Learn on PengiSaxon Math, Intermediate 4Chapter 6: Lessons 51–60, Investigation 6

Lesson 52: Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

In this Grade 4 Saxon Math Intermediate 4 lesson, students practice subtracting numbers with more than three digits, including subtraction across zeros, using column-by-column regrouping. They also extend their work with equal groups word problems, learning to divide when the total is known to find either the number of groups or the number in each group. Real-world contexts such as ticket sales and fabric measurement help students apply both skills in problem-solving situations.

Section 1

📘 Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

New Concept

If we know the total, then we need to divide to find the number of groups or the number in each group.

What’s next

Next, you’ll write and solve equations for word problems, using division to find either the number of groups or the number in each group.

Section 2

Subtracting Numbers with More Than Three Digits

Property

When subtracting numbers with more than three digits, always start in the ones column. If the top digit is smaller than the bottom one, you must regroup by borrowing from the column to the left. Continue this process for the tens, hundreds, thousands, and so on, moving from right to left, even across multiple zeros to find your answer.

Example

47,2438,615=38,62847,243 - 8,615 = 38,628; 80004,582=3,4188000 - 4,582 = 3,418; 30,0001,225=28,77530,000 - 1,225 = 28,775

Explanation

Think of it like borrowing sugar from a neighbor! Start on the right side. If a column is short on value, just borrow from the next column to the left. This 'regrouping' trick makes you a subtraction master, even when you have to borrow across a line of zeros. It ensures you always have enough value to subtract.

Section 3

Finding the number of groups

Property

In 'equal groups' word problems, you use a multiplication formula: Number in each group ×\times Number of groups = Total. When you already know the total amount and the number of items that go in each individual group, you must use division. Divide the total by the number in each group to find out how many groups there are.

Example

A total of 42 stickers are sorted with 6 in each group, so there are 42÷6=742 \div 6 = 7 groups.; With 30 students total and 5 students in each car, you need 30÷5=630 \div 5 = 6 cars.; If 56 marbles are bundled into sets of 8, you will have 56÷8=756 \div 8 = 7 bundles.

Explanation

Got a big pile of stuff and need to sort it? If you know the total and how many go in each container, just divide! The total divided by the number-per-group tells you exactly how many groups you can make. It's the simplest way to organize a large amount into smaller, equal-sized sets with division.

Section 4

Finding the number in each group

Property

This is another type of 'equal groups' problem where you use the same formula: Number of groups ×\times Number in each group = Total. In these problems, you know the total number of items and how many groups they are split into. To find out how many items are in each single group, you divide the total by the number of groups.

Example

If 45 players are split into 9 teams, each team has 45÷9=545 \div 9 = 5 players.; Distributing 100 eggs into 10 cartons means each carton holds 100÷10=10100 \div 10 = 10 eggs.; Given the equation 5n=605n = 60, we solve for n by dividing: n=60÷5=12n = 60 \div 5 = 12.

Explanation

You know the total and the number of containers, but not what's inside each one? Just divide the total amount by the number of groups! This reveals the mystery number of items that belong in each individual group. It’s division to the rescue for these fair sharing puzzles, revealing the size of each share.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51–60, Investigation 6

  1. Lesson 1

    Lesson 51: Adding Numbers with More Than Three Digits, Checking One-Digit Division

  2. Lesson 2Current

    Lesson 52: Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

  3. Lesson 3

    Lesson 53: One-Digit Division with a Remainder, Activity Finding Equal Groups with Remainders

  4. Lesson 4

    Lesson 54: The Calendar, Rounding Numbers to the Nearest Thousand

  5. Lesson 5

    Lesson 55: Prime and Composite Numbers, Activity Using Arrays to Find Factors

  6. Lesson 6

    Lesson 56: Using Models and Pictures to Compare Fractions, Activity Comparing Fractions

  7. Lesson 7

    Lesson 57: Rate Word Problems

  8. Lesson 8

    Lesson 58: Multiplying Three-Digit Numbers

  9. Lesson 9

    Lesson 59: Estimating Arithmetic Answers

  10. Lesson 10

    Lesson 60: Rate Problems with a Given Total

  11. Lesson 11

    Investigation 6: Displaying Data Using Graphs, Activity Displaying Information on Graphs

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

New Concept

If we know the total, then we need to divide to find the number of groups or the number in each group.

