Learn on PengiSaxon Algebra 2Chapter 3: Lessons 21-30, Investigation 3

Lesson 23: Factoring Polynomials

In Lesson 23 of Saxon Algebra 2, Grade 10 students learn how to completely factor polynomials using key strategies including factoring out the greatest common monomial factor, recognizing and factoring perfect square trinomials and the difference of two squares, and applying the Zero Product Property to solve quadratic equations. The lesson covers factoring patterns such as x² + bx + c = (x + u)(x + v), a² − 2ab + b² = (a − b)², and a² − b² = (a + b)(a − b) with worked examples throughout Chapter 3.

Section 1

📘 Factoring Polynomials

New Concept

To completely factor a polynomial of two or more terms means to express it as a product of prime polynomial factors.

Why it matters

Factoring is how we deconstruct complex expressions to reveal their simpler, fundamental components. Mastering this allows you to solve sophisticated equations, turning seemingly impossible problems into manageable steps.

What’s next

Next, you’ll learn specific patterns to factor different types of polynomials, starting with the greatest common factor.

Section 2

Greatest common monomial factor

Property: The first step in factoring any polynomial is to pull out the greatest common monomial factor (GCF). When the leading coefficient is negative, factor out the negative as well. This simplifies the remaining polynomial, making it easier to see if it can be factored further using other patterns.

Factor 4x2+8x124x^2 + 8x - 12: 4(x2+2x3)4(x^2 + 2x - 3)
Factor 6y315y-6y^3 - 15y: 3y(2y2+5)-3y(2y^2 + 5)
Factor 10a3b2+5a2b15ab10a^3b^2 + 5a^2b - 15ab: 5ab(2a2b+a3)5ab(2a^2b + a - 3)

Think of the GCF as the team captain! It's the biggest number and variable combo that's a part of every term. By pulling it out to the front, you're simplifying the team roster, making the next play (factoring) much easier to strategize. It's the essential first move to clean up the expression and see what you're really working with.

Section 3

Perfect Square Trinomial

Property: a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 and a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2. A trinomial is a perfect square if its first and last terms are perfect squares, and the middle term is exactly twice the product of their square roots. Recognizing this pattern is a major shortcut.

Factor x214x+49x^2 - 14x + 49: (x7)2(x - 7)^2
Factor 9m2+24mn+16n29m^2 + 24mn + 16n^2: (3m+4n)2(3m + 4n)^2
Factor y2+20y+100y^2 + 20y + 100: (y+10)2(y + 10)^2

Spotting a perfect square trinomial is like finding a secret passage in a video game. If you see two perfect squares at the ends (a2a^2 and b2b^2) and the middle term is just 2ab2ab (or 2ab-2ab), you can skip all the hard work and jump straight to the answer: (a+b)2(a+b)^2 or (ab)2(a-b)^2.

Section 4

Difference of Two Squares Pattern

Property

a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b). This pattern applies whenever you subtract one perfect square from another. This simple but powerful rule allows you to quickly factor expressions that have only two terms separated by a minus sign, where both terms are perfect squares. It is a fundamental pattern in algebra.

Examples

Factor x281x^2 - 81: (x+9)(x9)(x + 9)(x - 9)
Factor 16x290016x^2 - 900: (4x+30)(4x30)(4x + 30)(4x - 30)
Factor 25y24z225y^2 - 4z^2: (5y+2z)(5y2z)(5y + 2z)(5y - 2z)

Explanation

This is the 'opposites attract' of algebra! When a perfect square is fighting a another perfect square (a2b2a^2 - b^2), they break up into two nearly identical binomials but with opposite signs: (a+b)(a+b) and (ab)(a-b). When you multiply them back, the middle terms cancel out perfectly, leaving you right where you started. It's clean and simple!

Book overview

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Chapter 3: Lessons 21-30, Investigation 3

  1. Lesson 1

    Lesson 21: Solving Systems of Equations Using the Substitution Method

  2. Lesson 2

    LAB 5: Graphing Calculator: Storing and Plotting a List of Data

  3. Lesson 3

    Lesson 22: Analyzing Continuous, Discontinuous, and Discrete Functions

  4. Lesson 4Current

    Lesson 23: Factoring Polynomials

  5. Lesson 5

    Lesson 24: Solving Systems of Equations Using the Elimination Method

  6. Lesson 6

    LAB 6: Graphing Calculator: Calculating 1- and 2-Variable Statistical Data

  7. Lesson 7

    Lesson 25: Finding Measures of Central Tendency and Dispersion

  8. Lesson 8

    Lesson 26: Writing the Equation of a Line

  9. Lesson 9

    Lesson 27: Connecting the Parabola with the Quadratic Function

  10. Lesson 10

    Lesson 28: Simplifying Rational Expressions

  11. Lesson 11

    Lesson 29: Solving Systems of Equations in Three Variables

  12. Lesson 12

    Lesson 30: Applying Transformations to the Parabola and Determining the Minimum or Maximum

  13. Lesson 13

    Investigation 3: Graphing Three Linear Equations in Three Variables

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Factoring Polynomials

New Concept

To completely factor a polynomial of two or more terms means to express it as a product of prime polynomial factors.

