given a percent change. Real-world contexts like sale prices and rising home values are used to apply these skills.

Section 1

📘 Percent of Change

New Concept

Percents can describe a change, like an increase or decrease. We use a special three-row ratio table (Original, Change, New) to solve these problems.

What’s next

You're just getting started! Next, you’ll tackle worked examples using this ratio table to find sale prices, original costs, and the exact amount of a change.

Section 2

Calculating Original Price After Discount

Property

To find the original price after a discount, use a proportion comparing the original percent (100%) to the new percent (100% - discount %).

100100−Discount %=Original PriceSale Price \frac{100}{100 - \text{Discount \%}} = \frac{\text{Original Price}}{\text{Sale Price}}

Examples

  • A jacket bought at a 40% off sale cost 48 dollars. What was the original price?
    10060=x48→60x=4800→x=80\frac{100}{60} = \frac{x}{48} \rightarrow 60x = 4800 \rightarrow x = 80
    . The original price was 80 dollars.
  • A video game is on sale for 25% off and costs 45 dollars. Find its original price.
    10075=x45→75x=4500→x=60\frac{100}{75} = \frac{x}{45} \rightarrow 75x = 4500 \rightarrow x = 60
    . The original price was 60 dollars.

Explanation

When an item is discounted, its sale price is a new, smaller percentage of the original. The original is always 100%. If you get 30% off, you pay 70%. We use this simple logic to create a proportion that pits the original percent against the new percent to find the starting price, our mystery number!

Section 3

Calculating The Amount Of Increase

Property

To find the specific amount of change from an increase, use a proportion comparing the percent increase to the new total percent (100% + increase %).

Increase %100+Increase %=Amount of ChangeNew Value \frac{\text{Increase \%}}{100 + \text{Increase \%}} = \frac{\text{Amount of Change}}{\text{New Value}}

Examples

  • A collectible's value rose 10% in one year to 550 dollars. By how many dollars did its value increase?
    10110=c550→110c=5500→c=50\frac{10}{110} = \frac{c}{550} \rightarrow 110c = 5500 \rightarrow c = 50
    . The value increased by 50 dollars.
  • A town's population grew by 30% to 13,000 people. How many new people moved to the town?
    30130=c13000→130c=390000→c=3000\frac{30}{130} = \frac{c}{13000} \rightarrow 130c = 390000 \rightarrow c = 3000
    . The population increased by 3000 people.

Explanation

When a value goes up, the new amount is more than 100% of the original. If a price rises by 20%, the new price is 120% of the old one. We can then set up a proportion comparing the percent increase to the total new percent, which allows us to find the exact dollar amount of that increase.

Section 4

Percent Of Change Ratio Table

Property

A ratio table with three rows helps organize percent problems: one for the Original (100%), one for the Change (Increase + or Decrease –), and one for the New total.

Examples

  • For a 20% discount on a 50 dollar item, the New % is 100%−20%=80%100\% - 20\% = 80\%. To find the sale price:
    80100=x50→100x=4000→x=40\frac{80}{100} = \frac{x}{50} \rightarrow 100x = 4000 \rightarrow x=40
    . The sale price is 40 dollars.
  • A store marks up a 30 dollar item by 60%. The New % is 100%+60%=160%100\% + 60\% = 160\%. To find the store price:
    160100=x30→100x=4800→x=48\frac{160}{100} = \frac{x}{30} \rightarrow 100x = 4800 \rightarrow x=48
    . The store price is 48 dollars.

Explanation

This awesome table keeps our numbers organized! The 'Original' is always your 100% baseline. Just add the percent change for an increase or subtract it for a decrease to find the 'New' percentage. This structure lets you create a simple proportion to solve for any missing piece, whether it’s the old price or the change amount.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Algebra

  1. Lesson 1

    Lesson 61: Sequences

  2. Lesson 2

    Lesson 62: Graphing Solutions to Inequalities on a Number Line

  3. Lesson 3

    Lesson 63: Rational Numbers, Non-Terminating Decimals, and Percents and Fractions with Negative Exponents

  4. Lesson 4

    Lesson 64: Using a Unit Multiplier to Convert a Rate

  5. Lesson 5

    Lesson 65: Applications Using Similar Triangles

  6. Lesson 6

    Lesson 66: Special Right Triangles

  7. Lesson 7Current

    Lesson 67: Percent of Change

  8. Lesson 8

    Lesson 68: Probability Multiplication Rule

  9. Lesson 9

    Lesson 69: Direct Variation

  10. Lesson 10

    Lesson 70: Solving Direct Variation Problems

  11. Lesson 11

    Investigation 7: Probability Simulation

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Percent of Change

New Concept

Percents can describe a change, like an increase or decrease. We use a special three-row ratio table (Original, Change, New) to solve these problems.

