Learn on PengiSaxon Algebra 1Chapter 4: Linear Equations and Proportions

Lesson 39: Using the Distributive Property to Simplify Rational Expressions

In this Grade 9 Saxon Algebra 1 lesson, students learn to apply the Distributive Property to simplify rational expressions, including cases involving addition, subtraction, negative exponents, and multiple operations. The lesson covers key rules such as identifying restricted values that make denominators equal to zero and eliminating negative exponents in final answers. Students work through examples from Chapter 4 on Linear Equations and Proportions, building fluency with multiplying and simplifying multi-variable rational expressions.

Section 1

πŸ“˜ Using the Distributive Property to Simplify Rational Expressions

New Concept

A rational expression is an expression with a variable in the denominator.

What’s next

Next, you'll apply the distributive property to these expressions, combining a familiar rule with a new concept to expand your problem-solving toolkit.

Section 2

Rational expression

Property

A rational expression is an expression with a variable in the denominator. A key rule is that the denominator cannot equal zero, so any variable value that causes this is not allowed.

Examples

  • In the expression 5x\frac{5}{x}, the restriction is xβ‰ 0x \neq 0.
  • For a+bcβˆ’3\frac{a+b}{c-3}, the value c=3c=3 is not allowed, so we state cβ‰ 3c \neq 3.
  • In m2k(p+2)\frac{m^2}{k(p+2)}, we have two restrictions: kβ‰ 0k \neq 0 and pβ‰ βˆ’2p \neq -2.

Explanation

Think of rational expressions as fancy fractions that have variables in them! The most important rule in their world is that you can never, ever have a zero in the denominator. It's like trying to divide a pizza among zero friendsβ€”it just doesn't make sense! So, we always point out the values that are forbidden for the variables.

Section 3

Distributing Over Addition

Property

To simplify expressions like AB(CD+EF)\frac{A}{B}\left(\frac{C}{D} + \frac{E}{F}\right), you distribute the outside term to each term inside the parentheses: Aβ‹…CBβ‹…D+Aβ‹…EBβ‹…F\frac{A \cdot C}{B \cdot D} + \frac{A \cdot E}{B \cdot F}.

Examples

  • a2b3(a3b2+2b4c)=(a2b3β‹…a3b2)+(a2b3β‹…2b4c)=a5b5+2a2bc\frac{a^2}{b^3}\left(\frac{a^3}{b^2} + \frac{2b^4}{c}\right) = \left(\frac{a^2}{b^3} \cdot \frac{a^3}{b^2}\right) + \left(\frac{a^2}{b^3} \cdot \frac{2b^4}{c}\right) = \frac{a^5}{b^5} + \frac{2a^2b}{c}
  • mn(xymkβˆ’3m2)=mβ‹…xynβ‹…mkβˆ’mβ‹…3m2n=xynkβˆ’3m3n\frac{m}{n}\left(\frac{xy}{mk} - 3m^2\right) = \frac{m \cdot xy}{n \cdot mk} - \frac{m \cdot 3m^2}{n} = \frac{xy}{nk} - \frac{3m^3}{n}

Explanation

This is like being a delivery person for math! The fraction outside the parentheses has to be delivered, or multiplied, to every single term waiting inside. After you've made all your deliveries, you just need to tidy up by using exponent rules to simplify each of the new fractions you've created. It's all about sharing the multiplication!

Section 4

Simplifying with Negative Exponents

Property

When simplifying expressions, the final answer should not contain negative exponents. Use the rules aβˆ’n=1ana^{-n} = \frac{1}{a^n} and 1aβˆ’n=an\frac{1}{a^{-n}} = a^n to fix them.

Examples

  • b2dβˆ’4(3b3dβˆ’gβˆ’2db)=3b5dβˆ’3βˆ’bgβˆ’2ddβˆ’4=3b5d3βˆ’bd5g2\frac{b^2}{d^{-4}}\left(\frac{3b^3}{d} - \frac{g^{-2}d}{b}\right) = \frac{3b^5}{d^{-3}} - \frac{b g^{-2}d}{d^{-4}} = 3b^5d^3 - \frac{bd^5}{g^2}
  • nβˆ’2m(mxcnβˆ’4+3nβˆ’1pβˆ’3)=nβˆ’2mxmcnβˆ’4+3nβˆ’3pβˆ’3m=n2xc+3mn3p3\frac{n^{-2}}{m}\left(\frac{mx}{cn^{-4}} + 3n^{-1}p^{-3}\right) = \frac{n^{-2}mx}{mcn^{-4}} + \frac{3n^{-3}p^{-3}}{m} = \frac{n^2x}{c} + \frac{3}{mn^3p^3}

Explanation

Think of a negative exponent as a sign that a term is on the wrong floor of a fraction! If a term with a negative exponent is in the numerator, move it to the denominator to make its exponent positive. If it's in the denominator, move it up to the numerator. They just need help getting to the right place!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Linear Equations and Proportions

  1. Lesson 1

    Lesson 31: Using Rates, Ratios, and Proportions

  2. Lesson 2

    Lesson 32: Simplifying and Evaluating Expressions with Integer and Zero Exponents

  3. Lesson 3

    Lesson 33: Finding the Probability of Independent and Dependent Events

  4. Lesson 4

    Lesson 34: Recognizing and Extending Arithmetic Sequences

  5. Lesson 5

    Lesson 35: Locating and Using Intercepts

  6. Lesson 6

    Lesson 36: Writing and Solving Proportions

  7. Lesson 7

    Lesson 37: Using Scientific Notation

  8. Lesson 8

    Lesson 38: Simplifying Expressions Using the GCF

  9. Lesson 9Current

    Lesson 39: Using the Distributive Property to Simplify Rational Expressions

  10. Lesson 10

    Lesson 40: Simplifying and Evaluating Expressions Using the Power Property of Exponents

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Using the Distributive Property to Simplify Rational Expressions

New Concept

A rational expression is an expression with a variable in the denominator.