Why it matters

Factoring is how we deconstruct complex expressions to reveal their simpler, fundamental components. Mastering this allows you to solve sophisticated equations, turning seemingly impossible problems into manageable steps.

What’s next

Next, you’ll learn specific patterns to factor different types of polynomials, starting with the greatest common factor.

Section 2

Greatest common monomial factor

Property: The first step in factoring any polynomial is to pull out the greatest common monomial factor (GCF). When the leading coefficient is negative, factor out the negative as well. This simplifies the remaining polynomial, making it easier to see if it can be factored further using other patterns.

Factor 4x2+8x124x^2 + 8x - 12: 4(x2+2x3)4(x^2 + 2x - 3)
Factor 6y315y-6y^3 - 15y: 3y(2y2+5)-3y(2y^2 + 5)
Factor 10a3b2+5a2b15ab10a^3b^2 + 5a^2b - 15ab: 5ab(2a2b+a3)5ab(2a^2b + a - 3)

Think of the GCF as the team captain! It's the biggest number and variable combo that's a part of every term. By pulling it out to the front, you're simplifying the team roster, making the next play (factoring) much easier to strategize. It's the essential first move to clean up the expression and see what you're really working with.

Section 3

Perfect Square Trinomial

Property: a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 and a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2. A trinomial is a perfect square if its first and last terms are perfect squares, and the middle term is exactly twice the product of their square roots. Recognizing this pattern is a major shortcut.

Factor x214x+49x^2 - 14x + 49: (x7)2(x - 7)^2
Factor 9m2+24mn+16n29m^2 + 24mn + 16n^2: (3m+4n)2(3m + 4n)^2
Factor y2+20y+100y^2 + 20y + 100: (y+10)2(y + 10)^2

Spotting a perfect square trinomial is like finding a secret passage in a video game. If you see two perfect squares at the ends (a2a^2 and b2b^2) and the middle term is just 2ab2ab (or 2ab-2ab), you can skip all the hard work and jump straight to the answer: (a+b)2(a+b)^2 or (ab)2(a-b)^2.

Section 4

Difference of Two Squares Pattern

Property

a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b). This pattern applies whenever you subtract one perfect square from another. This simple but powerful rule allows you to quickly factor expressions that have only two terms separated by a minus sign, where both terms are perfect squares. It is a fundamental pattern in algebra.

Examples

Factor x281x^2 - 81: (x+9)(x9)(x + 9)(x - 9)
Factor 16x290016x^2 - 900: (4x+30)(4x30)(4x + 30)(4x - 30)
Factor 25y24z225y^2 - 4z^2: (5y+2z)(5y2z)(5y + 2z)(5y - 2z)

Explanation

This is the 'opposites attract' of algebra! When a perfect square is fighting a another perfect square (a2b2a^2 - b^2), they break up into two nearly identical binomials but with opposite signs: (a+b)(a+b) and (ab)(a-b). When you multiply them back, the middle terms cancel out perfectly, leaving you right where you started. It's clean and simple!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Lessons 21-30, Investigation 3

  1. Lesson 1

    Lesson 21: Solving Systems of Equations Using the Substitution Method

  2. Lesson 2

    LAB 5: Graphing Calculator: Storing and Plotting a List of Data

  3. Lesson 3

    Lesson 22: Analyzing Continuous, Discontinuous, and Discrete Functions

  4. Lesson 4Current

    Lesson 23: Factoring Polynomials

  5. Lesson 5

    Lesson 24: Solving Systems of Equations Using the Elimination Method

  6. Lesson 6

    LAB 6: Graphing Calculator: Calculating 1- and 2-Variable Statistical Data

  7. Lesson 7

    Lesson 25: Finding Measures of Central Tendency and Dispersion

  8. Lesson 8

    Lesson 26: Writing the Equation of a Line

  9. Lesson 9

    Lesson 27: Connecting the Parabola with the Quadratic Function

  10. Lesson 10

    Lesson 28: Simplifying Rational Expressions

  11. Lesson 11

    Lesson 29: Solving Systems of Equations in Three Variables

  12. Lesson 12

    Lesson 30: Applying Transformations to the Parabola and Determining the Minimum or Maximum

  13. Lesson 13

    Investigation 3: Graphing Three Linear Equations in Three Variables