Learn on PengiSaxon Algebra 1Chapter 5: Inequalities and Linear Systems

Lesson 44: Finding Slope Using the Slope Formula

In this Grade 9 Saxon Algebra 1 lesson, students learn to calculate the slope of a line using the slope formula m = (y₂ − y₁) / (x₂ − x₁) with two given coordinate points. The lesson covers how to determine slope from ordered pairs, tables, and graphs, including the special cases of zero slope for horizontal lines and undefined slope for vertical lines. Students also apply slope as a rate of change to real-world problems as part of Chapter 5 on Inequalities and Linear Systems.

Section 1

📘 Finding Slope Using the Slope Formula

New Concept

A rate of change is a ratio that compares the change in one quantity with the change in another. The slope of a line represents this rate:

m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

What’s next

This lesson builds the foundation. Next, you'll apply the slope formula in worked examples, analyze data from tables, and solve real-world rate-of-change problems.

Section 2

Slope

Property

The slope mm of a line containing points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.

Examples

For points (2,4)(2, 4) and (6,6)(6, 6), the slope is m=6462=24=12m = \frac{6 - 4}{6 - 2} = \frac{2}{4} = \frac{1}{2}.
For points (4,4)(-4, 4) and (4,2)(4, -2), the slope is m=244(4)=68=34m = \frac{-2 - 4}{4 - (-4)} = \frac{-6}{8} = -\frac{3}{4}.
For points (0,5)(0, -5) and (5,10)(5, 10), the slope is m=10(5)50=155=3m = \frac{10 - (-5)}{5 - 0} = \frac{15}{5} = 3.

Explanation

Think of slope as the ultimate measure of a line's steepness, or "rise over run." This formula calculates exactly that: for every step you take horizontally (the run), it tells you how many steps you go up or down (the rise). It’s a simple way to put a number to a slant.

Section 3

Special Slopes

Property

A horizontal line has a slope of 0. The slope of a vertical line is undefined.

Examples

A horizontal line through (6,4)(-6, 4) and (6,4)(6, 4) has a slope of m=446(6)=012=0m = \frac{4 - 4}{6 - (-6)} = \frac{0}{12} = 0.
A vertical line through (7,1)(7, 1) and (7,5)(7, -5) has a slope of m=5177=60m = \frac{-5 - 1}{7 - 7} = \frac{-6}{0}, which is undefined.

Explanation

A horizontal line is perfectly flat, so it has zero rise for its run. A vertical line is like a cliff—you can't run sideways at all! Since the formula would make you divide by zero (an impossible task in math), we just call its super-steep slope "undefined."

Section 4

Rate of Change

Property

The slope of a line represents a rate of change. It's a ratio that compares the change in one quantity with the change in another.

Examples

A train travels 1320 feet in 26 seconds. The rate (speed) is 13202650.8\frac{1320}{26} \approx 50.8 feet per second.
A boa grows from 22 to 42 inches in 10 months. The rate is 422210=2\frac{42-22}{10} = 2 inches per month.

Explanation

Slope isn't just for graphs; it shows how fast something changes in real life! Think of speed in feet per second or growth in inches per month. The slope formula is the perfect tool for calculating these everyday rates when you have two data points, like a start and end measurement.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Inequalities and Linear Systems

  1. Lesson 1

    Lesson 41: Finding Rates of Change and Slope

  2. Lesson 2

    Lesson 42: Solving Percent Problems

  3. Lesson 3

    Lesson 43: Simplifying Rational Expressions

  4. Lesson 4Current

    Lesson 44: Finding Slope Using the Slope Formula

  5. Lesson 5

    Lesson 45: Translating Between Words and Inequalities

  6. Lesson 6

    Lesson 46: Simplifying Expressions with Square Roots and Higher-Order Roots

  7. Lesson 7

    Lesson 47: Solving Problems Involving the Percent of Change

  8. Lesson 8

    Lesson 48: Analyzing Measures of Central Tendency

  9. Lesson 9

    Lesson 49: Writing Equations in Slope-Intercept Form

  10. Lesson 10

    Lesson 50: Graphing Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Finding Slope Using the Slope Formula

New Concept

A rate of change is a ratio that compares the change in one quantity with the change in another. The slope of a line represents this rate:

m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}

What’s next

This lesson builds the foundation. Next, you'll apply the slope formula in worked examples, analyze data from tables, and solve real-world rate-of-change problems.

Section 2

Slope

Property

The slope mm of a line containing points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}.

Examples

For points (2,4)(2, 4) and (6,6)(6, 6), the slope is m=6462=24=12m = \frac{6 - 4}{6 - 2} = \frac{2}{4} = \frac{1}{2}.
For points (4,4)(-4, 4) and (4,2)(4, -2), the slope is m=244(4)=68=34m = \frac{-2 - 4}{4 - (-4)} = \frac{-6}{8} = -\frac{3}{4}.
For points (0,5)(0, -5) and (5,10)(5, 10), the slope is m=10(5)50=155=3m = \frac{10 - (-5)}{5 - 0} = \frac{15}{5} = 3.

Explanation

Think of slope as the ultimate measure of a line's steepness, or "rise over run." This formula calculates exactly that: for every step you take horizontally (the run), it tells you how many steps you go up or down (the rise). It’s a simple way to put a number to a slant.

Section 3

Special Slopes

Property

A horizontal line has a slope of 0. The slope of a vertical line is undefined.

Examples

A horizontal line through (6,4)(-6, 4) and (6,4)(6, 4) has a slope of m=446(6)=012=0m = \frac{4 - 4}{6 - (-6)} = \frac{0}{12} = 0.
A vertical line through (7,1)(7, 1) and (7,5)(7, -5) has a slope of m=5177=60m = \frac{-5 - 1}{7 - 7} = \frac{-6}{0}, which is undefined.

Explanation

A horizontal line is perfectly flat, so it has zero rise for its run. A vertical line is like a cliff—you can't run sideways at all! Since the formula would make you divide by zero (an impossible task in math), we just call its super-steep slope "undefined."

Section 4

Rate of Change

Property

The slope of a line represents a rate of change. It's a ratio that compares the change in one quantity with the change in another.

Examples

A train travels 1320 feet in 26 seconds. The rate (speed) is 13202650.8\frac{1320}{26} \approx 50.8 feet per second.
A boa grows from 22 to 42 inches in 10 months. The rate is 422210=2\frac{42-22}{10} = 2 inches per month.

Explanation

Slope isn't just for graphs; it shows how fast something changes in real life! Think of speed in feet per second or growth in inches per month. The slope formula is the perfect tool for calculating these everyday rates when you have two data points, like a start and end measurement.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 5: Inequalities and Linear Systems

  1. Lesson 1

    Lesson 41: Finding Rates of Change and Slope

  2. Lesson 2

    Lesson 42: Solving Percent Problems

  3. Lesson 3

    Lesson 43: Simplifying Rational Expressions

  4. Lesson 4Current

    Lesson 44: Finding Slope Using the Slope Formula

  5. Lesson 5

    Lesson 45: Translating Between Words and Inequalities

  6. Lesson 6

    Lesson 46: Simplifying Expressions with Square Roots and Higher-Order Roots

  7. Lesson 7

    Lesson 47: Solving Problems Involving the Percent of Change

  8. Lesson 8

    Lesson 48: Analyzing Measures of Central Tendency

  9. Lesson 9

    Lesson 49: Writing Equations in Slope-Intercept Form

  10. Lesson 10

    Lesson 50: Graphing Inequalities