Learn on PengiYoshiwara Core MathChapter 2: Numbers and Variables

Lesson 2.5: Equations

In this Grade 8 lesson from Yoshiwara Core Math, Chapter 2, students learn what an equation is, how to write equations using variables to express relationships between two quantities, and how to identify a solution as the value that makes an equation true. The lesson covers using opposite operations to isolate the variable and find solutions. It is part of the Numbers and Variables chapter and builds foundational algebraic reasoning skills.

Section 1

📘 Equations

New Concept

An equation states that two expressions are equal. We'll find a 'solution'—the value of a variable that makes the equation true. You'll master solving equations by isolating the variable using opposite operations, like addition and subtraction.

What’s next

Next, you'll apply this with interactive examples and practice cards to master solving one-step equations.

Section 2

What is an equation

Property

An equation is a mathematical statement that two algebraic expressions are equal. We can use variables to write equations. For example, D=F+6D = F + 6 where DD and FF stand for Delbert’s age and Francine’s age. Finding relationships between variables and describing them as equations is an important algebraic skill.

Examples

  • A store offers a 20 dollar discount on all jackets. An equation for the sale price, SS, in terms of the original price, PP, is S=P−20S = P - 20.
  • A company gives a 10% bonus on top of a base salary. An equation for the total pay, TT, in terms of the base salary, BB, is T=1.10BT = 1.10B.

Section 3

Solution of an equation

Property

A solution of an equation is a value of the variable that makes the equation true. An equation containing a variable can be true or false, depending on the value substituted for the variable.

Examples

  • To check if 15 is a solution to 8x=1208x = 120, we substitute 15 for xx. This gives 8(15)=1208(15) = 120. Since 120=120120 = 120 is true, 15 is a solution.
  • To check if 5 is a solution to m4=2\frac{m}{4} = 2, we substitute 5 for mm. This gives 54=2\frac{5}{4} = 2. Since 1.25=21.25 = 2 is false, 5 is not a solution.

Section 4

Opposite operations

Property

Each of the four arithmetic operations has an opposite operation that 'undoes' its effect. Addition and subtraction are opposite operations. Multiplication and division are opposite operations. For any numbers xx, aa, and bb (where b≠0b \neq 0):

(x+a)−a=x(x + a) - a = x
bâ‹…xb=x\frac{b \cdot x}{b} = x

Section 5

Isolating the variable

Property

To solve an equation, we isolate the variable. The process is:

  1. Ask yourself: Which operation has been performed on the variable?
  2. Perform the opposite operation on both sides of the equation to maintain balance.
  3. Check your solution by substituting it into the original equation.

Examples

  • To solve x−5=12x - 5 = 12, we undo the subtraction by adding 5 to both sides: (x−5)+5=12+5(x - 5) + 5 = 12 + 5, which simplifies to x=17x = 17.
  • To solve y+9=20y + 9 = 20, we undo the addition by subtracting 9 from both sides: (y+9)−9=20−9(y + 9) - 9 = 20 - 9, which simplifies to y=11y = 11.

Book overview

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Continue this chapter

Chapter 2: Numbers and Variables

  1. Lesson 1

    Lesson 2.1: Decimal Numbers

  2. Lesson 2

    Lesson 2.2: More Fractions and Percents

  3. Lesson 3

    Lesson 2.3: Variables

  4. Lesson 4

    Lesson 2.4: Algebraic Expressions

  5. Lesson 5Current

    Lesson 2.5: Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Equations

New Concept

An equation states that two expressions are equal. We'll find a 'solution'—the value of a variable that makes the equation true. You'll master solving equations by isolating the variable using opposite operations, like addition and subtraction.

What’s next

Next, you'll apply this with interactive examples and practice cards to master solving one-step equations.

Section 2

What is an equation

Property

An equation is a mathematical statement that two algebraic expressions are equal. We can use variables to write equations. For example, D=F+6D = F + 6 where DD and FF stand for Delbert’s age and Francine’s age. Finding relationships between variables and describing them as equations is an important algebraic skill.

Examples

  • A store offers a 20 dollar discount on all jackets. An equation for the sale price, SS, in terms of the original price, PP, is S=P−20S = P - 20.
  • A company gives a 10% bonus on top of a base salary. An equation for the total pay, TT, in terms of the base salary, BB, is T=1.10BT = 1.10B.

Section 3

Solution of an equation

Property

A solution of an equation is a value of the variable that makes the equation true. An equation containing a variable can be true or false, depending on the value substituted for the variable.

Examples

  • To check if 15 is a solution to 8x=1208x = 120, we substitute 15 for xx. This gives 8(15)=1208(15) = 120. Since 120=120120 = 120 is true, 15 is a solution.
  • To check if 5 is a solution to m4=2\frac{m}{4} = 2, we substitute 5 for mm. This gives 54=2\frac{5}{4} = 2. Since 1.25=21.25 = 2 is false, 5 is not a solution.

Section 4

Opposite operations

Property

Each of the four arithmetic operations has an opposite operation that 'undoes' its effect. Addition and subtraction are opposite operations. Multiplication and division are opposite operations. For any numbers xx, aa, and bb (where b≠0b \neq 0):

(x+a)−a=x(x + a) - a = x
bâ‹…xb=x\frac{b \cdot x}{b} = x

Section 5

Isolating the variable

Property

To solve an equation, we isolate the variable. The process is:

  1. Ask yourself: Which operation has been performed on the variable?
  2. Perform the opposite operation on both sides of the equation to maintain balance.
  3. Check your solution by substituting it into the original equation.

Examples

  • To solve x−5=12x - 5 = 12, we undo the subtraction by adding 5 to both sides: (x−5)+5=12+5(x - 5) + 5 = 12 + 5, which simplifies to x=17x = 17.
  • To solve y+9=20y + 9 = 20, we undo the addition by subtracting 9 from both sides: (y+9)−9=20−9(y + 9) - 9 = 20 - 9, which simplifies to y=11y = 11.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 2: Numbers and Variables

  1. Lesson 1

    Lesson 2.1: Decimal Numbers

  2. Lesson 2

    Lesson 2.2: More Fractions and Percents

  3. Lesson 3

    Lesson 2.3: Variables

  4. Lesson 4

    Lesson 2.4: Algebraic Expressions

  5. Lesson 5Current

    Lesson 2.5: Equations