Learn on PengiSaxon Math, Course 1Chapter 8: Advanced Topics in Geometry and Number Operations

Lesson 71: Parallelograms

In Saxon Math Course 1, Lesson 71 introduces Grade 6 students to key properties of parallelograms, including opposite angles being equal, adjacent angles being supplementary, and how to calculate area using the formula base times height. Students explore why this area formula works by cutting and rearranging a parallelogram into a rectangle with equivalent dimensions. The lesson also examines how a parallelogram's area changes as its angles change while its side lengths remain constant.

Section 1

📘 Parallelograms

New Concept

A parallelogram is a quadrilateral with two pairs of parallel sides. Its area is found by multiplying the base by the height, as shown in the formula:

A=bhA = bh

What’s next

This is just the foundation. Next, you'll walk through worked examples to calculate the area, perimeter, and unknown angles of different parallelograms.

Section 2

Parallelogram

Property

A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite angles are equal, and adjacent angles are supplementary (their sum is 180∘180^{\circ}).

Examples

In parallelogram WXYZWXYZ, if ∠W=75∘\angle W = 75^{\circ}, then its opposite angle ∠Y=75∘\angle Y = 75^{\circ}.
If ∠W=75∘\angle W = 75^{\circ}, its adjacent angle ∠X\angle X must be 180∘−75∘=105∘180^{\circ} - 75^{\circ} = 105^{\circ}.
If ∠C=110∘\angle C = 110^{\circ} in a parallelogram, its opposite angle is 110∘110^{\circ} and its adjacent angles are both 70∘70^{\circ}.

Explanation

Imagine a rectangle getting a playful push! The sides stay parallel, but the angles tilt. This new shape is a parallelogram. A key secret is that the corners directly across from each other always stay identical twins (equal angles). Meanwhile, any two corners next to each other have to team up to make a perfect 180∘180^{\circ}!

Section 3

Area of a Parallelogram

Property

To find the area of a parallelogram, we multiply the base by the height. The formula is A=bhA = bh, where bb is the length of one side (the base) and hh is the perpendicular distance to the opposite side (the height).

Examples

A parallelogram with a base of 10 cm and a height of 5 cm has an area of 10×5=5010 \times 5 = 50 sq. cm.
A parallelogram has a base of 8 inches and a height of 4 inches, so its area is 8 in×4 in=328 \text{ in} \times 4 \text{ in} = 32 sq. in.
If a parallelogram's area is 48 sq. meters and its base is 12 meters, the height is 48÷12=448 \div 12 = 4 meters.

Explanation

Finding a parallelogram's area seems tricky, but it's a magic trick! Just snip a triangle off one end, slide it to the other, and voilà—you’ve made a rectangle. Since you only moved a piece, the area is exactly the same! Now, just multiply the base by the height, which were the length and width of your new rectangle.

Book overview

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Chapter 8: Advanced Topics in Geometry and Number Operations

  1. Lesson 1Current

    Lesson 71: Parallelograms

  2. Lesson 2

    Lesson 72: Fractions Chart

  3. Lesson 3

    Lesson 73: Exponents

  4. Lesson 4

    Lesson 74: Writing Fractions as Decimal Numbers

  5. Lesson 5

    Lesson 75: Writing Fractions and Decimals as Percents, Part 1

  6. Lesson 6

    Lesson 76: Comparing Fractions by Converting to Decimal Form

  7. Lesson 7

    Lesson 77: Finding Unstated Information in Fraction Problems

  8. Lesson 8

    Lesson 78: Capacity

  9. Lesson 9

    Lesson 79: Area of a Triangle

  10. Lesson 10

    Lesson 80: Using a Constant Factor to Solve Ratio Problems

  11. Lesson 11

    Investigation 8: Geometric Construction of Bisectors

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Parallelograms

New Concept

A parallelogram is a quadrilateral with two pairs of parallel sides. Its area is found by multiplying the base by the height, as shown in the formula:

A=bhA = bh

What’s next

This is just the foundation. Next, you'll walk through worked examples to calculate the area, perimeter, and unknown angles of different parallelograms.

Section 2

Parallelogram

Property

A parallelogram is a quadrilateral with two pairs of parallel sides. Opposite angles are equal, and adjacent angles are supplementary (their sum is 180∘180^{\circ}).

Examples

In parallelogram WXYZWXYZ, if ∠W=75∘\angle W = 75^{\circ}, then its opposite angle ∠Y=75∘\angle Y = 75^{\circ}.
If ∠W=75∘\angle W = 75^{\circ}, its adjacent angle ∠X\angle X must be 180∘−75∘=105∘180^{\circ} - 75^{\circ} = 105^{\circ}.
If ∠C=110∘\angle C = 110^{\circ} in a parallelogram, its opposite angle is 110∘110^{\circ} and its adjacent angles are both 70∘70^{\circ}.

Explanation

Imagine a rectangle getting a playful push! The sides stay parallel, but the angles tilt. This new shape is a parallelogram. A key secret is that the corners directly across from each other always stay identical twins (equal angles). Meanwhile, any two corners next to each other have to team up to make a perfect 180∘180^{\circ}!

Section 3

Area of a Parallelogram

Property

To find the area of a parallelogram, we multiply the base by the height. The formula is A=bhA = bh, where bb is the length of one side (the base) and hh is the perpendicular distance to the opposite side (the height).

Examples

A parallelogram with a base of 10 cm and a height of 5 cm has an area of 10×5=5010 \times 5 = 50 sq. cm.
A parallelogram has a base of 8 inches and a height of 4 inches, so its area is 8 in×4 in=328 \text{ in} \times 4 \text{ in} = 32 sq. in.
If a parallelogram's area is 48 sq. meters and its base is 12 meters, the height is 48÷12=448 \div 12 = 4 meters.

Explanation

Finding a parallelogram's area seems tricky, but it's a magic trick! Just snip a triangle off one end, slide it to the other, and voilà—you’ve made a rectangle. Since you only moved a piece, the area is exactly the same! Now, just multiply the base by the height, which were the length and width of your new rectangle.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Advanced Topics in Geometry and Number Operations

  1. Lesson 1Current

    Lesson 71: Parallelograms

  2. Lesson 2

    Lesson 72: Fractions Chart

  3. Lesson 3

    Lesson 73: Exponents

  4. Lesson 4

    Lesson 74: Writing Fractions as Decimal Numbers

  5. Lesson 5

    Lesson 75: Writing Fractions and Decimals as Percents, Part 1

  6. Lesson 6

    Lesson 76: Comparing Fractions by Converting to Decimal Form

  7. Lesson 7

    Lesson 77: Finding Unstated Information in Fraction Problems

  8. Lesson 8

    Lesson 78: Capacity

  9. Lesson 9

    Lesson 79: Area of a Triangle

  10. Lesson 10

    Lesson 80: Using a Constant Factor to Solve Ratio Problems

  11. Lesson 11

    Investigation 8: Geometric Construction of Bisectors