Learn on PengiYoshiwara Elementary AlgebraChapter 3: Graphs of Linear Equations

Lesson 4: Slope-Intercept Form

New Concept The slope intercept form, $y = mx + b$, is a powerful way to write linear equations. It instantly reveals a line's slope ($m$) and its $y$ intercept ($b$), making it simple to graph and interpret real world relationships.

Section 1

πŸ“˜ Slope-Intercept Form

New Concept

The slope-intercept form, y=mx+by = mx + b, is a powerful way to write linear equations. It instantly reveals a line's slope (mm) and its yy-intercept (bb), making it simple to graph and interpret real-world relationships.

What’s next

Now, let's put this into action. You'll work through interactive examples to identify the slope and intercept, then tackle graphing challenges.

Section 2

Coefficients of a linear equation

Property

  1. The constant term tells us the vertical intercept of the graph.
  2. The coefficient of the input variable tells us the slope of the graph.

Examples

  • In the equation for oven temperature, H=0.4t+70H = 0.4t + 70, the slope is 0.40.4 (temperature rise per minute) and the yy-intercept is 7070 (the starting temperature).
  • For a taxi fare modeled by C=2.50+1.50dC = 2.50 + 1.50d, the slope is 1.501.50 (cost per mile) and the yy-intercept is 2.502.50 (the initial fee).
  • If your phone plan is P=20+5gP = 20 + 5g, the slope is 55 (cost per gigabyte) and the yy-intercept is 2020 (the base monthly charge).

Explanation

Think of an equation's numbers as clues. The coefficient of the variable reveals the line's steepness (slope), while the constant term shows exactly where the line starts on the vertical axis (y-intercept).

Section 3

Slope-intercept form

Property

A linear equation written in the form

y=mx+by = mx + b

is said to be in slope-intercept form. The coefficient mm is the slope of the graph, and bb is the yy-intercept.

Examples

  • The equation y=3x+5y = 3x + 5 is in slope-intercept form. The slope is 33 and the yy-intercept is (0,5)(0, 5).
  • For y=βˆ’2xβˆ’1y = -2x - 1, the slope is βˆ’2-2 and the yy-intercept is (0,βˆ’1)(0, -1).
  • In the equation y=12x+4y = \frac{1}{2}x + 4, the slope is 12\frac{1}{2} and the yy-intercept is (0,4)(0, 4).

Explanation

This form is a recipe for drawing a line. The 'bb' tells you your starting point on the y-axis, and the 'mm' (slope) gives you directions on how steep to draw the line from there.

Section 4

Graph using the slope-intercept method

Property

To Graph a Line Using the Slope-Intercept Method:

  1. Write the equation in the form y=mx+by = mx + b.
  2. Plot the yy-intercept, (0,b)(0, b).
  3. Write the slope as a fraction, m=Ξ”yΞ”xm = \frac{\Delta y}{\Delta x}.
  4. Use the slope to find a second point on the graph: Starting at the yy-intercept, move Ξ”y\Delta y units in the yy-direction, then Ξ”x\Delta x units in the xx-direction.
  5. Find a third point by moving βˆ’Ξ”y-\Delta y units in the yy-direction, then βˆ’Ξ”x-\Delta x units in the xx-direction, starting from the yy-intercept.
  6. Draw a line through the three plotted points.

Examples

  • To graph y=23x+1y = \frac{2}{3}x + 1, first plot the yy-intercept at (0,1)(0, 1). From there, use the slope to move up 2 units and right 3 units to find a second point at (3,3)(3, 3).
  • For y=βˆ’3x+5y = -3x + 5, start by plotting (0,5)(0, 5). Write the slope as βˆ’31\frac{-3}{1}, then move down 3 units and right 1 unit to find the point (1,2)(1, 2).
  • To graph y=52xβˆ’3y = \frac{5}{2}x - 3, plot the intercept at (0,βˆ’3)(0, -3). From that point, move up 5 units and right 2 units to locate a second point at (2,2)(2, 2).

Explanation

This method is like a treasure map for graphing. Start at 'X marks the spot' on the y-axis (the intercept, bb), then follow the slope's 'rise over run' directions to find your next point and draw the line.

Section 5

Finding the slope-intercept form

Property

We can write the equation of any non-vertical line in slope-intercept form by solving the equation for yy in terms of xx.

Caution: Do not confuse solving for yy with finding the yy-intercept. When we 'solve for yy', we are writing the equation in another form, so both variables, xx and yy, still appear in the equation.

Examples

  • To convert 6x+3y=126x + 3y = 12, subtract 6x6x from both sides to get 3y=βˆ’6x+123y = -6x + 12. Then divide all terms by 33 to get the final form y=βˆ’2x+4y = -2x + 4.
  • For the equation 5xβˆ’2y=105x - 2y = 10, subtract 5x5x to get βˆ’2y=βˆ’5x+10-2y = -5x + 10. Divide everything by βˆ’2-2 to find the slope-intercept form, y=52xβˆ’5y = \frac{5}{2}x - 5.
  • To solve x+4y=8x + 4y = 8 for yy, subtract xx from both sides giving 4y=βˆ’x+84y = -x + 8. Then divide by 44 to get y=βˆ’14x+2y = -\frac{1}{4}x + 2.

