Learn on PengiYoshiwara Elementary AlgebraChapter 7: Polynomials

Lesson 3: More About Factoring

In this Grade 6 lesson from Chapter 7 of Yoshiwara's Elementary Algebra, students learn to simplify quotients of powers using the Second Law of Exponents, which involves subtracting exponents when dividing powers with the same base. They also practice dividing monomials by applying this rule to each variable separately, and learn to identify the greatest common factor (GCF) of a polynomial by finding the largest numerical factor and the lowest power of each variable across all terms. The lesson reinforces these skills through practice with polynomial products, rectangular area models for quadratic trinomials, and real-world problems involving volume and surface area.

Section 1

πŸ“˜ More About Factoring

New Concept

This lesson expands your factoring toolkit. You'll learn to handle more complex polynomials by finding the greatest common factor (GCF) and using strategies like guess-and-check or the box method to factor quadratic trinomials completely.

What’s next

Get ready to master these new techniques! You'll start with practice cards on dividing powers and finding the GCF, building your skills for factoring.

Section 2

Quotients of powers

Property

To divide two powers with the same base, we subtract the smaller exponent from the larger one, and keep the same base.

  1. If the larger exponent occurs in the numerator, put the power in the numerator.
  2. If the larger exponent occurs in the denominator, put the power in the denominator.

In symbols:

  1. aman=amβˆ’n\frac{a^m}{a^n} = a^{m-n} if n<mn < m
  2. aman=1anβˆ’m\frac{a^m}{a^n} = \frac{1}{a^{n-m}} if n>mn > m

Section 3

Greatest common factors

Property

The greatest common factor (GCF) is the largest factor that divides evenly into each term of the polynomial. It consists of the largest numerical factor and the highest power of each variable that is common to all terms. The exponent on each variable of the GCF is the smallest exponent that appears on that variable among the terms of the polynomial.

Examples

  • For 15x2y2βˆ’12xy+6xy315x^2y^2 - 12xy + 6xy^3, the GCF of the coefficients 15, -12, and 6 is 3. The smallest power of xx is x1x^1 and of yy is y1y^1. The GCF is 3xy3xy.
  • To factor 4a3b2+6ab3βˆ’18a2b44a^3b^2 + 6ab^3 - 18a^2b^4, the GCF is 2ab22ab^2. Factoring this out gives 2ab2(2a2+3bβˆ’9ab2)2ab^2(2a^2 + 3b - 9ab^2).

Section 4

Factoring by guess-and-check

Property

To factor a quadratic trinomial of the form ax2+bx+cax^2 + bx + c, we reverse the FOIL method. We look for two binomials whose product matches the trinomial.

  • The First terms of the binomials must multiply to ax2ax^2.
  • The Last terms must multiply to cc.
  • The sum of the Outer and Inner products must equal the middle term, bxbx.

Examples

  • To factor 2x2βˆ’7x+32x^2 - 7x + 3, the first terms could be 2x2x and xx. The last terms could be βˆ’1-1 and βˆ’3-3. The combination (2xβˆ’1)(xβˆ’3)(2x - 1)(x - 3) gives a middle term of βˆ’6xβˆ’x=βˆ’7x-6x - x = -7x, so it is correct.

Section 5

Quadratic trinomials in two variables

Property

To factor a trinomial in two variables of the form ax2+bxy+cy2ax^2 + bxy + cy^2, we use the same methods as for single-variable trinomials. The first and last terms of the trinomial are quadratic, and the middle is a cross-term.
The factored form will look like (px+qy)(rx+sy)(px + qy)(rx + sy).

Examples

  • To factor x2+5xy+6y2x^2 + 5xy + 6y^2, we need factors of 6y26y^2 that sum to 5xy5xy. The factors 2y2y and 3y3y work, giving (x+2y)(x+3y)(x + 2y)(x + 3y).
  • To factor a2βˆ’abβˆ’12b2a^2 - ab - 12b^2, we need factors of βˆ’12b2-12b^2 that sum to βˆ’ab-ab. The factors βˆ’4b-4b and 3b3b work, resulting in (aβˆ’4b)(a+3b)(a - 4b)(a + 3b).

Section 6

Combining factoring techniques

Property

To factor a polynomial completely, you should always begin by checking for a greatest common factor (GCF). After factoring out the GCF, examine the remaining polynomial factor to see if it can be factored again using other techniques.

Examples

  • To factor 2b4+8b2+6b2b^4 + 8b^2 + 6b, first factor out the GCF, 2b2b, to get 2b(b2+4b+3)2b(b^2 + 4b + 3). Then, factor the trinomial to get the final answer: 2b(b+3)(b+1)2b(b + 3)(b + 1).
  • To factor 4a6βˆ’10a5+6a44a^6 - 10a^5 + 6a^4, the GCF is 2a42a^4. Factoring it out gives 2a4(2a2βˆ’5a+3)2a^4(2a^2 - 5a + 3). Factoring the trinomial gives 2a4(2aβˆ’3)(aβˆ’1)2a^4(2a - 3)(a - 1).

