Learn on PengiYoshiwara Elementary AlgebraChapter 3: Graphs of Linear Equations

Lesson 1: Intercepts

New Concept Intercepts are the points where a line's graph crosses the axes. We'll find them algebraically by setting $x=0$ or $y=0$ in an equation. This powerful skill lets you quickly graph lines and understand their real world meaning.

Section 1

πŸ“˜ Intercepts

New Concept

Intercepts are the points where a line's graph crosses the axes. We'll find them algebraically by setting x=0x=0 or y=0y=0 in an equation. This powerful skill lets you quickly graph lines and understand their real-world meaning.

What’s next

This is just the foundation. Next, you’ll master this concept through interactive examples, practice graphing with the intercept method, and solve challenge problems.

Section 2

Intercepts of a line

Property

The intercepts of a line are the points where the graph crosses the axes. Because the yy-intercept of a graph lies on the yy-axis, its xx-coordinate must be zero. And because the xx-intercept lies on the xx-axis, its yy-coordinate must be zero.

Examples

  • A line crosses the x-axis at (5,0)(5, 0) and the y-axis at (0,βˆ’2)(0, -2). The x-intercept is (5,0)(5, 0) and the y-intercept is $(0, -2).
  • For the line y=x+3y = x + 3, the graph intersects the y-axis at (0,3)(0, 3) and the x-axis at (βˆ’3,0)(-3, 0). These are its intercepts.

Section 3

Finding intercepts of a graph

Property

To find the xx-intercept of a graph: Substitute 00 for yy in the equation and solve for xx. To find the yy-intercept of a graph: Substitute 00 for xx in the equation and solve for yy.

Examples

  • To find the intercepts of y=4xβˆ’8y = 4x - 8: for the y-intercept, set x=0x=0 to get y=βˆ’8y = -8, so it's (0,βˆ’8)(0, -8). For the x-intercept, set y=0y=0 to get 0=4xβˆ’80 = 4x - 8, which means x=2x=2, so it's (2,0)(2, 0).
  • To find the intercepts of 3x+5y=153x + 5y = 15: for the y-intercept, set x=0x=0 to get 5y=155y = 15, which means y=3y=3, so it's (0,3)(0, 3). For the x-intercept, set y=0y=0 to get 3x=153x = 15, which means x=5x=5, so it's (5,0)(5, 0).

Section 4

The intercept method of graphing

Property

To Graph a Linear Equation Using the Intercept Method.

  1. Find the xx- and yy-intercepts of the graph.
  2. Draw the line through the two intercepts.
  3. Find a third point on the graph as a check. (Choose any convenient value for xx and solve for yy.)

Examples

  • To graph xβˆ’2y=6x - 2y = 6, find the intercepts. Setting x=0x=0 gives y=βˆ’3y=-3, so (0,βˆ’3)(0, -3). Setting y=0y=0 gives x=6x=6, so (6,0)(6, 0). Plot these two points and draw a line through them.
  • To graph 4x+3y=124x + 3y = 12, find the intercepts. Setting x=0x=0 gives y=4y=4, so (0,4)(0, 4). Setting y=0y=0 gives x=3x=3, so (3,0)(3, 0). Plot (0,4)(0, 4) and (3,0)(3, 0) and connect them with a line.

Section 5

Interpreting the intercepts

Property

The intercepts of a graph give us valuable information about a problem. They often represent the starting or ending values for a particular variable.

Examples

  • A phone's battery percentage is modeled by P=100βˆ’5hP = 100 - 5h. The P-intercept (0,100)(0, 100) means the battery starts at 100%. The h-intercept (20,0)(20, 0) means the battery will be dead after 20 hours.
  • The value of a car is V=20000βˆ’2500yV = 20000 - 2500y. The V-intercept (0,20000)(0, 20000) is the initial price of the car (20000 dollars). The y-intercept (8,0)(8, 0) means the car will be worth 0 dollars after 8 years.

