Learn on PengiSaxon Algebra 2Chapter 6: Lessons 51-60, Investigation 6

Lesson 55: Finding Probability

In this Grade 10 Saxon Algebra 2 lesson, students learn how to calculate theoretical probability, geometric probability, and experimental probability using ratios of favorable outcomes to total outcomes. The lesson also covers the probability of independent and dependent events, including conditional probability notation P(B|A), as well as how to express odds in favor of an event. Students apply these concepts through problems involving random integers, geometric regions, and permutations and combinations.

Section 1

📘 Finding Probability

New Concept

For equally likely outcomes, theoretical probability is the ratio of favorable to total outcomes: P(event)=number  of  favorable  outcomestotal  number  of  outcomesP(\operatorname{event}) = \frac{\operatorname{number\;of\;favorable\;outcomes}}{\operatorname{total\;number\;of\;outcomes}}.

Why it matters

Probability is the mathematical tool for quantifying uncertainty, a skill essential for strategic decision-making in fields from finance to scientific research. Mastering it allows you to model risk and predict outcomes where others only see chance.

What’s next

Next, you'll apply this definition to calculate probabilities in scenarios involving geometric shapes, combinations, and both independent and dependent events.

Section 2

Theoretical probability

For equally likely outcomes, the theoretical probability PP of an event is the ratio:

P(event)=number of favorable outcomestotal number of outcomesP(\text{event}) = \frac{\text{number of favorable outcomes}}{\text{total number of outcomes}}

Example 1: P(rolling a number > 4 on a 6-sided die)=2 (5, 6)6 (1, 2, 3, 4, 5, 6)=13P(\text{rolling a number > 4 on a 6-sided die}) = \frac{2 \text{ (5, 6)}}{6 \text{ (1, 2, 3, 4, 5, 6)}} = \frac{1}{3}.

Example 2: A random integer from 1 to 100 is chosen. P(multiple of 25)=4 (25, 50, 75, 100)100=125P(\text{multiple of 25}) = \frac{4 \text{ (25, 50, 75, 100)}}{100} = \frac{1}{25}.

Section 3

Probability of Independent and Dependent Events

For independent events A and B, P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B). For dependent events A and B, P(A and B)=P(A)P(BA)P(A \text{ and } B) = P(A) \cdot P(B|A).

Example 1 (Independent): Rolling a die and flipping a coin. P(rolling a 6 and getting heads)=1612=112P(\text{rolling a 6 and getting heads}) = \frac{1}{6} \cdot \frac{1}{2} = \frac{1}{12}.

Example 2 (Dependent): A bag has 3 green and 5 yellow marbles. P(picking green, then yellow without replacement)=3857=1556P(\text{picking green, then yellow without replacement}) = \frac{3}{8} \cdot \frac{5}{7} = \frac{15}{56}.

Section 4

Odds of an Event

Odds compare favorable outcomes to unfavorable outcomes.

odds in favor of event=number of favorable outcomesnumber of unfavorable outcomes\text{odds in favor of event} = \frac{\text{number of favorable outcomes}}{\text{number of unfavorable outcomes}}
This is often written as a ratio, such as favorable : unfavorable.

Example 1: A bag contains 4 green and 7 orange marbles. The odds in favor of picking green are 47\frac{4}{7} or 4:74:7.
Example 2: The odds in favor of an event are 3:83:8. The probability of the event is 33+8=311\frac{3}{3+8} = \frac{3}{11}.

Forget total outcomes for a second! Odds are all about a direct showdown: the chances of winning versus the chances of losing. It’s a ratio that compares your desired outcomes directly to all the other, not-so-great outcomes. This is the language of sports betting and races, focusing purely on the favorable versus the unfavorable.

Section 5

Conditional probability

Conditional probability P(BA)P(B|A) is the probability of event BB given that event AA has occurred.

Example 1: From a bag with 2 red and 6 blue marbles, P(blue|red was picked first without replacement)=67P(\text{blue|red was picked first without replacement}) = \frac{6}{7}.
Example 2: From a standard 52-card deck, P(King | Face Card)=4 Kings12 Face Cards=13P(\text{King | Face Card}) = \frac{4 \text{ Kings}}{12 \text{ Face Cards}} = \frac{1}{3}.
Example 3: When rolling a die, P(rolling a 2 | an even number was rolled)=13P(\text{rolling a 2 | an even number was rolled}) = \frac{1}{3}.

This is 'if-then' probability! It answers the question: 'What are the chances of B happening, if I already know A happened?' This new information shrinks the sample space, changing the odds. It is like asking the probability of drawing a Queen, given you already know the card you drew is a face card. It is all about updating your predictions.

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Chapter 6: Lessons 51-60, Investigation 6

  1. Lesson 1

    Lesson 51: Using Synthetic Division

  2. Lesson 2

    Lesson 52: Using Two Special Right Triangles

  3. Lesson 3

    Lesson 53: Performing Compositions of Functions

  4. Lesson 4

    Lesson 54: Using Linear Programming

  5. Lesson 5Current

    Lesson 55: Finding Probability

  6. Lesson 6

    Lesson 56: Finding Angles of Rotation

  7. Lesson 7

    Lesson 57: Finding Exponential Growth and Decay

  8. Lesson 8

    Lesson 58: Completing the Square (Exploration: Modeling Completing the Square)

  9. Lesson 9

    Lesson 59: Using Fractional Exponents

  10. Lesson 10

    Lesson 60: Distinguishing Between Mutually Exclusive and Independent Events

  11. Lesson 11

    Investigation 6: Deriving the Quadratic Formula

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

📘 Finding Probability

New Concept

For equally likely outcomes, theoretical probability is the ratio of favorable to total outcomes: P(event)=number  of  favorable  outcomestotal  number  of  outcomesP(\operatorname{event}) = \frac{\operatorname{number\;of\;favorable\;outcomes}}{\operatorname{total\;number\;of\;outcomes}}.

