Learn on PengienVision, Algebra 1Chapter 1: Solving Equations and Inequalities

Lesson 3: Solving Equations With a Variable on Both Sides

In this Grade 11 enVision Algebra 1 lesson from Chapter 1, students learn to solve equations with a variable on both sides by applying the distributive property, combining like terms, and using inverse operations to isolate the variable. The lesson also covers identifying equations that are identities (infinitely many solutions) or have no solution, and applies these skills to real-world mixture and cost-comparison problems. Students practice setting up and solving multi-step equations involving fractions, decimals, and rational expressions.

Section 1

Solve an equation with variables on both sides

Property

We'll start by choosing a variable side and a constant side, and then use the Subtraction and Addition Properties of Equality to collect all variables on one side and all constants on the other side.
Remember, what you do to the left side of the equation, you must do to the right side too.

Examples

  • In 6y=5y+106y = 5y + 10, subtract 5y5y from both sides. This simplifies directly to y=10y = 10.
  • To solve 3p12=9p3p - 12 = 9p, subtract 3p3p from both sides to get 12=6p-12 = 6p. Then, divide by 6 to find p=2p = -2.

Section 2

Solve equations with variables and constants on both sides

Property

Step 1. Choose one side to be the variable side and then the other will be the constant side.
Step 2. Collect the variable terms to the variable side, using the Addition or Subtraction Property of Equality.
Step 3. Collect the constants to the other side, using the Addition or Subtraction Property of Equality.
Step 4. Make the coefficient of the variable 1, using the Multiplication or Division Property of Equality.
Step 5. Check the solution by substituting it into the original equation.

It is a good idea to make the variable side the one in which the variable has the larger coefficient. This usually makes the arithmetic easier.

Examples

  • Given 9x+3=4x+239x + 3 = 4x + 23, subtract 4x4x from both sides to get 5x+3=235x + 3 = 23. Then subtract 3 to get 5x=205x = 20, so x=4x = 4.

Book overview

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Continue this chapter

Chapter 1: Solving Equations and Inequalities

  1. Lesson 1

    Lesson 1: Operations on Real Numbers

  2. Lesson 2

    Lesson 2: Solving Linear Equations

  3. Lesson 3Current

    Lesson 3: Solving Equations With a Variable on Both Sides

  4. Lesson 4

    Lesson 4: Literal Equations and Formulas

  5. Lesson 5

    Lesson 5: Solving Inequalities in One Variable

  6. Lesson 6

    Lesson 6: Compound Inequalities

  7. Lesson 7

    Lesson 7: Absolute Value Equations and Inequalities

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Solve an equation with variables on both sides

Property

We'll start by choosing a variable side and a constant side, and then use the Subtraction and Addition Properties of Equality to collect all variables on one side and all constants on the other side.
Remember, what you do to the left side of the equation, you must do to the right side too.

Examples

  • In 6y=5y+106y = 5y + 10, subtract 5y5y from both sides. This simplifies directly to y=10y = 10.
  • To solve 3p12=9p3p - 12 = 9p, subtract 3p3p from both sides to get 12=6p-12 = 6p. Then, divide by 6 to find p=2p = -2.

Section 2

Solve equations with variables and constants on both sides

Property

Step 1. Choose one side to be the variable side and then the other will be the constant side.
Step 2. Collect the variable terms to the variable side, using the Addition or Subtraction Property of Equality.
Step 3. Collect the constants to the other side, using the Addition or Subtraction Property of Equality.
Step 4. Make the coefficient of the variable 1, using the Multiplication or Division Property of Equality.
Step 5. Check the solution by substituting it into the original equation.

It is a good idea to make the variable side the one in which the variable has the larger coefficient. This usually makes the arithmetic easier.

Examples

  • Given 9x+3=4x+239x + 3 = 4x + 23, subtract 4x4x from both sides to get 5x+3=235x + 3 = 23. Then subtract 3 to get 5x=205x = 20, so x=4x = 4.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Solving Equations and Inequalities

  1. Lesson 1

    Lesson 1: Operations on Real Numbers

  2. Lesson 2

    Lesson 2: Solving Linear Equations

  3. Lesson 3Current

    Lesson 3: Solving Equations With a Variable on Both Sides

  4. Lesson 4

    Lesson 4: Literal Equations and Formulas

  5. Lesson 5

    Lesson 5: Solving Inequalities in One Variable

  6. Lesson 6

    Lesson 6: Compound Inequalities

  7. Lesson 7

    Lesson 7: Absolute Value Equations and Inequalities