Learn on PengiSaxon Algebra 1Chapter 4: Linear Equations and Proportions

Lesson 31: Using Rates, Ratios, and Proportions

In this Grade 9 Saxon Algebra 1 lesson, students learn to distinguish between ratios, rates, and unit rates, and apply the Cross Products Property to solve proportions. The lesson covers converting rates using dimensional analysis, finding unit prices to compare values, and setting up proportions to solve real-world problems involving ratios, map scales, and distance-rate-time relationships. Part of Chapter 4 on Linear Equations and Proportions, the lesson builds foundational skills for working with proportional reasoning in algebraic contexts.

Section 1

📘 Using Rates, Ratios, and Proportions

New Concept

Algebra is built on relationships between quantities. A core example is the proportion, an equation that shows two ratios are equal.

Proportion:
The equation ab=cd\frac{a}{b} = \frac{c}{d} is a proportion.

Cross Products Property:
If ab=cd\frac{a}{b} = \frac{c}{d} and b0b \ne 0 and d0d \ne 0, then ad=bcad = bc.

What’s next

Our journey begins with this lesson on rates, ratios, and proportions. Soon, you'll use these fundamental tools to practice setting up and solving your first algebraic equations.

Section 2

Finding Unit Rates

Property

A unit rate is a rate whose denominator is 1. A unit price is the cost per unit.

Examples

Which is cheaper: 4 candy bars for 3.20 dollars or 5 for 3.50 dollars? 3.20 dollars4=0.80\frac{3.20 \text{ dollars}}{4} = 0.80 dollars per bar vs 3.50 dollars5=0.70\frac{3.50 \text{ dollars}}{5} = 0.70 dollars per bar. The 5-pack is the better buy!
A car travels 120 miles on 4 gallons of gas. The unit rate is 120 miles4 gallons=30\frac{120 \text{ miles}}{4 \text{ gallons}} = 30 miles per gallon.
You earn 45 dollars for 5 hours of work. Your unit rate is 45 dollars5 hours=9\frac{45 \text{ dollars}}{5 \text{ hours}} = 9 dollars per hour.

Explanation

Ever wondered which deal is truly better? Unit rates are your secret weapon! By finding the cost for just one item, like a can of soda, you can easily compare prices. This makes you a super-savvy shopper because you always know the cost 'per one,' which helps you spot the best value every single time.

Section 3

Converting Rates

Property

Set up the conversion factor so the units of measure cancel.

Examples

Convert 45 miles per hour to miles per minute: 45 miles1 hour1 hour60 minutes=45 miles60 minutes=0.75\frac{45 \text{ miles}}{1 \text{ hour}} \cdot \frac{1 \text{ hour}}{60 \text{ minutes}} = \frac{45 \text{ miles}}{60 \text{ minutes}} = 0.75 miles per minute.
Convert 2 gallons per minute to quarts per minute: 2 gallons1 minute4 quarts1 gallon=8 quarts1 minute\frac{2 \text{ gallons}}{1 \text{ minute}} \cdot \frac{4 \text{ quarts}}{1 \text{ gallon}} = \frac{8 \text{ quarts}}{1 \text{ minute}}.

Explanation

Need to switch from miles per hour to feet per second? That's converting rates! The trick is multiplying by a special fraction, called a conversion factor, that equals one, like 60 seconds1 minute\frac{60 \text{ seconds}}{1 \text{ minute}}. You cleverly arrange it so the old units on top and bottom cancel out, leaving you with the brand new units you want.

Section 4

Solving Proportions Using Cross Products

Property

Cross Products Property: If ab=cd\frac{a}{b} = \frac{c}{d} and b0b \ne 0 and d0d \ne 0, then ad=bcad = bc.

Examples

Solve x10=45\frac{x}{10} = \frac{4}{5}. Cross multiply to get 5x=1045 \cdot x = 10 \cdot 4, so 5x=405x = 40, which means x=8x=8.
Solve y+28=54\frac{y+2}{8} = \frac{5}{4}. Cross multiply to get 4(y+2)=854(y+2) = 8 \cdot 5. This simplifies to 4y+8=404y + 8 = 40, so 4y=324y=32 and y=8y=8.

Explanation

Think of this as the ultimate shortcut for solving proportions! Instead of guessing the missing number, you just multiply the numbers that are diagonal from each other across the equals sign. This 'cross-multiplication' trick magically turns a tricky fraction problem into a simple equation you already know how to solve. It is a powerful tool!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Linear Equations and Proportions

  1. Lesson 1Current

    Lesson 31: Using Rates, Ratios, and Proportions

  2. Lesson 2

    Lesson 32: Simplifying and Evaluating Expressions with Integer and Zero Exponents

  3. Lesson 3

    Lesson 33: Finding the Probability of Independent and Dependent Events

  4. Lesson 4

    Lesson 34: Recognizing and Extending Arithmetic Sequences

  5. Lesson 5

    Lesson 35: Locating and Using Intercepts

  6. Lesson 6

    Lesson 36: Writing and Solving Proportions

  7. Lesson 7

    Lesson 37: Using Scientific Notation

  8. Lesson 8

    Lesson 38: Simplifying Expressions Using the GCF

  9. Lesson 9

    Lesson 39: Using the Distributive Property to Simplify Rational Expressions

  10. Lesson 10

    Lesson 40: Simplifying and Evaluating Expressions Using the Power Property of Exponents

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Using Rates, Ratios, and Proportions

New Concept

Algebra is built on relationships between quantities. A core example is the proportion, an equation that shows two ratios are equal.

