Learn on PengiReveal Math, Course 3Module 6: Systems of Linear Equations

Lesson 6-5: Write and Solve Systems of Equations

In this Grade 8 lesson from Reveal Math, Course 3, Module 6, students learn how to translate real-world scenarios into systems of linear equations and solve them using graphing, substitution, or elimination. The lesson walks through identifying variables, writing algebraic equations from verbal models, and choosing the most efficient solution method for a given system. Students practice interpreting solutions in context, such as finding unknown costs or determining when two pricing plans are equal.

Section 1

Review: Strategy for Solving Word Problems with Two Unknowns

Property

To solve word problems with two unknown quantities, translate the sentences into a system of linear equations. Follow this problem-solving strategy:
Step 1. Read the problem. Make sure all the words and ideas are understood.
Step 2. Identify what we are looking for.
Step 3. Name what we are looking for. Choose variables to represent those quantities.
Step 4. Translate into a system of equations.
Step 5. Solve the system of equations using good algebra techniques.
Step 6. Check the answer in the problem and make sure it makes sense.
Step 7. Answer the question with a complete sentence.

Examples

  • The sum of two numbers is 25. One number is 5 more than the other. Find them. Let the numbers be xx and yy. The system is {x+y=25x=y+5\begin{cases} x+y=25 \\ x=y+5 \end{cases}. Substituting gives (y+5)+y=25(y+5)+y=25, so 2y=202y=20 and y=10y=10. Then x=10+5=15x=10+5=15. The numbers are 10 and 15.
  • The perimeter of a rectangle is 40 inches. The length is 4 inches less than twice the width. Find the dimensions. Let LL be length and WW be width. The system is {2L+2W=40L=2W4\begin{cases} 2L+2W=40 \\ L=2W-4 \end{cases}. Substituting gives 2(2W4)+2W=402(2W-4)+2W=40, so 6W8=406W-8=40, 6W=486W=48, and W=8W=8. Then L=2(8)4=12L=2(8)-4=12. The length is 12 inches and the width is 8 inches.

Section 2

Choosing the Most Efficient Method to Solve a System of Equations

Property

The most efficient method for solving a system of linear equations depends on the initial form of the given equations:

  • Graphing: Best when both equations are in slope-intercept form (y=mx+by = mx + b) or when a visual estimate is needed.
  • Substitution: Best when at least one equation has an isolated variable (e.g., x = ... or y = ...) or a variable with a coefficient of 1 or -1.
  • Elimination: Best when both equations are in standard form (Ax+By=CAx + By = C), especially if a pair of variables has the same or opposite coefficients.

Examples

  • Graphing: For the system y=2x+4y = 2x + 4 and y=x+1y = -x + 1, graphing is efficient because both equations are in slope-intercept form and can be easily plotted.
  • Substitution: For the system y=3x2y = 3x - 2 and 4x+2y=164x + 2y = 16, substitution is most efficient because y is already isolated in the first equation.
  • Elimination: For the system 5x2y=105x - 2y = 10 and 3x+2y=143x + 2y = 14, elimination is most efficient because both equations are in standard form and the y-terms (-2y and 2y) are opposites that will immediately cancel.

Explanation

While any system of linear equations can be solved using graphing, substitution, or elimination, choosing the most efficient method saves time and reduces the chance of calculation errors. By analyzing the initial format of the equations, you can determine the quickest path to the solution.

Book overview

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Module 6: Systems of Linear Equations

  1. Lesson 1

    Lesson 6-1: Solve Systems of Equations by Graphing

  2. Lesson 2

    Lesson 6-2: Determine Number of Solutions

  3. Lesson 3

    Lesson 6-3: Solve Systems of Equations by Substitution

  4. Lesson 4

    Lesson 6-4: Solve Systems of Equations by Elimination

  5. Lesson 5Current

    Lesson 6-5: Write and Solve Systems of Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Review: Strategy for Solving Word Problems with Two Unknowns

Property

To solve word problems with two unknown quantities, translate the sentences into a system of linear equations. Follow this problem-solving strategy:
Step 1. Read the problem. Make sure all the words and ideas are understood.
Step 2. Identify what we are looking for.
Step 3. Name what we are looking for. Choose variables to represent those quantities.
Step 4. Translate into a system of equations.
Step 5. Solve the system of equations using good algebra techniques.
Step 6. Check the answer in the problem and make sure it makes sense.
Step 7. Answer the question with a complete sentence.

Examples

  • The sum of two numbers is 25. One number is 5 more than the other. Find them. Let the numbers be xx and yy. The system is {x+y=25x=y+5\begin{cases} x+y=25 \\ x=y+5 \end{cases}. Substituting gives (y+5)+y=25(y+5)+y=25, so 2y=202y=20 and y=10y=10. Then x=10+5=15x=10+5=15. The numbers are 10 and 15.
  • The perimeter of a rectangle is 40 inches. The length is 4 inches less than twice the width. Find the dimensions. Let LL be length and WW be width. The system is {2L+2W=40L=2W4\begin{cases} 2L+2W=40 \\ L=2W-4 \end{cases}. Substituting gives 2(2W4)+2W=402(2W-4)+2W=40, so 6W8=406W-8=40, 6W=486W=48, and W=8W=8. Then L=2(8)4=12L=2(8)-4=12. The length is 12 inches and the width is 8 inches.

Section 2

Choosing the Most Efficient Method to Solve a System of Equations

Property

The most efficient method for solving a system of linear equations depends on the initial form of the given equations:

  • Graphing: Best when both equations are in slope-intercept form (y=mx+by = mx + b) or when a visual estimate is needed.
  • Substitution: Best when at least one equation has an isolated variable (e.g., x = ... or y = ...) or a variable with a coefficient of 1 or -1.
  • Elimination: Best when both equations are in standard form (Ax+By=CAx + By = C), especially if a pair of variables has the same or opposite coefficients.

Examples

  • Graphing: For the system y=2x+4y = 2x + 4 and y=x+1y = -x + 1, graphing is efficient because both equations are in slope-intercept form and can be easily plotted.
  • Substitution: For the system y=3x2y = 3x - 2 and 4x+2y=164x + 2y = 16, substitution is most efficient because y is already isolated in the first equation.
  • Elimination: For the system 5x2y=105x - 2y = 10 and 3x+2y=143x + 2y = 14, elimination is most efficient because both equations are in standard form and the y-terms (-2y and 2y) are opposites that will immediately cancel.

Explanation

While any system of linear equations can be solved using graphing, substitution, or elimination, choosing the most efficient method saves time and reduces the chance of calculation errors. By analyzing the initial format of the equations, you can determine the quickest path to the solution.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Module 6: Systems of Linear Equations

  1. Lesson 1

    Lesson 6-1: Solve Systems of Equations by Graphing

  2. Lesson 2

    Lesson 6-2: Determine Number of Solutions

  3. Lesson 3

    Lesson 6-3: Solve Systems of Equations by Substitution

  4. Lesson 4

    Lesson 6-4: Solve Systems of Equations by Elimination

  5. Lesson 5Current

    Lesson 6-5: Write and Solve Systems of Equations