Learn on PengienVision, Mathematics, Grade 8Chapter 2: Analyze and Solve Linear Equations

Lesson 4: Equations with No Solutions or Infinitely Many Solutions

In this Grade 8 enVision Mathematics lesson from Chapter 2, students learn to determine whether a one-variable linear equation has one solution, no solution, or infinitely many solutions. They explore how simplifying equations using inverse operations, combining like terms, and the distributive property reveals whether the resulting statement is always true, never true, or true for a unique value. Students also practice identifying the number of solutions by inspection, without fully solving the equation.

Section 1

Overview of Solution Types for Linear Equations

Property

The result of this process may be “all numbers” or “a particular number” or “no numbers”.
These occur when the coefficient of xx is the same on both sides of the equation.

Examples

  • One solution: 5x2=3x+85x - 2 = 3x + 8 simplifies to 2x=102x = 10, so x=5x = 5 is the single solution.
  • No solution: 3(x+2)=3x13(x+2) = 3x - 1 becomes 3x+6=3x13x+6 = 3x-1. Subtracting 3x3x from both sides gives the false statement 6=16 = -1, so there is no solution.

Section 2

Solving Equations with the Distributive Property

Property

Steps for Solving Linear Equations.

  1. Use the distributive law to remove any parentheses.
  2. Combine like terms on each side of the equation.
  3. By adding or subtracting the same quantity on both sides of the equation, get all the variable terms on one side and all the constant terms on the other.
  4. Divide both sides by the coefficient of the variable to obtain an equation of the form x=ax = a.

Examples

  • Solve 3(x4)=93(x-4) = 9. First, distribute the 3 to get 3x12=93x - 12 = 9. Add 12 to both sides to get 3x=213x = 21. Finally, divide by 3 to find x=7x = 7.
  • Solve 5(y+1)=2y45(y+1) = 2y - 4. Distribute to get 5y+5=2y45y+5 = 2y-4. Subtract 2y2y from both sides, then subtract 5 from both sides to get 3y=93y = -9. Divide by 3 to find y=3y=-3.
  • Solve 254x=2x5(2x)25 - 4x = 2x - 5(2-x). Distribute to get 254x=2x10+5x25 - 4x = 2x - 10 + 5x. Combine like terms to get 254x=7x1025 - 4x = 7x - 10. Add 4x4x to both sides, then add 10 to both sides to get 35=11x35 = 11x, so x=3511x = \frac{35}{11}.

Explanation

When an equation has parentheses, first use the distributive law to clear them. After that, tidy up by combining like terms on each side. This simplifies the equation, making it easier to isolate the variable and find your solution.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Analyze and Solve Linear Equations

  1. Lesson 1

    Lesson 1: Combine Like Terms to Solve Equations

  2. Lesson 2

    Lesson 2: Solve Equations with Variables on Both Sides

  3. Lesson 3

    Lesson 3: Solve Multistep Equations

  4. Lesson 4Current

    Lesson 4: Equations with No Solutions or Infinitely Many Solutions

  5. Lesson 5

    Lesson 5: Compare Proportional Relationships

  6. Lesson 6

    Lesson 6: Connect Proportional Relationships and Slope

  7. Lesson 7

    Lesson 7: Analyze Linear Equations: y = mx

  8. Lesson 8

    Lesson 8: Understand the y-Intercept of a Line

  9. Lesson 9

    Lesson 9: Analyze Linear Equations: y = mx + b

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Overview of Solution Types for Linear Equations

Property

The result of this process may be “all numbers” or “a particular number” or “no numbers”.
These occur when the coefficient of xx is the same on both sides of the equation.

Examples

  • One solution: 5x2=3x+85x - 2 = 3x + 8 simplifies to 2x=102x = 10, so x=5x = 5 is the single solution.
  • No solution: 3(x+2)=3x13(x+2) = 3x - 1 becomes 3x+6=3x13x+6 = 3x-1. Subtracting 3x3x from both sides gives the false statement 6=16 = -1, so there is no solution.

Section 2

Solving Equations with the Distributive Property

Property

Steps for Solving Linear Equations.

  1. Use the distributive law to remove any parentheses.
  2. Combine like terms on each side of the equation.
  3. By adding or subtracting the same quantity on both sides of the equation, get all the variable terms on one side and all the constant terms on the other.
  4. Divide both sides by the coefficient of the variable to obtain an equation of the form x=ax = a.

Examples

  • Solve 3(x4)=93(x-4) = 9. First, distribute the 3 to get 3x12=93x - 12 = 9. Add 12 to both sides to get 3x=213x = 21. Finally, divide by 3 to find x=7x = 7.
  • Solve 5(y+1)=2y45(y+1) = 2y - 4. Distribute to get 5y+5=2y45y+5 = 2y-4. Subtract 2y2y from both sides, then subtract 5 from both sides to get 3y=93y = -9. Divide by 3 to find y=3y=-3.
  • Solve 254x=2x5(2x)25 - 4x = 2x - 5(2-x). Distribute to get 254x=2x10+5x25 - 4x = 2x - 10 + 5x. Combine like terms to get 254x=7x1025 - 4x = 7x - 10. Add 4x4x to both sides, then add 10 to both sides to get 35=11x35 = 11x, so x=3511x = \frac{35}{11}.

Explanation

When an equation has parentheses, first use the distributive law to clear them. After that, tidy up by combining like terms on each side. This simplifies the equation, making it easier to isolate the variable and find your solution.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Analyze and Solve Linear Equations

  1. Lesson 1

    Lesson 1: Combine Like Terms to Solve Equations

  2. Lesson 2

    Lesson 2: Solve Equations with Variables on Both Sides

  3. Lesson 3

    Lesson 3: Solve Multistep Equations

  4. Lesson 4Current

    Lesson 4: Equations with No Solutions or Infinitely Many Solutions

  5. Lesson 5

    Lesson 5: Compare Proportional Relationships

  6. Lesson 6

    Lesson 6: Connect Proportional Relationships and Slope

  7. Lesson 7

    Lesson 7: Analyze Linear Equations: y = mx

  8. Lesson 8

    Lesson 8: Understand the y-Intercept of a Line

  9. Lesson 9

    Lesson 9: Analyze Linear Equations: y = mx + b