Learn on PengiSaxon Math, Course 1Chapter 5: Number and Operations

Lesson 50: Decimal Number Line (Tenths)

In this Grade 6 Saxon Math Course 1 lesson, students learn to locate and name decimal numbers in tenths on a number line by identifying how far a point lies between consecutive whole numbers. The lesson also introduces dividing by a fraction using reciprocals, walking students through a two-step method to solve problems such as finding how many three-quarter-inch segments fit in a given length.

Section 1

πŸ“˜ Dividing by a Fraction

New Concept

To divide a number by a fraction, find the fraction's reciprocal. Then, multiply the original number by that reciprocal to find the answer.

To solve a problem like 7Γ·237 \div \frac{2}{3}:

Step 1: Find the number of 23\frac{2}{3}s in 1.

1Γ·23=321 \div \frac{2}{3} = \frac{3}{2}

Section 2

Decimal number line

Property

On a number line, the distance between consecutive whole numbers can be divided into ten equal lengths. Each length is 110\frac{1}{10} of the distance between consecutive whole numbers.

Examples

An arrow points to the eighth mark after the whole number 3, which represents 38103\frac{8}{10} or 3.8.
An arrow points to the second mark after the whole number 9, which represents 92109\frac{2}{10} or 9.2.
An arrow points to the fifth mark after the whole number 6, which represents 65106\frac{5}{10} or 6.5.

Explanation

Imagine a ruler where the space between whole numbers is chopped into 10 equal bits called tenths. Each tiny bit is worth 110\frac{1}{10}, or 0.1. So, if you start at the number 5 and hop over 4 of these tiny marks, you land on 54105\frac{4}{10}. We just write this in its cool decimal form: 5.4! It’s that simple.

Section 3

Dividing by a fraction

Property

To divide a whole number by a fraction, first find how many parts of that fraction are in 1 (its reciprocal), then multiply that result by the whole number.

Examples

To solve 8Γ·238 \div \frac{2}{3}: Step 1 is 1Γ·23=321 \div \frac{2}{3} = \frac{3}{2}. Step 2 is 8Γ—32=128 \times \frac{3}{2} = 12.
To solve 10Γ·1510 \div \frac{1}{5}: Step 1 is 1Γ·15=51 \div \frac{1}{5} = 5. Step 2 is 10Γ—5=5010 \times 5 = 50.
To solve 12Γ·3812 \div \frac{3}{8}: Step 1 is 1Γ·38=831 \div \frac{3}{8} = \frac{8}{3}. Step 2 is 12Γ—83=3212 \times \frac{8}{3} = 32.

Explanation

Dividing by a fraction sounds scary, but it’s a two-step trick! First, ask how many of the fraction fit into the number 1β€”this is just its reciprocal. Then, multiply that answer by the big number you started with. This turns a confusing division problem into a simple multiplication, making it way easier to find your answer and avoid a fraction-induced headache.

Section 4

Reciprocals

Property

Two numbers whose product is 1 are reciprocals. For example, 12Γ—2=1\frac{1}{2} \times 2 = 1, so 12\frac{1}{2} and 22 are reciprocals.

Examples

The reciprocal of 58\frac{5}{8} is 85\frac{8}{5}, because 58Γ—85=4040=1\frac{5}{8} \times \frac{8}{5} = \frac{40}{40} = 1.
The reciprocal of the whole number 7 (or 71\frac{7}{1}) is 17\frac{1}{7}, because 7Γ—17=17 \times \frac{1}{7} = 1.
The reciprocal of 110\frac{1}{10} is 10 (or 101\frac{10}{1}), because 110Γ—10=1\frac{1}{10} \times 10 = 1.

Explanation

Reciprocals are math’s dynamic duo! They are two numbers that, when multiplied, give you a perfect 1. To find a fraction's reciprocal, you just flip it upside down. For example, 25\frac{2}{5} becomes 52\frac{5}{2}. This 'flipping' trick is the secret weapon that lets you transform tricky fraction division problems into much friendlier multiplication tasks. It is very useful.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Number and Operations

  1. Lesson 1

    Lesson 41: Finding a Percent of a Number

  2. Lesson 2

    Lesson 42: Renaming Fractions by Multiplying by 1

  3. Lesson 3

    Lesson 43: Equivalent Division Problems

  4. Lesson 4

    Lesson 44: Simplifying Decimal Numbers

  5. Lesson 5

    Lesson 45: Dividing a Decimal Number by a Whole Number

  6. Lesson 6

    Lesson 46: Writing Decimal Numbers in Expanded Notation

  7. Lesson 7

    Lesson 47: Circumference

  8. Lesson 8

    Lesson 48: Subtracting Mixed Numbers with Regrouping, Part 1

  9. Lesson 9

    Lesson 49: Dividing by a Decimal Number

  10. Lesson 10Current

    Lesson 50: Decimal Number Line (Tenths)

  11. Lesson 11

    Investigation 5: Displaying Data

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Dividing by a Fraction

New Concept

To divide a number by a fraction, find the fraction's reciprocal. Then, multiply the original number by that reciprocal to find the answer.