Why it matters

Probability is the mathematical tool for quantifying uncertainty, a skill essential for strategic decision-making in fields from finance to scientific research. Mastering it allows you to model risk and predict outcomes where others only see chance.

What’s next

Next, you'll apply this definition to calculate probabilities in scenarios involving geometric shapes, combinations, and both independent and dependent events.

Section 2

Theoretical probability

For equally likely outcomes, the theoretical probability PP of an event is the ratio:

P(event)=number of favorable outcomestotal number of outcomesP(\text{event}) = \frac{\text{number of favorable outcomes}}{\text{total number of outcomes}}

Example 1: P(rolling a number > 4 on a 6-sided die)=2 (5, 6)6 (1, 2, 3, 4, 5, 6)=13P(\text{rolling a number > 4 on a 6-sided die}) = \frac{2 \text{ (5, 6)}}{6 \text{ (1, 2, 3, 4, 5, 6)}} = \frac{1}{3}.

Example 2: A random integer from 1 to 100 is chosen. P(multiple of 25)=4 (25, 50, 75, 100)100=125P(\text{multiple of 25}) = \frac{4 \text{ (25, 50, 75, 100)}}{100} = \frac{1}{25}.

Section 3

Probability of Independent and Dependent Events

For independent events A and B, P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B). For dependent events A and B, P(A and B)=P(A)P(BA)P(A \text{ and } B) = P(A) \cdot P(B|A).

Example 1 (Independent): Rolling a die and flipping a coin. P(rolling a 6 and getting heads)=1612=112P(\text{rolling a 6 and getting heads}) = \frac{1}{6} \cdot \frac{1}{2} = \frac{1}{12}.

Example 2 (Dependent): A bag has 3 green and 5 yellow marbles. P(picking green, then yellow without replacement)=3857=1556P(\text{picking green, then yellow without replacement}) = \frac{3}{8} \cdot \frac{5}{7} = \frac{15}{56}.

Section 4

Odds of an Event

Odds compare favorable outcomes to unfavorable outcomes.

odds in favor of event=number of favorable outcomesnumber of unfavorable outcomes\text{odds in favor of event} = \frac{\text{number of favorable outcomes}}{\text{number of unfavorable outcomes}}
This is often written as a ratio, such as favorable : unfavorable.

Example 1: A bag contains 4 green and 7 orange marbles. The odds in favor of picking green are 47\frac{4}{7} or 4:74:7.
Example 2: The odds in favor of an event are 3:83:8. The probability of the event is 33+8=311\frac{3}{3+8} = \frac{3}{11}.

Forget total outcomes for a second! Odds are all about a direct showdown: the chances of winning versus the chances of losing. It’s a ratio that compares your desired outcomes directly to all the other, not-so-great outcomes. This is the language of sports betting and races, focusing purely on the favorable versus the unfavorable.

Section 5

Conditional probability

Conditional probability P(BA)P(B|A) is the probability of event BB given that event AA has occurred.

Example 1: From a bag with 2 red and 6 blue marbles, P(blue|red was picked first without replacement)=67P(\text{blue|red was picked first without replacement}) = \frac{6}{7}.
Example 2: From a standard 52-card deck, P(King | Face Card)=4 Kings12 Face Cards=13P(\text{King | Face Card}) = \frac{4 \text{ Kings}}{12 \text{ Face Cards}} = \frac{1}{3}.
Example 3: When rolling a die, P(rolling a 2 | an even number was rolled)=13P(\text{rolling a 2 | an even number was rolled}) = \frac{1}{3}.

This is 'if-then' probability! It answers the question: 'What are the chances of B happening, if I already know A happened?' This new information shrinks the sample space, changing the odds. It is like asking the probability of drawing a Queen, given you already know the card you drew is a face card. It is all about updating your predictions.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 6: Lessons 51-60, Investigation 6

  1. Lesson 1

    Lesson 51: Using Synthetic Division

  2. Lesson 2

    Lesson 52: Using Two Special Right Triangles

  3. Lesson 3

    Lesson 53: Performing Compositions of Functions

  4. Lesson 4

    Lesson 54: Using Linear Programming

  5. Lesson 5Current

    Lesson 55: Finding Probability

  6. Lesson 6

    Lesson 56: Finding Angles of Rotation

  7. Lesson 7

    Lesson 57: Finding Exponential Growth and Decay

  8. Lesson 8

    Lesson 58: Completing the Square (Exploration: Modeling Completing the Square)

  9. Lesson 9

    Lesson 59: Using Fractional Exponents

  10. Lesson 10

    Lesson 60: Distinguishing Between Mutually Exclusive and Independent Events

  11. Lesson 11

    Investigation 6: Deriving the Quadratic Formula