Learn on PengiSaxon Algebra 1Chapter 11: Advanced Topics in Algebra

Lesson 101: Solving Multi-Step Absolute-Value Inequalities

In this Grade 9 Saxon Algebra 1 lesson from Chapter 11, students learn how to solve multi-step absolute-value inequalities by first isolating the absolute-value expression and then rewriting it as a compound inequality using AND for less-than or OR for greater-than conditions. The lesson covers cases with one or two operations inside the absolute-value symbols, including division by a negative number and reversing the inequality symbol. Students also apply these skills to a real-world context, modeling acceptable ranges with absolute-value inequalities.

Section 1

πŸ“˜ Solving Multi-Step Absolute-Value Inequalities

New Concept

The expression ∣cβˆ’29.75∣|c - 29.75| represents the difference between the actual circumference and 29.75 inches.

What’s next

Next, you'll use this idea to solve multi-step inequalities and apply it to problems like defining acceptable product specifications.

Section 2

Solving Absolute-Value Inequalities

Property

First, isolate the absolute value expression. Then, rewrite it as a compound inequality. Use AND for "less than" (∣x∣<cβ†’βˆ’c<x<c|x| < c \rightarrow -c < x < c) and OR for "greater than" (∣x∣>cβ†’x<βˆ’c|x| > c \rightarrow x < -c or x>cx > c).

Explanation

Think of it like unwrapping a gift! You have to get the absolute value expression all by itself on one side before you can see the two possible solutions hidden inside. It's the most important first step, so don't rush past it. After isolating, you split the problem into two separate paths.

Examples

  • Solve 3∣x∣+5<143|x| + 5 < 14. First, isolate ∣x∣|x| to get ∣x∣<3|x| < 3. Then, unwrap it: βˆ’3<x<3-3 < x < 3.
  • Solve ∣x+2βˆ£βˆ’4>1|x+2| - 4 > 1. First, isolate the absolute value to get ∣x+2∣>5|x+2| > 5. Then, split it: x+2<βˆ’5x+2 < -5 or x+2>5x+2 > 5, which simplifies to x<βˆ’7x < -7 or x>3x > 3.
  • Solve ∣x2βˆ’1∣+6≀10|\frac{x}{2} - 1| + 6 \leq 10. Isolate to get ∣x2βˆ’1βˆ£β‰€4|\frac{x}{2} - 1| \leq 4. This becomes βˆ’4≀x2βˆ’1≀4-4 \leq \frac{x}{2} - 1 \leq 4. Solving gives βˆ’6≀x≀10-6 \leq x \leq 10.

Section 3

Dividing by a Negative Number

Property

When you multiply or divide both sides of an inequality by a negative number, you must reverse the direction of the inequality symbol.

Explanation

Dividing by a negative is like entering a "mirror world" where everything is backward! Greater than becomes less than, and less than becomes greater than. Forgetting to flip the sign is a super common mistake, so always double-check when you see that negative sign in a multiplication or division step.

Examples

  • Solve βˆ’5∣x∣+10β‰₯βˆ’15-5|x| + 10 \geq -15. Subtract 10 to get βˆ’5∣x∣β‰₯βˆ’25-5|x| \geq -25. Divide by βˆ’5-5 and FLIP the sign: ∣xβˆ£β‰€5|x| \leq 5. The final answer is βˆ’5≀x≀5-5 \leq x \leq 5.
  • Solve βˆ’2∣xβˆ’1∣>βˆ’8-2|x-1| > -8. Divide by βˆ’2-2 and FLIP the sign from >> to <<: ∣xβˆ’1∣<4|x-1| < 4. Then solve: βˆ’4<xβˆ’1<4-4 < x-1 < 4, which gives βˆ’3<x<5-3 < x < 5.

Section 4

Application: Basketball

Property

A value cc that can vary no more than some amount vv from a standard value ss is modeled by the inequality ∣cβˆ’sβˆ£β‰€v|c - s| \leq v.

Explanation

This sounds tricky, but it's just about setting a tolerance or a margin of error. The formula ∣cβˆ’29.75βˆ£β‰€0.25|c - 29.75| \leq 0.25 means the basketball's circumference (cc) can't be "off" from the ideal 29.75 inches by more than 0.25 inches. It helps keep the game fair for everyone who plays!

Examples

  • NCAA rules state a ball's circumference cc must vary no more than 0.25 inches from 29.75 inches. This is modeled by ∣cβˆ’29.75βˆ£β‰€0.25|c - 29.75| \leq 0.25, so the acceptable range is 29.5≀c≀3029.5 \leq c \leq 30 inches.
  • A ball's weight ww must vary no more than 1 ounce from 21 ounces. We write this as ∣wβˆ’21βˆ£β‰€1|w - 21| \leq 1. This means the acceptable weight is between 20 and 22 ounces, or 20≀w≀2220 \leq w \leq 22.

Book overview

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Chapter 11: Advanced Topics in Algebra

  1. Lesson 1Current

    Lesson 101: Solving Multi-Step Absolute-Value Inequalities

  2. Lesson 2

    Lesson 102: Solving Quadratic Equations Using Square Roots

  3. Lesson 3

    Lesson 103: Dividing Radical Expressions

  4. Lesson 4

    Lesson 104: Solving Quadratic Equations by Completing the Square

  5. Lesson 5

    Lesson 105: Recognizing and Extending Geometric Sequences

  6. Lesson 6

    Lesson 106: Solving Radical Equations

  7. Lesson 7

    Lesson 107: Graphing Absolute-Value Functions

  8. Lesson 8

    Lesson 108: Identifying and Graphing Exponential Functions

  9. Lesson 9

    Lesson 109: Graphing Systems of Linear Inequalities

  10. Lesson 10

    Lesson 110: Using the Quadratic Formula

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Solving Multi-Step Absolute-Value Inequalities

New Concept

The expression ∣cβˆ’29.75∣|c - 29.75| represents the difference between the actual circumference and 29.75 inches.

