Learn on PengiAoPS: Introduction to Algebra (AMC 8 & 10)Chapter 1: Follow the Rules

Lesson 6: Exponents

Grade 4 students in the AoPS Introduction to Algebra course learn how exponents work as shorthand for repeated multiplication, covering key terms like base and exponent and discovering the core laws of exponents including the product rule, power of a power rule, and negative and zero exponents. The lesson uses problems from Chapter 1 to build understanding of expressions like 3 to the 6th power and why rules such as a to the b times a to the c equals a to the b plus c hold true. Students also explore important distinctions like the difference between negative 2 to the 4th power and the quantity negative 2 to the 4th power, developing the careful reasoning needed for AMC 8 and AMC 10 competition math.

Section 1

Exponential Notation

Property

ana^n means multiply nn factors of aa.

an=aaa...aa^n = a \cdot a \cdot a \cdot ... \cdot a

(nn factors)
This is read aa to the nthn^{\text{th}} power. In the expression ana^n, the exponent tells us how many times we use the base aa as a factor.

Examples

  • 434^3 means 4444 \cdot 4 \cdot 4, which simplifies to 6464.
  • (2)4(-2)^4 means (2)(2)(2)(2)(-2)(-2)(-2)(-2), which is 1616. Be careful, as 24-2^4 means (2222)-(2 \cdot 2 \cdot 2 \cdot 2), which is 16-16.
  • (15)2(\frac{1}{5})^2 means 1515\frac{1}{5} \cdot \frac{1}{5}, resulting in 125\frac{1}{25}.

Explanation

The exponent is a counter for how many times the base number is multiplied by itself.
The base is the number being multiplied, and the exponent is the small number written up high, telling you the count.

Section 2

Evaluating Exponents with Negative Bases

Property

The placement of parentheses completely changes the meaning and the result of an expression with a negative base.
In (a)n(-a)^n, the base is a-a and the entire negative number is multiplied nn times.
In an-a^n, the base is just aa; the exponent is applied first, and then the negative sign is attached to the final result.

Examples

  • To simplify (3)2(-3)^2, the base is -3. You calculate (3)(3)=9(-3)(-3) = 9.
  • To simplify 32-3^2, the base is 3. You calculate 32=93^2 = 9 first, and then take the opposite, giving -9.
  • Evaluate k2kk^2 - k for k=6k = -6:

Substitute with parentheses: (6)2(6)=36+6=42(-6)^2 - (-6) = 36 + 6 = 42.

Explanation

Parentheses act like a protective force field! When you write (5)2(-5)^2, you're telling the math world to square the entire thing inside, negative sign and all, resulting in a positive 25. But without that force field, 52-5^2 means you only square the 5, and the negative sign just waits outside to get tacked on at the very end. Always use parentheses when substituting negative numbers!

Section 3

Zero as an Exponent

Property

a0=1a^0 = 1, if a0a \neq 0

This definition is based on the second law of exponents. For any non-zero number aa, the quotient anan\frac{a^n}{a^n} is equal to 1. Using the law of exponents, we can also write anan=ann=a0\frac{a^n}{a^n} = a^{n-n} = a^0. Therefore, it is logical to define a0a^0 as 1.

Examples

  • For a positive integer, 80=18^0 = 1.
  • For a negative integer, (55)0=1(-55)^0 = 1.
  • For an algebraic term where variables are non-zero, (2ab2)0=1(2ab^2)^0 = 1.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Follow the Rules

  1. Lesson 1

    Lesson 1: Numbers

  2. Lesson 2

    Lesson 2: Order of Operations

  3. Lesson 3

    Lesson 3: When Does Order Matter?

  4. Lesson 4

    Lesson 4: Distribution and Factoring

  5. Lesson 5

    Lesson 5: Equations

  6. Lesson 6Current

    Lesson 6: Exponents

  7. Lesson 7

    Lesson 7: Fractional Exponents

  8. Lesson 8

    Lesson 8: Radicals

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Exponential Notation

Property

ana^n means multiply nn factors of aa.

an=aaa...aa^n = a \cdot a \cdot a \cdot ... \cdot a

(nn factors)
This is read aa to the nthn^{\text{th}} power. In the expression ana^n, the exponent tells us how many times we use the base aa as a factor.

Examples

  • 434^3 means 4444 \cdot 4 \cdot 4, which simplifies to 6464.
  • (2)4(-2)^4 means (2)(2)(2)(2)(-2)(-2)(-2)(-2), which is 1616. Be careful, as 24-2^4 means (2222)-(2 \cdot 2 \cdot 2 \cdot 2), which is 16-16.
  • (15)2(\frac{1}{5})^2 means 1515\frac{1}{5} \cdot \frac{1}{5}, resulting in 125\frac{1}{25}.

Explanation

The exponent is a counter for how many times the base number is multiplied by itself.
The base is the number being multiplied, and the exponent is the small number written up high, telling you the count.

Section 2

Evaluating Exponents with Negative Bases

Property

The placement of parentheses completely changes the meaning and the result of an expression with a negative base.
In (a)n(-a)^n, the base is a-a and the entire negative number is multiplied nn times.
In an-a^n, the base is just aa; the exponent is applied first, and then the negative sign is attached to the final result.

Examples

  • To simplify (3)2(-3)^2, the base is -3. You calculate (3)(3)=9(-3)(-3) = 9.
  • To simplify 32-3^2, the base is 3. You calculate 32=93^2 = 9 first, and then take the opposite, giving -9.
  • Evaluate k2kk^2 - k for k=6k = -6:

Substitute with parentheses: (6)2(6)=36+6=42(-6)^2 - (-6) = 36 + 6 = 42.

Explanation

Parentheses act like a protective force field! When you write (5)2(-5)^2, you're telling the math world to square the entire thing inside, negative sign and all, resulting in a positive 25. But without that force field, 52-5^2 means you only square the 5, and the negative sign just waits outside to get tacked on at the very end. Always use parentheses when substituting negative numbers!

Section 3

Zero as an Exponent

Property

a0=1a^0 = 1, if a0a \neq 0

This definition is based on the second law of exponents. For any non-zero number aa, the quotient anan\frac{a^n}{a^n} is equal to 1. Using the law of exponents, we can also write anan=ann=a0\frac{a^n}{a^n} = a^{n-n} = a^0. Therefore, it is logical to define a0a^0 as 1.

Examples

  • For a positive integer, 80=18^0 = 1.
  • For a negative integer, (55)0=1(-55)^0 = 1.
  • For an algebraic term where variables are non-zero, (2ab2)0=1(2ab^2)^0 = 1.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Follow the Rules

  1. Lesson 1

    Lesson 1: Numbers

  2. Lesson 2

    Lesson 2: Order of Operations

  3. Lesson 3

    Lesson 3: When Does Order Matter?

  4. Lesson 4

    Lesson 4: Distribution and Factoring

  5. Lesson 5

    Lesson 5: Equations

  6. Lesson 6Current

    Lesson 6: Exponents

  7. Lesson 7

    Lesson 7: Fractional Exponents

  8. Lesson 8

    Lesson 8: Radicals