What’s next

Next, you’ll write and solve equations for word problems, using division to find either the number of groups or the number in each group.

Section 2

Subtracting Numbers with More Than Three Digits

Property

When subtracting numbers with more than three digits, always start in the ones column. If the top digit is smaller than the bottom one, you must regroup by borrowing from the column to the left. Continue this process for the tens, hundreds, thousands, and so on, moving from right to left, even across multiple zeros to find your answer.

Example

47,2438,615=38,62847,243 - 8,615 = 38,628; 80004,582=3,4188000 - 4,582 = 3,418; 30,0001,225=28,77530,000 - 1,225 = 28,775

Explanation

Think of it like borrowing sugar from a neighbor! Start on the right side. If a column is short on value, just borrow from the next column to the left. This 'regrouping' trick makes you a subtraction master, even when you have to borrow across a line of zeros. It ensures you always have enough value to subtract.

Section 3

Finding the number of groups

Property

In 'equal groups' word problems, you use a multiplication formula: Number in each group ×\times Number of groups = Total. When you already know the total amount and the number of items that go in each individual group, you must use division. Divide the total by the number in each group to find out how many groups there are.

Example

A total of 42 stickers are sorted with 6 in each group, so there are 42÷6=742 \div 6 = 7 groups.; With 30 students total and 5 students in each car, you need 30÷5=630 \div 5 = 6 cars.; If 56 marbles are bundled into sets of 8, you will have 56÷8=756 \div 8 = 7 bundles.

Explanation

Got a big pile of stuff and need to sort it? If you know the total and how many go in each container, just divide! The total divided by the number-per-group tells you exactly how many groups you can make. It's the simplest way to organize a large amount into smaller, equal-sized sets with division.

Section 4

Finding the number in each group

Property

This is another type of 'equal groups' problem where you use the same formula: Number of groups ×\times Number in each group = Total. In these problems, you know the total number of items and how many groups they are split into. To find out how many items are in each single group, you divide the total by the number of groups.

Example

If 45 players are split into 9 teams, each team has 45÷9=545 \div 9 = 5 players.; Distributing 100 eggs into 10 cartons means each carton holds 100÷10=10100 \div 10 = 10 eggs.; Given the equation 5n=605n = 60, we solve for n by dividing: n=60÷5=12n = 60 \div 5 = 12.

Explanation

You know the total and the number of containers, but not what's inside each one? Just divide the total amount by the number of groups! This reveals the mystery number of items that belong in each individual group. It’s division to the rescue for these fair sharing puzzles, revealing the size of each share.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51–60, Investigation 6

  1. Lesson 1

    Lesson 51: Adding Numbers with More Than Three Digits, Checking One-Digit Division

  2. Lesson 2Current

    Lesson 52: Subtracting Numbers with More Than Three Digits, Word Problems About Equal Groups, Part 2

  3. Lesson 3

    Lesson 53: One-Digit Division with a Remainder, Activity Finding Equal Groups with Remainders

  4. Lesson 4

    Lesson 54: The Calendar, Rounding Numbers to the Nearest Thousand

  5. Lesson 5

    Lesson 55: Prime and Composite Numbers, Activity Using Arrays to Find Factors

  6. Lesson 6

    Lesson 56: Using Models and Pictures to Compare Fractions, Activity Comparing Fractions

  7. Lesson 7

    Lesson 57: Rate Word Problems

  8. Lesson 8

    Lesson 58: Multiplying Three-Digit Numbers

  9. Lesson 9

    Lesson 59: Estimating Arithmetic Answers

  10. Lesson 10

    Lesson 60: Rate Problems with a Given Total

  11. Lesson 11

    Investigation 6: Displaying Data Using Graphs, Activity Displaying Information on Graphs