Learn on PengiSaxon Algebra 2Chapter 6: Lessons 51-60, Investigation 6

Lesson 60: Distinguishing Between Mutually Exclusive and Independent Events

In this Grade 10 Saxon Algebra 2 lesson, students learn to distinguish between mutually exclusive (disjoint) and inclusive (overlapping) events and apply the correct probability formulas for each: P(A or B) = P(A) + P(B) for mutually exclusive events and P(A or B) = P(A) + P(B) − P(A and B) for inclusive events. Students also identify dependent versus independent events and use the multiplication rule P(A and B) = P(A) · P(B) to calculate the probability of multiple independent events occurring together. Real-world examples involving number wheels and marble jars are used to reinforce these compound probability concepts from Chapter 6, Lesson 60.

Section 1

📘 Distinguishing Between Mutually Exclusive and Independent Events

New Concept

A compound event is an event that is made up of two or more simple events.

What’s next

Next, you’ll use specific formulas to calculate the probabilities for events that are mutually exclusive, inclusive, or independent.

Section 2

Inclusive Events

For two inclusive events A and B:

P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)

A standard die is rolled. Find the probability of rolling an even number or a number greater than 3.

P(even or >3)=P(even)+P(>3)P(even and >3)=36+3626=46=23P(\text{even or >3}) = P(\text{even}) + P(>3) - P(\text{even and >3}) = \frac{3}{6} + \frac{3}{6} - \frac{2}{6} = \frac{4}{6} = \frac{2}{3}
A card is drawn from a standard 52-card deck. Find the probability of drawing a face card or a spade.
P(face or spade)=1252+1352352=2252=1126P(\text{face or spade}) = \frac{12}{52} + \frac{13}{52} - \frac{3}{52} = \frac{22}{52} = \frac{11}{26}

Imagine you're picking a card. What's the chance it's a heart OR a king? You add the probabilities, but wait! The King of Hearts got counted twice. We must subtract that overlap to be accurate. This formula is your tool to fix that double-counting problem when events share outcomes and can happen at the same time.

Section 3

Mutually Exclusive Events

For two mutually exclusive events A and B:

P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

A die is rolled. Find the probability of rolling a 2 or a 5.

P(2 or 5)=P(2)+P(5)=16+16=26=13P(2 \text{ or } 5) = P(2) + P(5) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}
A bag has 5 red and 5 blue marbles. Find the probability of picking a red marble or a blue marble.
P(red or blue)=P(red)+P(blue)=510+510=1010=1P(\text{red or blue}) = P(\text{red}) + P(\text{blue}) = \frac{5}{10} + \frac{5}{10} = \frac{10}{10} = 1

Think of it like choosing between pizza and a burger for dinner; you can't have both in a single choice! These events are totally separate and can't happen at the same time. Since there's no overlap to worry about, you simply add their probabilities together. It’s a straightforward addition, making your calculations clean and easy.

Section 4

Probability of Independent Events

For the probability of two independent events A and B:

P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B)

A coin is flipped and a die is rolled. Find the probability of getting heads and rolling a 4.

P(heads and 4)=P(heads)P(4)=1216=112P(\text{heads and 4}) = P(\text{heads}) \cdot P(4) = \frac{1}{2} \cdot \frac{1}{6} = \frac{1}{12}
A bag contains 3 red and 7 blue marbles. A marble is drawn and replaced. Find P(red then blue).
P(red then blue)=P(red)P(blue)=310710=21100P(\text{red then blue}) = P(\text{red}) \cdot P(\text{blue}) = \frac{3}{10} \cdot \frac{7}{10} = \frac{21}{100}

Imagine flipping a coin and then rolling a die. The coin doesn't care what the die does, and vice-versa! These are independent events—one doesn't affect the other's outcome. To find the chance of both happening in a sequence, you just multiply their individual probabilities. Think of it as finding a fraction of a fraction.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51-60, Investigation 6

  1. Lesson 1

    Lesson 51: Using Synthetic Division

  2. Lesson 2

    Lesson 52: Using Two Special Right Triangles

  3. Lesson 3

    Lesson 53: Performing Compositions of Functions

  4. Lesson 4

    Lesson 54: Using Linear Programming

  5. Lesson 5

    Lesson 55: Finding Probability

  6. Lesson 6

    Lesson 56: Finding Angles of Rotation

  7. Lesson 7

    Lesson 57: Finding Exponential Growth and Decay

  8. Lesson 8

    Lesson 58: Completing the Square (Exploration: Modeling Completing the Square)

  9. Lesson 9

    Lesson 59: Using Fractional Exponents

  10. Lesson 10Current

    Lesson 60: Distinguishing Between Mutually Exclusive and Independent Events

  11. Lesson 11

    Investigation 6: Deriving the Quadratic Formula

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Distinguishing Between Mutually Exclusive and Independent Events

New Concept

A compound event is an event that is made up of two or more simple events.

