Learn on PengiSaxon Math, Course 2Chapter 4: Lessons 31-40, Investigation 4

Lessons 39: Proportions

In Saxon Math Course 2, Grade 7 students learn what a proportion is and how to solve for missing terms using cross products. The lesson teaches the two-step process of setting equal cross products and then dividing the known product by the known factor to find the unknown variable. Students apply this skill to real-world rate problems and practice solving proportions that include whole numbers and decimals.

Section 1

📘 Proportions

New Concept

A proportion is a statement that two ratios are equal. The cross products of equal ratios are equal.

What’s next

This lesson introduces the core idea of proportions. Next, you'll work through examples showing how to use cross products to find a missing value in a proportion.

Section 2

Proportion

Property

A proportion is a statement that two ratios are equal. Read 1620=45\frac{16}{20} = \frac{4}{5} as "sixteen is to twenty as four is to five."

Examples

  • Cost check: 2 apples1 dollar=10 apples5 dollars\frac{2 \text{ apples}}{1 \text{ dollar}} = \frac{10 \text{ apples}}{5 \text{ dollars}}.
  • A false proportion: 12=35\frac{1}{2} = \frac{3}{5}.
  • A true proportion: 34=912\frac{3}{4} = \frac{9}{12}.

Explanation

Proportions show balanced relationships. If 2 apples cost 1 dollar, a proportion confirms 10 apples cost 5 dollars. Things stay fair as they scale up or down!

Section 3

Cross Product

Property

Multiply the upper term of one ratio by the lower term of the other. The cross products of equal ratios are equal.

Examples

  • Check 45=810\frac{4}{5} = \frac{8}{10}: 4×10=404 \times 10 = 40 and 5×8=405 \times 8 = 40. Equal!
  • Check 23=58\frac{2}{3} = \frac{5}{8}: 2×8=162 \times 8 = 16 and 3×5=153 \times 5 = 15. Not equal!

Explanation

Think of the cross product as a super-fast trick to check if two ratios are truly equal partners. Multiply diagonally! If the answers match, it’s a valid proportion. It's a trusty lie detector for ratios.

Section 4

Solving Proportions

Property

Step 1: Find the cross products, which are equal. Step 2: Divide the known product by the known factor to find the missing term.

Examples

  • Solve 6x=35\frac{6}{x} = \frac{3}{5}: 3x=303x = 30, so x=10x=10.
  • Solve n12=23\frac{n}{12} = \frac{2}{3}: 3n=243n = 24, so n=8n=8.
  • Solve 58=10d\frac{5}{8} = \frac{10}{d}: 5d=805d = 80, so d=16d=16.

Explanation

Finding a missing number is a treasure hunt. Cross-multiplication gives you a map (20n=36020n=360), and division leads you straight to the treasure (n=18n=18). X marks the spot!

Book overview

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Chapter 4: Lessons 31-40, Investigation 4

  1. Lesson 1

    Lessons 31: Reading and Writing Decimal Numbers

  2. Lesson 2

    Lessons 32: Metric System

  3. Lesson 3

    Lessons 33: Comparing Decimals, Rounding Decimals

  4. Lesson 4

    Lessons 34: Decimal Numbers on the Number Line

  5. Lesson 5

    Lessons 35: Adding, Subtracting, Multiplying, and Dividing Decimal Numbers

  6. Lesson 6

    Lessons 36: Ratio, Sample Space

  7. Lesson 7

    Lessons 37: Area of a Triangle, Rectangular Area, Part 2

  8. Lesson 8

    Lessons 38: Interpreting Graphs

  9. Lesson 9Current

    Lessons 39: Proportions

  10. Lesson 10

    Lessons 40: Sum of the Angle Measures of a Triangle, Angle Pairs

  11. Lesson 11

    Investigation 4: Stem-and-Leaf Plots, Box-and-Whisker Plots

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Proportions

New Concept

A proportion is a statement that two ratios are equal. The cross products of equal ratios are equal.

What’s next

This lesson introduces the core idea of proportions. Next, you'll work through examples showing how to use cross products to find a missing value in a proportion.

Section 2

Proportion

Property

A proportion is a statement that two ratios are equal. Read 1620=45\frac{16}{20} = \frac{4}{5} as "sixteen is to twenty as four is to five."

Examples

  • Cost check: 2 apples1 dollar=10 apples5 dollars\frac{2 \text{ apples}}{1 \text{ dollar}} = \frac{10 \text{ apples}}{5 \text{ dollars}}.
  • A false proportion: 12=35\frac{1}{2} = \frac{3}{5}.
  • A true proportion: 34=912\frac{3}{4} = \frac{9}{12}.

Explanation

Proportions show balanced relationships. If 2 apples cost 1 dollar, a proportion confirms 10 apples cost 5 dollars. Things stay fair as they scale up or down!

Section 3

Cross Product

Property

Multiply the upper term of one ratio by the lower term of the other. The cross products of equal ratios are equal.

Examples

  • Check 45=810\frac{4}{5} = \frac{8}{10}: 4×10=404 \times 10 = 40 and 5×8=405 \times 8 = 40. Equal!
  • Check 23=58\frac{2}{3} = \frac{5}{8}: 2×8=162 \times 8 = 16 and 3×5=153 \times 5 = 15. Not equal!

Explanation

Think of the cross product as a super-fast trick to check if two ratios are truly equal partners. Multiply diagonally! If the answers match, it’s a valid proportion. It's a trusty lie detector for ratios.

Section 4

Solving Proportions

Property

Step 1: Find the cross products, which are equal. Step 2: Divide the known product by the known factor to find the missing term.

Examples

  • Solve 6x=35\frac{6}{x} = \frac{3}{5}: 3x=303x = 30, so x=10x=10.
  • Solve n12=23\frac{n}{12} = \frac{2}{3}: 3n=243n = 24, so n=8n=8.
  • Solve 58=10d\frac{5}{8} = \frac{10}{d}: 5d=805d = 80, so d=16d=16.

Explanation

Finding a missing number is a treasure hunt. Cross-multiplication gives you a map (20n=36020n=360), and division leads you straight to the treasure (n=18n=18). X marks the spot!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Lessons 31-40, Investigation 4

  1. Lesson 1

    Lessons 31: Reading and Writing Decimal Numbers

  2. Lesson 2

    Lessons 32: Metric System

  3. Lesson 3

    Lessons 33: Comparing Decimals, Rounding Decimals

  4. Lesson 4

    Lessons 34: Decimal Numbers on the Number Line

  5. Lesson 5

    Lessons 35: Adding, Subtracting, Multiplying, and Dividing Decimal Numbers

  6. Lesson 6

    Lessons 36: Ratio, Sample Space

  7. Lesson 7

    Lessons 37: Area of a Triangle, Rectangular Area, Part 2

  8. Lesson 8

    Lessons 38: Interpreting Graphs

  9. Lesson 9Current

    Lessons 39: Proportions

  10. Lesson 10

    Lessons 40: Sum of the Angle Measures of a Triangle, Angle Pairs

  11. Lesson 11

    Investigation 4: Stem-and-Leaf Plots, Box-and-Whisker Plots