Book overview

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Continue this chapter

Chapter 7: Polynomials

  1. Lesson 1

    Lesson 1: Polynomials

  2. Lesson 2

    Lesson 2: Products of Polynomials

  3. Lesson 3Current

    Lesson 3: More About Factoring

  4. Lesson 4

    Lesson 4: Special Products and Factors

  5. Lesson 5

    Lesson 5: Chapter Summary and Review

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

πŸ“˜ More About Factoring

New Concept

This lesson expands your factoring toolkit. You'll learn to handle more complex polynomials by finding the greatest common factor (GCF) and using strategies like guess-and-check or the box method to factor quadratic trinomials completely.

What’s next

Get ready to master these new techniques! You'll start with practice cards on dividing powers and finding the GCF, building your skills for factoring.

Section 2

Quotients of powers

Property

To divide two powers with the same base, we subtract the smaller exponent from the larger one, and keep the same base.

  1. If the larger exponent occurs in the numerator, put the power in the numerator.
  2. If the larger exponent occurs in the denominator, put the power in the denominator.

In symbols:

  1. aman=amβˆ’n\frac{a^m}{a^n} = a^{m-n} if n<mn < m
  2. aman=1anβˆ’m\frac{a^m}{a^n} = \frac{1}{a^{n-m}} if n>mn > m

Section 3

Greatest common factors

Property

The greatest common factor (GCF) is the largest factor that divides evenly into each term of the polynomial. It consists of the largest numerical factor and the highest power of each variable that is common to all terms. The exponent on each variable of the GCF is the smallest exponent that appears on that variable among the terms of the polynomial.

Examples

  • For 15x2y2βˆ’12xy+6xy315x^2y^2 - 12xy + 6xy^3, the GCF of the coefficients 15, -12, and 6 is 3. The smallest power of xx is x1x^1 and of yy is y1y^1. The GCF is 3xy3xy.
  • To factor 4a3b2+6ab3βˆ’18a2b44a^3b^2 + 6ab^3 - 18a^2b^4, the GCF is 2ab22ab^2. Factoring this out gives 2ab2(2a2+3bβˆ’9ab2)2ab^2(2a^2 + 3b - 9ab^2).

Section 4

Factoring by guess-and-check

Property

To factor a quadratic trinomial of the form ax2+bx+cax^2 + bx + c, we reverse the FOIL method. We look for two binomials whose product matches the trinomial.

  • The First terms of the binomials must multiply to ax2ax^2.
  • The Last terms must multiply to cc.
  • The sum of the Outer and Inner products must equal the middle term, bxbx.

Examples

  • To factor 2x2βˆ’7x+32x^2 - 7x + 3, the first terms could be 2x2x and xx. The last terms could be βˆ’1-1 and βˆ’3-3. The combination (2xβˆ’1)(xβˆ’3)(2x - 1)(x - 3) gives a middle term of βˆ’6xβˆ’x=βˆ’7x-6x - x = -7x, so it is correct.

Section 5

Quadratic trinomials in two variables

Property

To factor a trinomial in two variables of the form ax2+bxy+cy2ax^2 + bxy + cy^2, we use the same methods as for single-variable trinomials. The first and last terms of the trinomial are quadratic, and the middle is a cross-term.
The factored form will look like (px+qy)(rx+sy)(px + qy)(rx + sy).

Examples

  • To factor x2+5xy+6y2x^2 + 5xy + 6y^2, we need factors of 6y26y^2 that sum to 5xy5xy. The factors 2y2y and 3y3y work, giving (x+2y)(x+3y)(x + 2y)(x + 3y).
  • To factor a2βˆ’abβˆ’12b2a^2 - ab - 12b^2, we need factors of βˆ’12b2-12b^2 that sum to βˆ’ab-ab. The factors βˆ’4b-4b and 3b3b work, resulting in (aβˆ’4b)(a+3b)(a - 4b)(a + 3b).

Section 6

Combining factoring techniques

Property

To factor a polynomial completely, you should always begin by checking for a greatest common factor (GCF). After factoring out the GCF, examine the remaining polynomial factor to see if it can be factored again using other techniques.

Examples

  • To factor 2b4+8b2+6b2b^4 + 8b^2 + 6b, first factor out the GCF, 2b2b, to get 2b(b2+4b+3)2b(b^2 + 4b + 3). Then, factor the trinomial to get the final answer: 2b(b+3)(b+1)2b(b + 3)(b + 1).
  • To factor 4a6βˆ’10a5+6a44a^6 - 10a^5 + 6a^4, the GCF is 2a42a^4. Factoring it out gives 2a4(2a2βˆ’5a+3)2a^4(2a^2 - 5a + 3). Factoring the trinomial gives 2a4(2aβˆ’3)(aβˆ’1)2a^4(2a - 3)(a - 1).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Polynomials

  1. Lesson 1

    Lesson 1: Polynomials

  2. Lesson 2

    Lesson 2: Products of Polynomials

  3. Lesson 3Current

    Lesson 3: More About Factoring

  4. Lesson 4

    Lesson 4: Special Products and Factors

  5. Lesson 5

    Lesson 5: Chapter Summary and Review