What’s next

Next, you'll apply the distributive property to these expressions, combining a familiar rule with a new concept to expand your problem-solving toolkit.

Section 2

Rational expression

Property

A rational expression is an expression with a variable in the denominator. A key rule is that the denominator cannot equal zero, so any variable value that causes this is not allowed.

Examples

  • In the expression 5x\frac{5}{x}, the restriction is xβ‰ 0x \neq 0.
  • For a+bcβˆ’3\frac{a+b}{c-3}, the value c=3c=3 is not allowed, so we state cβ‰ 3c \neq 3.
  • In m2k(p+2)\frac{m^2}{k(p+2)}, we have two restrictions: kβ‰ 0k \neq 0 and pβ‰ βˆ’2p \neq -2.

Explanation

Think of rational expressions as fancy fractions that have variables in them! The most important rule in their world is that you can never, ever have a zero in the denominator. It's like trying to divide a pizza among zero friendsβ€”it just doesn't make sense! So, we always point out the values that are forbidden for the variables.

Section 3

Distributing Over Addition

Property

To simplify expressions like AB(CD+EF)\frac{A}{B}\left(\frac{C}{D} + \frac{E}{F}\right), you distribute the outside term to each term inside the parentheses: Aβ‹…CBβ‹…D+Aβ‹…EBβ‹…F\frac{A \cdot C}{B \cdot D} + \frac{A \cdot E}{B \cdot F}.

Examples

  • a2b3(a3b2+2b4c)=(a2b3β‹…a3b2)+(a2b3β‹…2b4c)=a5b5+2a2bc\frac{a^2}{b^3}\left(\frac{a^3}{b^2} + \frac{2b^4}{c}\right) = \left(\frac{a^2}{b^3} \cdot \frac{a^3}{b^2}\right) + \left(\frac{a^2}{b^3} \cdot \frac{2b^4}{c}\right) = \frac{a^5}{b^5} + \frac{2a^2b}{c}
  • mn(xymkβˆ’3m2)=mβ‹…xynβ‹…mkβˆ’mβ‹…3m2n=xynkβˆ’3m3n\frac{m}{n}\left(\frac{xy}{mk} - 3m^2\right) = \frac{m \cdot xy}{n \cdot mk} - \frac{m \cdot 3m^2}{n} = \frac{xy}{nk} - \frac{3m^3}{n}

Explanation

This is like being a delivery person for math! The fraction outside the parentheses has to be delivered, or multiplied, to every single term waiting inside. After you've made all your deliveries, you just need to tidy up by using exponent rules to simplify each of the new fractions you've created. It's all about sharing the multiplication!

Section 4

Simplifying with Negative Exponents

Property

When simplifying expressions, the final answer should not contain negative exponents. Use the rules aβˆ’n=1ana^{-n} = \frac{1}{a^n} and 1aβˆ’n=an\frac{1}{a^{-n}} = a^n to fix them.

Examples

  • b2dβˆ’4(3b3dβˆ’gβˆ’2db)=3b5dβˆ’3βˆ’bgβˆ’2ddβˆ’4=3b5d3βˆ’bd5g2\frac{b^2}{d^{-4}}\left(\frac{3b^3}{d} - \frac{g^{-2}d}{b}\right) = \frac{3b^5}{d^{-3}} - \frac{b g^{-2}d}{d^{-4}} = 3b^5d^3 - \frac{bd^5}{g^2}
  • nβˆ’2m(mxcnβˆ’4+3nβˆ’1pβˆ’3)=nβˆ’2mxmcnβˆ’4+3nβˆ’3pβˆ’3m=n2xc+3mn3p3\frac{n^{-2}}{m}\left(\frac{mx}{cn^{-4}} + 3n^{-1}p^{-3}\right) = \frac{n^{-2}mx}{mcn^{-4}} + \frac{3n^{-3}p^{-3}}{m} = \frac{n^2x}{c} + \frac{3}{mn^3p^3}

Explanation

Think of a negative exponent as a sign that a term is on the wrong floor of a fraction! If a term with a negative exponent is in the numerator, move it to the denominator to make its exponent positive. If it's in the denominator, move it up to the numerator. They just need help getting to the right place!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Linear Equations and Proportions

  1. Lesson 1

    Lesson 31: Using Rates, Ratios, and Proportions

  2. Lesson 2

    Lesson 32: Simplifying and Evaluating Expressions with Integer and Zero Exponents

  3. Lesson 3

    Lesson 33: Finding the Probability of Independent and Dependent Events

  4. Lesson 4

    Lesson 34: Recognizing and Extending Arithmetic Sequences

  5. Lesson 5

    Lesson 35: Locating and Using Intercepts

  6. Lesson 6

    Lesson 36: Writing and Solving Proportions

  7. Lesson 7

    Lesson 37: Using Scientific Notation

  8. Lesson 8

    Lesson 38: Simplifying Expressions Using the GCF

  9. Lesson 9Current

    Lesson 39: Using the Distributive Property to Simplify Rational Expressions

  10. Lesson 10

    Lesson 40: Simplifying and Evaluating Expressions Using the Power Property of Exponents