Learn on PengiSaxon Math, Course 3Chapter 4: Algebra • Measurement

Lesson 40: Area of a Circle

In this Grade 8 Saxon Math Course 3 lesson, students learn to calculate the area of a circle using the formula A = πr², including how to express answers in terms of π and when to use approximations such as 3.14 or 22/7. The lesson also introduces sectors and central angles, showing students how to find the area of a sector as a fractional part of the total circle area. Students explore how changes to the radius or diameter, such as doubling, affect the overall area of a circle.

Section 1

📘 Area of a Circle

New Concept

The area of a circle is π\pi times the area of a square on its radius. This relationship is expressed with the formula:

A=πr2A = \pi r^2

What’s next

This card is just the start. Next, you’ll tackle worked examples for finding the area of full circles and even parts of circles, called sectors.

Section 2

Area of a Circle

Property

The area of a circle is π\pi times the area of a square built on the radius. The formula is:

A=πr2A = \pi r^2

Examples

For a radius of 5 cm: A=π(5 cm)2=25π cm2A = \pi(5 \text{ cm})^2 = 25\pi \text{ cm}^2.
For a diameter of 6 feet, the radius is 3 feet: A=π(3 ft)23.14(9 ft2)=28.26 ft2A = \pi(3 \text{ ft})^2 \approx 3.14(9 \text{ ft}^2) = 28.26 \text{ ft}^2.

Explanation

Think of the area as being just a little more than three squares made from the circle's radius! The magic number π\pi (pi) is the special ingredient that tells us exactly how many of those squares can fit inside the circle. It’s always the same amount for any circle.

Section 3

Sector of a Circle

Property

A sector is a portion of a circle's interior enclosed by two radii and an arc. The area is a fraction of the circle's total area, determined by the central angle:

Area of sector=central angle360πr2\text{Area of sector} = \frac{\text{central angle}}{360^\circ} \cdot \pi r^2

Examples

For a 4545^\circ sector with a 4 cm radius: Area = 45360π(4 cm)2=1816π cm2=2π cm2\frac{45^\circ}{360^\circ} \cdot \pi(4 \text{ cm})^2 = \frac{1}{8} \cdot 16\pi \text{ cm}^2 = 2\pi \text{ cm}^2.
A semicircle (a 180180^\circ sector) with a 10m radius: Area = 12π(10 m)2=50π m2\frac{1}{2} \cdot \pi(10 \text{ m})^2 = 50\pi \text{ m}^2.

Explanation

Imagine a sector as a perfect slice of pizza! The angle at the pointy end tells you exactly what fraction of the whole pizza you get. A 9090^\circ angle means you get a quarter of the pie, while a 180180^\circ angle gets you a delicious half!

Book overview

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Chapter 4: Algebra • Measurement

  1. Lesson 1

    Lesson 31: Adding Integers and Collecting Like Terms

  2. Lesson 2

    Lesson 32: Probability

  3. Lesson 3

    Lesson 33: Subtracting Integers

  4. Lesson 4

    Lesson 34: Proportions and Ratio Word Problems

  5. Lesson 5

    Lesson 35: Similar and Congruent Polygons

  6. Lesson 6

    Lesson 36: Multiplying and Dividing Integers and Multiplying and Dividing Terms

  7. Lesson 7

    Lesson 37: Areas of Combined Polygons

  8. Lesson 8

    Lesson 38: Using Properties of Equality to Solve Equations

  9. Lesson 9

    Lesson 39: Circumference of a Circle

  10. Lesson 10Current

    Lesson 40: Area of a Circle

  11. Lesson 11

    Lesson 11: Investigation 4: Drawing Geometric Solids

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Area of a Circle

New Concept

The area of a circle is π\pi times the area of a square on its radius. This relationship is expressed with the formula:

A=πr2A = \pi r^2

What’s next

This card is just the start. Next, you’ll tackle worked examples for finding the area of full circles and even parts of circles, called sectors.

Section 2

Area of a Circle

Property

The area of a circle is π\pi times the area of a square built on the radius. The formula is:

A=πr2A = \pi r^2

Examples

For a radius of 5 cm: A=π(5 cm)2=25π cm2A = \pi(5 \text{ cm})^2 = 25\pi \text{ cm}^2.
For a diameter of 6 feet, the radius is 3 feet: A=π(3 ft)23.14(9 ft2)=28.26 ft2A = \pi(3 \text{ ft})^2 \approx 3.14(9 \text{ ft}^2) = 28.26 \text{ ft}^2.

Explanation

Think of the area as being just a little more than three squares made from the circle's radius! The magic number π\pi (pi) is the special ingredient that tells us exactly how many of those squares can fit inside the circle. It’s always the same amount for any circle.

Section 3

Sector of a Circle

Property

A sector is a portion of a circle's interior enclosed by two radii and an arc. The area is a fraction of the circle's total area, determined by the central angle:

Area of sector=central angle360πr2\text{Area of sector} = \frac{\text{central angle}}{360^\circ} \cdot \pi r^2

Examples

For a 4545^\circ sector with a 4 cm radius: Area = 45360π(4 cm)2=1816π cm2=2π cm2\frac{45^\circ}{360^\circ} \cdot \pi(4 \text{ cm})^2 = \frac{1}{8} \cdot 16\pi \text{ cm}^2 = 2\pi \text{ cm}^2.
A semicircle (a 180180^\circ sector) with a 10m radius: Area = 12π(10 m)2=50π m2\frac{1}{2} \cdot \pi(10 \text{ m})^2 = 50\pi \text{ m}^2.

Explanation

Imagine a sector as a perfect slice of pizza! The angle at the pointy end tells you exactly what fraction of the whole pizza you get. A 9090^\circ angle means you get a quarter of the pie, while a 180180^\circ angle gets you a delicious half!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 4: Algebra • Measurement

  1. Lesson 1

    Lesson 31: Adding Integers and Collecting Like Terms

  2. Lesson 2

    Lesson 32: Probability

  3. Lesson 3

    Lesson 33: Subtracting Integers

  4. Lesson 4

    Lesson 34: Proportions and Ratio Word Problems

  5. Lesson 5

    Lesson 35: Similar and Congruent Polygons

  6. Lesson 6

    Lesson 36: Multiplying and Dividing Integers and Multiplying and Dividing Terms

  7. Lesson 7

    Lesson 37: Areas of Combined Polygons

  8. Lesson 8

    Lesson 38: Using Properties of Equality to Solve Equations

  9. Lesson 9

    Lesson 39: Circumference of a Circle

  10. Lesson 10Current

    Lesson 40: Area of a Circle

  11. Lesson 11

    Lesson 11: Investigation 4: Drawing Geometric Solids