To solve a problem like 7Γ·237 \div \frac{2}{3}:

Step 1: Find the number of 23\frac{2}{3}s in 1.

1Γ·23=321 \div \frac{2}{3} = \frac{3}{2}

Section 2

Decimal number line

Property

On a number line, the distance between consecutive whole numbers can be divided into ten equal lengths. Each length is 110\frac{1}{10} of the distance between consecutive whole numbers.

Examples

An arrow points to the eighth mark after the whole number 3, which represents 38103\frac{8}{10} or 3.8.
An arrow points to the second mark after the whole number 9, which represents 92109\frac{2}{10} or 9.2.
An arrow points to the fifth mark after the whole number 6, which represents 65106\frac{5}{10} or 6.5.

Explanation

Imagine a ruler where the space between whole numbers is chopped into 10 equal bits called tenths. Each tiny bit is worth 110\frac{1}{10}, or 0.1. So, if you start at the number 5 and hop over 4 of these tiny marks, you land on 54105\frac{4}{10}. We just write this in its cool decimal form: 5.4! It’s that simple.

Section 3

Dividing by a fraction

Property

To divide a whole number by a fraction, first find how many parts of that fraction are in 1 (its reciprocal), then multiply that result by the whole number.

Examples

To solve 8Γ·238 \div \frac{2}{3}: Step 1 is 1Γ·23=321 \div \frac{2}{3} = \frac{3}{2}. Step 2 is 8Γ—32=128 \times \frac{3}{2} = 12.
To solve 10Γ·1510 \div \frac{1}{5}: Step 1 is 1Γ·15=51 \div \frac{1}{5} = 5. Step 2 is 10Γ—5=5010 \times 5 = 50.
To solve 12Γ·3812 \div \frac{3}{8}: Step 1 is 1Γ·38=831 \div \frac{3}{8} = \frac{8}{3}. Step 2 is 12Γ—83=3212 \times \frac{8}{3} = 32.

Explanation

Dividing by a fraction sounds scary, but it’s a two-step trick! First, ask how many of the fraction fit into the number 1β€”this is just its reciprocal. Then, multiply that answer by the big number you started with. This turns a confusing division problem into a simple multiplication, making it way easier to find your answer and avoid a fraction-induced headache.

Section 4

Reciprocals

Property

Two numbers whose product is 1 are reciprocals. For example, 12Γ—2=1\frac{1}{2} \times 2 = 1, so 12\frac{1}{2} and 22 are reciprocals.

Examples

The reciprocal of 58\frac{5}{8} is 85\frac{8}{5}, because 58Γ—85=4040=1\frac{5}{8} \times \frac{8}{5} = \frac{40}{40} = 1.
The reciprocal of the whole number 7 (or 71\frac{7}{1}) is 17\frac{1}{7}, because 7Γ—17=17 \times \frac{1}{7} = 1.
The reciprocal of 110\frac{1}{10} is 10 (or 101\frac{10}{1}), because 110Γ—10=1\frac{1}{10} \times 10 = 1.

Explanation

Reciprocals are math’s dynamic duo! They are two numbers that, when multiplied, give you a perfect 1. To find a fraction's reciprocal, you just flip it upside down. For example, 25\frac{2}{5} becomes 52\frac{5}{2}. This 'flipping' trick is the secret weapon that lets you transform tricky fraction division problems into much friendlier multiplication tasks. It is very useful.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Number and Operations

  1. Lesson 1

    Lesson 41: Finding a Percent of a Number

  2. Lesson 2

    Lesson 42: Renaming Fractions by Multiplying by 1

  3. Lesson 3

    Lesson 43: Equivalent Division Problems

  4. Lesson 4

    Lesson 44: Simplifying Decimal Numbers

  5. Lesson 5

    Lesson 45: Dividing a Decimal Number by a Whole Number

  6. Lesson 6

    Lesson 46: Writing Decimal Numbers in Expanded Notation

  7. Lesson 7

    Lesson 47: Circumference

  8. Lesson 8

    Lesson 48: Subtracting Mixed Numbers with Regrouping, Part 1

  9. Lesson 9

    Lesson 49: Dividing by a Decimal Number

  10. Lesson 10Current

    Lesson 50: Decimal Number Line (Tenths)

  11. Lesson 11

    Investigation 5: Displaying Data