What’s next

Next, you'll use this idea to solve multi-step inequalities and apply it to problems like defining acceptable product specifications.

Section 2

Solving Absolute-Value Inequalities

Property

First, isolate the absolute value expression. Then, rewrite it as a compound inequality. Use AND for "less than" (∣x∣<cβ†’βˆ’c<x<c|x| < c \rightarrow -c < x < c) and OR for "greater than" (∣x∣>cβ†’x<βˆ’c|x| > c \rightarrow x < -c or x>cx > c).

Explanation

Think of it like unwrapping a gift! You have to get the absolute value expression all by itself on one side before you can see the two possible solutions hidden inside. It's the most important first step, so don't rush past it. After isolating, you split the problem into two separate paths.

Examples

  • Solve 3∣x∣+5<143|x| + 5 < 14. First, isolate ∣x∣|x| to get ∣x∣<3|x| < 3. Then, unwrap it: βˆ’3<x<3-3 < x < 3.
  • Solve ∣x+2βˆ£βˆ’4>1|x+2| - 4 > 1. First, isolate the absolute value to get ∣x+2∣>5|x+2| > 5. Then, split it: x+2<βˆ’5x+2 < -5 or x+2>5x+2 > 5, which simplifies to x<βˆ’7x < -7 or x>3x > 3.
  • Solve ∣x2βˆ’1∣+6≀10|\frac{x}{2} - 1| + 6 \leq 10. Isolate to get ∣x2βˆ’1βˆ£β‰€4|\frac{x}{2} - 1| \leq 4. This becomes βˆ’4≀x2βˆ’1≀4-4 \leq \frac{x}{2} - 1 \leq 4. Solving gives βˆ’6≀x≀10-6 \leq x \leq 10.

Section 3

Dividing by a Negative Number

Property

When you multiply or divide both sides of an inequality by a negative number, you must reverse the direction of the inequality symbol.

Explanation

Dividing by a negative is like entering a "mirror world" where everything is backward! Greater than becomes less than, and less than becomes greater than. Forgetting to flip the sign is a super common mistake, so always double-check when you see that negative sign in a multiplication or division step.

Examples

  • Solve βˆ’5∣x∣+10β‰₯βˆ’15-5|x| + 10 \geq -15. Subtract 10 to get βˆ’5∣x∣β‰₯βˆ’25-5|x| \geq -25. Divide by βˆ’5-5 and FLIP the sign: ∣xβˆ£β‰€5|x| \leq 5. The final answer is βˆ’5≀x≀5-5 \leq x \leq 5.
  • Solve βˆ’2∣xβˆ’1∣>βˆ’8-2|x-1| > -8. Divide by βˆ’2-2 and FLIP the sign from >> to <<: ∣xβˆ’1∣<4|x-1| < 4. Then solve: βˆ’4<xβˆ’1<4-4 < x-1 < 4, which gives βˆ’3<x<5-3 < x < 5.

Section 4

Application: Basketball

Property

A value cc that can vary no more than some amount vv from a standard value ss is modeled by the inequality ∣cβˆ’sβˆ£β‰€v|c - s| \leq v.

Explanation

This sounds tricky, but it's just about setting a tolerance or a margin of error. The formula ∣cβˆ’29.75βˆ£β‰€0.25|c - 29.75| \leq 0.25 means the basketball's circumference (cc) can't be "off" from the ideal 29.75 inches by more than 0.25 inches. It helps keep the game fair for everyone who plays!

Examples

  • NCAA rules state a ball's circumference cc must vary no more than 0.25 inches from 29.75 inches. This is modeled by ∣cβˆ’29.75βˆ£β‰€0.25|c - 29.75| \leq 0.25, so the acceptable range is 29.5≀c≀3029.5 \leq c \leq 30 inches.
  • A ball's weight ww must vary no more than 1 ounce from 21 ounces. We write this as ∣wβˆ’21βˆ£β‰€1|w - 21| \leq 1. This means the acceptable weight is between 20 and 22 ounces, or 20≀w≀2220 \leq w \leq 22.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 11: Advanced Topics in Algebra

  1. Lesson 1Current

    Lesson 101: Solving Multi-Step Absolute-Value Inequalities

  2. Lesson 2

    Lesson 102: Solving Quadratic Equations Using Square Roots

  3. Lesson 3

    Lesson 103: Dividing Radical Expressions

  4. Lesson 4

    Lesson 104: Solving Quadratic Equations by Completing the Square

  5. Lesson 5

    Lesson 105: Recognizing and Extending Geometric Sequences

  6. Lesson 6

    Lesson 106: Solving Radical Equations

  7. Lesson 7

    Lesson 107: Graphing Absolute-Value Functions

  8. Lesson 8

    Lesson 108: Identifying and Graphing Exponential Functions

  9. Lesson 9

    Lesson 109: Graphing Systems of Linear Inequalities

  10. Lesson 10

    Lesson 110: Using the Quadratic Formula