Book overview

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Chapter 3: Graphs of Linear Equations

  1. Lesson 1Current

    Lesson 1: Intercepts

  2. Lesson 2

    Lesson 2: Ratio and Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4

    Lesson 4: Slope-Intercept Form

  5. Lesson 5

    Lesson 5: Properties of Lines

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

πŸ“˜ Intercepts

New Concept

Intercepts are the points where a line's graph crosses the axes. We'll find them algebraically by setting x=0x=0 or y=0y=0 in an equation. This powerful skill lets you quickly graph lines and understand their real-world meaning.

What’s next

This is just the foundation. Next, you’ll master this concept through interactive examples, practice graphing with the intercept method, and solve challenge problems.

Section 2

Intercepts of a line

Property

The intercepts of a line are the points where the graph crosses the axes. Because the yy-intercept of a graph lies on the yy-axis, its xx-coordinate must be zero. And because the xx-intercept lies on the xx-axis, its yy-coordinate must be zero.

Examples

  • A line crosses the x-axis at (5,0)(5, 0) and the y-axis at (0,βˆ’2)(0, -2). The x-intercept is (5,0)(5, 0) and the y-intercept is $(0, -2).
  • For the line y=x+3y = x + 3, the graph intersects the y-axis at (0,3)(0, 3) and the x-axis at (βˆ’3,0)(-3, 0). These are its intercepts.

Section 3

Finding intercepts of a graph

Property

To find the xx-intercept of a graph: Substitute 00 for yy in the equation and solve for xx. To find the yy-intercept of a graph: Substitute 00 for xx in the equation and solve for yy.

Examples

  • To find the intercepts of y=4xβˆ’8y = 4x - 8: for the y-intercept, set x=0x=0 to get y=βˆ’8y = -8, so it's (0,βˆ’8)(0, -8). For the x-intercept, set y=0y=0 to get 0=4xβˆ’80 = 4x - 8, which means x=2x=2, so it's (2,0)(2, 0).
  • To find the intercepts of 3x+5y=153x + 5y = 15: for the y-intercept, set x=0x=0 to get 5y=155y = 15, which means y=3y=3, so it's (0,3)(0, 3). For the x-intercept, set y=0y=0 to get 3x=153x = 15, which means x=5x=5, so it's (5,0)(5, 0).

Section 4

The intercept method of graphing

Property

To Graph a Linear Equation Using the Intercept Method.

  1. Find the xx- and yy-intercepts of the graph.
  2. Draw the line through the two intercepts.
  3. Find a third point on the graph as a check. (Choose any convenient value for xx and solve for yy.)

Examples

  • To graph xβˆ’2y=6x - 2y = 6, find the intercepts. Setting x=0x=0 gives y=βˆ’3y=-3, so (0,βˆ’3)(0, -3). Setting y=0y=0 gives x=6x=6, so (6,0)(6, 0). Plot these two points and draw a line through them.
  • To graph 4x+3y=124x + 3y = 12, find the intercepts. Setting x=0x=0 gives y=4y=4, so (0,4)(0, 4). Setting y=0y=0 gives x=3x=3, so (3,0)(3, 0). Plot (0,4)(0, 4) and (3,0)(3, 0) and connect them with a line.

Section 5

Interpreting the intercepts

Property

The intercepts of a graph give us valuable information about a problem. They often represent the starting or ending values for a particular variable.

Examples

  • A phone's battery percentage is modeled by P=100βˆ’5hP = 100 - 5h. The P-intercept (0,100)(0, 100) means the battery starts at 100%. The h-intercept (20,0)(20, 0) means the battery will be dead after 20 hours.
  • The value of a car is V=20000βˆ’2500yV = 20000 - 2500y. The V-intercept (0,20000)(0, 20000) is the initial price of the car (20000 dollars). The y-intercept (8,0)(8, 0) means the car will be worth 0 dollars after 8 years.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 3: Graphs of Linear Equations

  1. Lesson 1Current

    Lesson 1: Intercepts

  2. Lesson 2

    Lesson 2: Ratio and Proportion

  3. Lesson 3

    Lesson 3: Slope

  4. Lesson 4

    Lesson 4: Slope-Intercept Form

  5. Lesson 5

    Lesson 5: Properties of Lines