Book overview

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Chapter 3: Graphs of Linear Equations

  1. Lesson 1

    Lesson 1: Intercepts

  2. Lesson 2

    Lesson 2: Ratio and Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4Current

    Lesson 4: Slope-Intercept Form

  5. Lesson 5

    Lesson 5: Properties of Lines

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ Slope-Intercept Form

New Concept

The slope-intercept form, y=mx+by = mx + b, is a powerful way to write linear equations. It instantly reveals a line's slope (mm) and its yy-intercept (bb), making it simple to graph and interpret real-world relationships.

What’s next

Now, let's put this into action. You'll work through interactive examples to identify the slope and intercept, then tackle graphing challenges.

Section 2

Coefficients of a linear equation

Property

  1. The constant term tells us the vertical intercept of the graph.
  2. The coefficient of the input variable tells us the slope of the graph.

Examples

  • In the equation for oven temperature, H=0.4t+70H = 0.4t + 70, the slope is 0.40.4 (temperature rise per minute) and the yy-intercept is 7070 (the starting temperature).
  • For a taxi fare modeled by C=2.50+1.50dC = 2.50 + 1.50d, the slope is 1.501.50 (cost per mile) and the yy-intercept is 2.502.50 (the initial fee).
  • If your phone plan is P=20+5gP = 20 + 5g, the slope is 55 (cost per gigabyte) and the yy-intercept is 2020 (the base monthly charge).

Explanation

Think of an equation's numbers as clues. The coefficient of the variable reveals the line's steepness (slope), while the constant term shows exactly where the line starts on the vertical axis (y-intercept).

Section 3

Slope-intercept form

Property

A linear equation written in the form

y=mx+by = mx + b

is said to be in slope-intercept form. The coefficient mm is the slope of the graph, and bb is the yy-intercept.

Examples

  • The equation y=3x+5y = 3x + 5 is in slope-intercept form. The slope is 33 and the yy-intercept is (0,5)(0, 5).
  • For y=βˆ’2xβˆ’1y = -2x - 1, the slope is βˆ’2-2 and the yy-intercept is (0,βˆ’1)(0, -1).
  • In the equation y=12x+4y = \frac{1}{2}x + 4, the slope is 12\frac{1}{2} and the yy-intercept is (0,4)(0, 4).

Explanation

This form is a recipe for drawing a line. The 'bb' tells you your starting point on the y-axis, and the 'mm' (slope) gives you directions on how steep to draw the line from there.

Section 4

Graph using the slope-intercept method

Property

To Graph a Line Using the Slope-Intercept Method:

  1. Write the equation in the form y=mx+by = mx + b.
  2. Plot the yy-intercept, (0,b)(0, b).
  3. Write the slope as a fraction, m=Ξ”yΞ”xm = \frac{\Delta y}{\Delta x}.
  4. Use the slope to find a second point on the graph: Starting at the yy-intercept, move Ξ”y\Delta y units in the yy-direction, then Ξ”x\Delta x units in the xx-direction.
  5. Find a third point by moving βˆ’Ξ”y-\Delta y units in the yy-direction, then βˆ’Ξ”x-\Delta x units in the xx-direction, starting from the yy-intercept.
  6. Draw a line through the three plotted points.

Examples

  • To graph y=23x+1y = \frac{2}{3}x + 1, first plot the yy-intercept at (0,1)(0, 1). From there, use the slope to move up 2 units and right 3 units to find a second point at (3,3)(3, 3).
  • For y=βˆ’3x+5y = -3x + 5, start by plotting (0,5)(0, 5). Write the slope as βˆ’31\frac{-3}{1}, then move down 3 units and right 1 unit to find the point (1,2)(1, 2).
  • To graph y=52xβˆ’3y = \frac{5}{2}x - 3, plot the intercept at (0,βˆ’3)(0, -3). From that point, move up 5 units and right 2 units to locate a second point at (2,2)(2, 2).

Explanation

This method is like a treasure map for graphing. Start at 'X marks the spot' on the y-axis (the intercept, bb), then follow the slope's 'rise over run' directions to find your next point and draw the line.

Section 5

Finding the slope-intercept form

Property

We can write the equation of any non-vertical line in slope-intercept form by solving the equation for yy in terms of xx.

Caution: Do not confuse solving for yy with finding the yy-intercept. When we 'solve for yy', we are writing the equation in another form, so both variables, xx and yy, still appear in the equation.

Examples

  • To convert 6x+3y=126x + 3y = 12, subtract 6x6x from both sides to get 3y=βˆ’6x+123y = -6x + 12. Then divide all terms by 33 to get the final form y=βˆ’2x+4y = -2x + 4.
  • For the equation 5xβˆ’2y=105x - 2y = 10, subtract 5x5x to get βˆ’2y=βˆ’5x+10-2y = -5x + 10. Divide everything by βˆ’2-2 to find the slope-intercept form, y=52xβˆ’5y = \frac{5}{2}x - 5.
  • To solve x+4y=8x + 4y = 8 for yy, subtract xx from both sides giving 4y=βˆ’x+84y = -x + 8. Then divide by 44 to get y=βˆ’14x+2y = -\frac{1}{4}x + 2.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Graphs of Linear Equations

  1. Lesson 1

    Lesson 1: Intercepts

  2. Lesson 2

    Lesson 2: Ratio and Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4Current

    Lesson 4: Slope-Intercept Form

  5. Lesson 5

    Lesson 5: Properties of Lines