Learn on PengiSaxon Math, Intermediate 4Chapter 6: Lessons 51–60, Investigation 6

Lesson 53: One-Digit Division with a Remainder, Activity Finding Equal Groups with Remainders

In this Grade 4 lesson from Saxon Math Intermediate 4, students learn how to perform one-digit division with a remainder, using the standard division algorithm to find a quotient and identify the leftover amount written in R notation. The lesson walks through the steps of dividing, multiplying, and subtracting to calculate remainders, supported by dot sketches and real-world word problems involving equal groups.

Section 1

📘 One-Digit Division with a Remainder

New Concept

The amount left over is the remainder.

What’s next

Next, you'll apply this concept by solving division problems where a leftover amount, the remainder, is part of the answer.

Section 2

remainder

Property

When a number cannot be perfectly divided into equal groups, the amount left over is the remainder. For instance, while 12 dots can be split into three perfect groups of four, 13 dots cannot. After making three groups of four, one dot remains. This leftover amount is the remainder, representing the part that does not fit evenly.

Example

For 13÷413 \div 4, we can make 3 groups, with 1 left over. The answer is written as 3 R 13 \text{ R } 1.
For 17÷317 \div 3, we can make 5 groups of three (5×3=155 \times 3 = 15), with 2 left over. The answer is 5 R 25 \text{ R } 2.
For 25÷625 \div 6, we can make 4 groups of six (4×6=244 \times 6 = 24), with 1 left over. The answer is 4 R 14 \text{ R } 1.

Explanation

Think of it as sharing cookies! If you have 13 cookies for 4 friends, each gets 3, but 1 cookie is left. That lonely, extra cookie is the remainder!

Section 3

One-Digit Division with a Remainder

Property

To solve a division problem like 4)134 \overline{) 13}, first find how many full groups you can make. Since 3×4=123 \times 4 = 12 is close to 13 without going over, you write 3 as the quotient. Next, multiply your answer by the divisor (3×4=123 \times 4 = 12) and write it below. Finally, subtract to find the remainder (1312=113 - 12 = 1).

Example

To solve 3)163 \overline{) 16}: Divide 16 by 3 to get 5. Multiply 5×3=155 \times 3 = 15. Subtract 1615=116 - 15 = 1. The answer is 5 R 15 \text{ R } 1.
To solve 5)125 \overline{) 12}: Divide 12 by 5 to get 2. Multiply 2×5=102 \times 5 = 10. Subtract 1210=212 - 10 = 2. The answer is 2 R 22 \text{ R } 2.
To solve 4)234 \overline{) 23}: Divide 23 by 4 to get 5. Multiply 5×4=205 \times 4 = 20. Subtract 2320=323 - 20 = 3. The answer is 5 R 35 \text{ R } 3.

Explanation

It’s a simple three-step dance: Divide, Multiply, and then Subtract! This helps you find the number of full groups and identify exactly what’s left over at the end.

Section 4

Interpreting Remainders in Word Problems

Property

In real-world scenarios, the remainder holds a specific meaning that guides your final answer. If 20 people need rides in vans that hold 6 each, dividing 20÷620 \div 6 gives 3 R 2. This means 3 vans are filled completely, and the remainder of 2 represents the people who need a separate car. The context determines how you use leftovers.

Example

20 members need rides in vans that hold 6. 20÷6=3 R 220 \div 6 = 3 \text{ R } 2. This means 3 vans are full and 2 members need a separate ride.
Lucius needs 18 quarts of cider, sold in 4-quart gallons. 18÷4=4 R 218 \div 4 = 4 \text{ R } 2. He must buy 5 full gallons to have enough cider.
Nina threw a shot put 28 feet. To find the yards, 28÷3=9 R 128 \div 3 = 9 \text{ R } 1. This is 9 full yards and 1 extra foot.

Explanation

Don't just write 'R 2' and walk away! That remainder could be leftover pizza slices, people needing another car, or extra feet of ribbon. Always ask what it represents!

Book overview

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Chapter 6: Lessons 51–60, Investigation 6

  1. Lesson 1

    Lesson 51: Adding Numbers with More Than Three Digits, Checking One-Digit Division

  2. Lesson 2

    Lesson 52: Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

  3. Lesson 3Current

    Lesson 53: One-Digit Division with a Remainder, Activity Finding Equal Groups with Remainders

  4. Lesson 4

    Lesson 54: The Calendar, Rounding Numbers to the Nearest Thousand

  5. Lesson 5

    Lesson 55: Prime and Composite Numbers, Activity Using Arrays to Find Factors

  6. Lesson 6

    Lesson 56: Using Models and Pictures to Compare Fractions, Activity Comparing Fractions

  7. Lesson 7

    Lesson 57: Rate Word Problems

  8. Lesson 8

    Lesson 58: Multiplying Three-Digit Numbers

  9. Lesson 9

    Lesson 59: Estimating Arithmetic Answers

  10. Lesson 10

    Lesson 60: Rate Problems with a Given Total

  11. Lesson 11

    Investigation 6: Displaying Data Using Graphs, Activity Displaying Information on Graphs

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 One-Digit Division with a Remainder

New Concept

The amount left over is the remainder.