What’s next

Next, you’ll use specific formulas to calculate the probabilities for events that are mutually exclusive, inclusive, or independent.

Section 2

Inclusive Events

For two inclusive events A and B:

P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)

A standard die is rolled. Find the probability of rolling an even number or a number greater than 3.

P(even or >3)=P(even)+P(>3)P(even and >3)=36+3626=46=23P(\text{even or >3}) = P(\text{even}) + P(>3) - P(\text{even and >3}) = \frac{3}{6} + \frac{3}{6} - \frac{2}{6} = \frac{4}{6} = \frac{2}{3}
A card is drawn from a standard 52-card deck. Find the probability of drawing a face card or a spade.
P(face or spade)=1252+1352352=2252=1126P(\text{face or spade}) = \frac{12}{52} + \frac{13}{52} - \frac{3}{52} = \frac{22}{52} = \frac{11}{26}

Imagine you're picking a card. What's the chance it's a heart OR a king? You add the probabilities, but wait! The King of Hearts got counted twice. We must subtract that overlap to be accurate. This formula is your tool to fix that double-counting problem when events share outcomes and can happen at the same time.

Section 3

Mutually Exclusive Events

For two mutually exclusive events A and B:

P(A or B)=P(A)+P(B)P(A \text{ or } B) = P(A) + P(B)

A die is rolled. Find the probability of rolling a 2 or a 5.

P(2 or 5)=P(2)+P(5)=16+16=26=13P(2 \text{ or } 5) = P(2) + P(5) = \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}
A bag has 5 red and 5 blue marbles. Find the probability of picking a red marble or a blue marble.
P(red or blue)=P(red)+P(blue)=510+510=1010=1P(\text{red or blue}) = P(\text{red}) + P(\text{blue}) = \frac{5}{10} + \frac{5}{10} = \frac{10}{10} = 1

Think of it like choosing between pizza and a burger for dinner; you can't have both in a single choice! These events are totally separate and can't happen at the same time. Since there's no overlap to worry about, you simply add their probabilities together. It’s a straightforward addition, making your calculations clean and easy.

Section 4

Probability of Independent Events

For the probability of two independent events A and B:

P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B)

A coin is flipped and a die is rolled. Find the probability of getting heads and rolling a 4.

P(heads and 4)=P(heads)P(4)=1216=112P(\text{heads and 4}) = P(\text{heads}) \cdot P(4) = \frac{1}{2} \cdot \frac{1}{6} = \frac{1}{12}
A bag contains 3 red and 7 blue marbles. A marble is drawn and replaced. Find P(red then blue).
P(red then blue)=P(red)P(blue)=310710=21100P(\text{red then blue}) = P(\text{red}) \cdot P(\text{blue}) = \frac{3}{10} \cdot \frac{7}{10} = \frac{21}{100}

Imagine flipping a coin and then rolling a die. The coin doesn't care what the die does, and vice-versa! These are independent events—one doesn't affect the other's outcome. To find the chance of both happening in a sequence, you just multiply their individual probabilities. Think of it as finding a fraction of a fraction.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51-60, Investigation 6

  1. Lesson 1

    Lesson 51: Using Synthetic Division

  2. Lesson 2

    Lesson 52: Using Two Special Right Triangles

  3. Lesson 3

    Lesson 53: Performing Compositions of Functions

  4. Lesson 4

    Lesson 54: Using Linear Programming

  5. Lesson 5

    Lesson 55: Finding Probability

  6. Lesson 6

    Lesson 56: Finding Angles of Rotation

  7. Lesson 7

    Lesson 57: Finding Exponential Growth and Decay

  8. Lesson 8

    Lesson 58: Completing the Square (Exploration: Modeling Completing the Square)

  9. Lesson 9

    Lesson 59: Using Fractional Exponents

  10. Lesson 10Current

    Lesson 60: Distinguishing Between Mutually Exclusive and Independent Events

  11. Lesson 11

    Investigation 6: Deriving the Quadratic Formula