In this Grade 4 Eureka Math lesson from Chapter 13, students learn to solve division problems with remainders using the area model, working through examples like 37 ÷ 2 and 76 ÷ 3 by building rectangles part to whole according to place value. Students practice representing the quotient as the total length of a rectangle and identifying the leftover square units as the remainder. The lesson connects the area model to the distributive property and the standard division algorithm to reinforce conceptual understanding.
Section 1
Area Model for Division with Remainders
To solve a division problem like , we use an area model where the dividend () is the total area and the divisor () is one side length. The quotient () is the other side length, found by adding partial quotients. Any leftover area is the remainder (). The relationship is:
Section 2
Relating the Area Model to the Standard Algorithm
The standard long division algorithm is a shorthand method for recording the steps used in the area model. Each number in the algorithm corresponds to a component of the area model: the partial quotients (partial lengths), the subtracted amounts (partial areas), and the final remainder (leftover area).
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Section 1
Area Model for Division with Remainders
To solve a division problem like , we use an area model where the dividend () is the total area and the divisor () is one side length. The quotient () is the other side length, found by adding partial quotients. Any leftover area is the remainder (). The relationship is:
Section 2
Relating the Area Model to the Standard Algorithm
The standard long division algorithm is a shorthand method for recording the steps used in the area model. Each number in the algorithm corresponds to a component of the area model: the partial quotients (partial lengths), the subtracted amounts (partial areas), and the final remainder (leftover area).
Book overview
Jump across lessons in the current chapter without opening the full course modal.
Continue this chapter