Proportion:
The equation ab=cd\frac{a}{b} = \frac{c}{d} is a proportion.

Cross Products Property:
If ab=cd\frac{a}{b} = \frac{c}{d} and b0b \ne 0 and d0d \ne 0, then ad=bcad = bc.

What’s next

Our journey begins with this lesson on rates, ratios, and proportions. Soon, you'll use these fundamental tools to practice setting up and solving your first algebraic equations.

Section 2

Finding Unit Rates

Property

A unit rate is a rate whose denominator is 1. A unit price is the cost per unit.

Examples

Which is cheaper: 4 candy bars for 3.20 dollars or 5 for 3.50 dollars? 3.20 dollars4=0.80\frac{3.20 \text{ dollars}}{4} = 0.80 dollars per bar vs 3.50 dollars5=0.70\frac{3.50 \text{ dollars}}{5} = 0.70 dollars per bar. The 5-pack is the better buy!
A car travels 120 miles on 4 gallons of gas. The unit rate is 120 miles4 gallons=30\frac{120 \text{ miles}}{4 \text{ gallons}} = 30 miles per gallon.
You earn 45 dollars for 5 hours of work. Your unit rate is 45 dollars5 hours=9\frac{45 \text{ dollars}}{5 \text{ hours}} = 9 dollars per hour.

Explanation

Ever wondered which deal is truly better? Unit rates are your secret weapon! By finding the cost for just one item, like a can of soda, you can easily compare prices. This makes you a super-savvy shopper because you always know the cost 'per one,' which helps you spot the best value every single time.

Section 3

Converting Rates

Property

Set up the conversion factor so the units of measure cancel.

Examples

Convert 45 miles per hour to miles per minute: 45 miles1 hour1 hour60 minutes=45 miles60 minutes=0.75\frac{45 \text{ miles}}{1 \text{ hour}} \cdot \frac{1 \text{ hour}}{60 \text{ minutes}} = \frac{45 \text{ miles}}{60 \text{ minutes}} = 0.75 miles per minute.
Convert 2 gallons per minute to quarts per minute: 2 gallons1 minute4 quarts1 gallon=8 quarts1 minute\frac{2 \text{ gallons}}{1 \text{ minute}} \cdot \frac{4 \text{ quarts}}{1 \text{ gallon}} = \frac{8 \text{ quarts}}{1 \text{ minute}}.

Explanation

Need to switch from miles per hour to feet per second? That's converting rates! The trick is multiplying by a special fraction, called a conversion factor, that equals one, like 60 seconds1 minute\frac{60 \text{ seconds}}{1 \text{ minute}}. You cleverly arrange it so the old units on top and bottom cancel out, leaving you with the brand new units you want.

Section 4

Solving Proportions Using Cross Products

Property

Cross Products Property: If ab=cd\frac{a}{b} = \frac{c}{d} and b0b \ne 0 and d0d \ne 0, then ad=bcad = bc.

Examples

Solve x10=45\frac{x}{10} = \frac{4}{5}. Cross multiply to get 5x=1045 \cdot x = 10 \cdot 4, so 5x=405x = 40, which means x=8x=8.
Solve y+28=54\frac{y+2}{8} = \frac{5}{4}. Cross multiply to get 4(y+2)=854(y+2) = 8 \cdot 5. This simplifies to 4y+8=404y + 8 = 40, so 4y=324y=32 and y=8y=8.

Explanation

Think of this as the ultimate shortcut for solving proportions! Instead of guessing the missing number, you just multiply the numbers that are diagonal from each other across the equals sign. This 'cross-multiplication' trick magically turns a tricky fraction problem into a simple equation you already know how to solve. It is a powerful tool!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Linear Equations and Proportions

  1. Lesson 1Current

    Lesson 31: Using Rates, Ratios, and Proportions

  2. Lesson 2

    Lesson 32: Simplifying and Evaluating Expressions with Integer and Zero Exponents

  3. Lesson 3

    Lesson 33: Finding the Probability of Independent and Dependent Events

  4. Lesson 4

    Lesson 34: Recognizing and Extending Arithmetic Sequences

  5. Lesson 5

    Lesson 35: Locating and Using Intercepts

  6. Lesson 6

    Lesson 36: Writing and Solving Proportions

  7. Lesson 7

    Lesson 37: Using Scientific Notation

  8. Lesson 8

    Lesson 38: Simplifying Expressions Using the GCF

  9. Lesson 9

    Lesson 39: Using the Distributive Property to Simplify Rational Expressions

  10. Lesson 10

    Lesson 40: Simplifying and Evaluating Expressions Using the Power Property of Exponents