What’s next

Next, you'll apply this concept by solving division problems where a leftover amount, the remainder, is part of the answer.

Section 2

remainder

Property

When a number cannot be perfectly divided into equal groups, the amount left over is the remainder. For instance, while 12 dots can be split into three perfect groups of four, 13 dots cannot. After making three groups of four, one dot remains. This leftover amount is the remainder, representing the part that does not fit evenly.

Example

For 13÷413 \div 4, we can make 3 groups, with 1 left over. The answer is written as 3 R 13 \text{ R } 1.
For 17÷317 \div 3, we can make 5 groups of three (5×3=155 \times 3 = 15), with 2 left over. The answer is 5 R 25 \text{ R } 2.
For 25÷625 \div 6, we can make 4 groups of six (4×6=244 \times 6 = 24), with 1 left over. The answer is 4 R 14 \text{ R } 1.

Explanation

Think of it as sharing cookies! If you have 13 cookies for 4 friends, each gets 3, but 1 cookie is left. That lonely, extra cookie is the remainder!

Section 3

One-Digit Division with a Remainder

Property

To solve a division problem like 4)134 \overline{) 13}, first find how many full groups you can make. Since 3×4=123 \times 4 = 12 is close to 13 without going over, you write 3 as the quotient. Next, multiply your answer by the divisor (3×4=123 \times 4 = 12) and write it below. Finally, subtract to find the remainder (1312=113 - 12 = 1).

Example

To solve 3)163 \overline{) 16}: Divide 16 by 3 to get 5. Multiply 5×3=155 \times 3 = 15. Subtract 1615=116 - 15 = 1. The answer is 5 R 15 \text{ R } 1.
To solve 5)125 \overline{) 12}: Divide 12 by 5 to get 2. Multiply 2×5=102 \times 5 = 10. Subtract 1210=212 - 10 = 2. The answer is 2 R 22 \text{ R } 2.
To solve 4)234 \overline{) 23}: Divide 23 by 4 to get 5. Multiply 5×4=205 \times 4 = 20. Subtract 2320=323 - 20 = 3. The answer is 5 R 35 \text{ R } 3.

Explanation

It’s a simple three-step dance: Divide, Multiply, and then Subtract! This helps you find the number of full groups and identify exactly what’s left over at the end.

Section 4

Interpreting Remainders in Word Problems

Property

In real-world scenarios, the remainder holds a specific meaning that guides your final answer. If 20 people need rides in vans that hold 6 each, dividing 20÷620 \div 6 gives 3 R 2. This means 3 vans are filled completely, and the remainder of 2 represents the people who need a separate car. The context determines how you use leftovers.

Example

20 members need rides in vans that hold 6. 20÷6=3 R 220 \div 6 = 3 \text{ R } 2. This means 3 vans are full and 2 members need a separate ride.
Lucius needs 18 quarts of cider, sold in 4-quart gallons. 18÷4=4 R 218 \div 4 = 4 \text{ R } 2. He must buy 5 full gallons to have enough cider.
Nina threw a shot put 28 feet. To find the yards, 28÷3=9 R 128 \div 3 = 9 \text{ R } 1. This is 9 full yards and 1 extra foot.

Explanation

Don't just write 'R 2' and walk away! That remainder could be leftover pizza slices, people needing another car, or extra feet of ribbon. Always ask what it represents!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51–60, Investigation 6

  1. Lesson 1

    Lesson 51: Adding Numbers with More Than Three Digits, Checking One-Digit Division

  2. Lesson 2

    Lesson 52: Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

  3. Lesson 3Current

    Lesson 53: One-Digit Division with a Remainder, Activity Finding Equal Groups with Remainders

  4. Lesson 4

    Lesson 54: The Calendar, Rounding Numbers to the Nearest Thousand

  5. Lesson 5

    Lesson 55: Prime and Composite Numbers, Activity Using Arrays to Find Factors

  6. Lesson 6

    Lesson 56: Using Models and Pictures to Compare Fractions, Activity Comparing Fractions

  7. Lesson 7

    Lesson 57: Rate Word Problems

  8. Lesson 8

    Lesson 58: Multiplying Three-Digit Numbers

  9. Lesson 9

    Lesson 59: Estimating Arithmetic Answers

  10. Lesson 10

    Lesson 60: Rate Problems with a Given Total

  11. Lesson 11

    Investigation 6: Displaying Data Using Graphs, Activity Displaying Information on Graphs