What’s next

You're just getting started! Next, you’ll tackle worked examples using this ratio table to find sale prices, original costs, and the exact amount of a change.

Section 2

Calculating Original Price After Discount

Property

To find the original price after a discount, use a proportion comparing the original percent (100%) to the new percent (100% - discount %).

100100−Discount %=Original PriceSale Price \frac{100}{100 - \text{Discount \%}} = \frac{\text{Original Price}}{\text{Sale Price}}

Examples

  • A jacket bought at a 40% off sale cost 48 dollars. What was the original price?
    10060=x48→60x=4800→x=80\frac{100}{60} = \frac{x}{48} \rightarrow 60x = 4800 \rightarrow x = 80
    . The original price was 80 dollars.
  • A video game is on sale for 25% off and costs 45 dollars. Find its original price.
    10075=x45→75x=4500→x=60\frac{100}{75} = \frac{x}{45} \rightarrow 75x = 4500 \rightarrow x = 60
    . The original price was 60 dollars.

Explanation

When an item is discounted, its sale price is a new, smaller percentage of the original. The original is always 100%. If you get 30% off, you pay 70%. We use this simple logic to create a proportion that pits the original percent against the new percent to find the starting price, our mystery number!

Section 3

Calculating The Amount Of Increase

Property

To find the specific amount of change from an increase, use a proportion comparing the percent increase to the new total percent (100% + increase %).

Increase %100+Increase %=Amount of ChangeNew Value \frac{\text{Increase \%}}{100 + \text{Increase \%}} = \frac{\text{Amount of Change}}{\text{New Value}}

Examples

  • A collectible's value rose 10% in one year to 550 dollars. By how many dollars did its value increase?
    10110=c550→110c=5500→c=50\frac{10}{110} = \frac{c}{550} \rightarrow 110c = 5500 \rightarrow c = 50
    . The value increased by 50 dollars.
  • A town's population grew by 30% to 13,000 people. How many new people moved to the town?
    30130=c13000→130c=390000→c=3000\frac{30}{130} = \frac{c}{13000} \rightarrow 130c = 390000 \rightarrow c = 3000
    . The population increased by 3000 people.

Explanation

When a value goes up, the new amount is more than 100% of the original. If a price rises by 20%, the new price is 120% of the old one. We can then set up a proportion comparing the percent increase to the total new percent, which allows us to find the exact dollar amount of that increase.

Section 4

Percent Of Change Ratio Table

Property

A ratio table with three rows helps organize percent problems: one for the Original (100%), one for the Change (Increase + or Decrease –), and one for the New total.

Examples

  • For a 20% discount on a 50 dollar item, the New % is 100%−20%=80%100\% - 20\% = 80\%. To find the sale price:
    80100=x50→100x=4000→x=40\frac{80}{100} = \frac{x}{50} \rightarrow 100x = 4000 \rightarrow x=40
    . The sale price is 40 dollars.
  • A store marks up a 30 dollar item by 60%. The New % is 100%+60%=160%100\% + 60\% = 160\%. To find the store price:
    160100=x30→100x=4800→x=48\frac{160}{100} = \frac{x}{30} \rightarrow 100x = 4800 \rightarrow x=48
    . The store price is 48 dollars.

Explanation

This awesome table keeps our numbers organized! The 'Original' is always your 100% baseline. Just add the percent change for an increase or subtract it for a decrease to find the 'New' percentage. This structure lets you create a simple proportion to solve for any missing piece, whether it’s the old price or the change amount.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Algebra

  1. Lesson 1

    Lesson 61: Sequences

  2. Lesson 2

    Lesson 62: Graphing Solutions to Inequalities on a Number Line

  3. Lesson 3

    Lesson 63: Rational Numbers, Non-Terminating Decimals, and Percents and Fractions with Negative Exponents

  4. Lesson 4

    Lesson 64: Using a Unit Multiplier to Convert a Rate

  5. Lesson 5

    Lesson 65: Applications Using Similar Triangles

  6. Lesson 6

    Lesson 66: Special Right Triangles

  7. Lesson 7Current

    Lesson 67: Percent of Change

  8. Lesson 8

    Lesson 68: Probability Multiplication Rule

  9. Lesson 9

    Lesson 69: Direct Variation

  10. Lesson 10

    Lesson 70: Solving Direct Variation Problems

  11. Lesson 11

    Investigation 7: Probability Simulation