Learn on PengiReveal Math, AcceleratedUnit 12: Area, Surface Area, and Volume

Lesson 12-3: Solve Problems Involving Area and Surface Area

In this Grade 7 lesson from Reveal Math, Accelerated, students apply area and surface area formulas to solve real-world problems involving composite two-dimensional and three-dimensional figures. Using skills such as decomposing trapezoids, rectangles, and triangles and summing their areas, students work through multi-step problems like calculating roofing material for a pagoda-style roof and determining how much paint is needed for a multi-tier planter. The lesson builds on Unit 12 concepts by connecting geometric formulas to practical, context-driven scenarios.

Section 1

Converting mixed-unit to single-unit measures

Property

To express a mixed-unit measurement like height in a single unit, convert the smaller unit into a fraction or decimal of the larger unit. For example, to convert 6 ft 3 in. to feet:

6 ft 3 in.=6312 ft=614 ft=6.25 ft 6 \text{ ft } 3 \text{ in.} = 6\frac{3}{12} \text{ ft} = 6\frac{1}{4} \text{ ft} = 6.25 \text{ ft}

Examples

  • Convert a run time of 8 minutes and 30 seconds to minutes: 8 min 30 sec=83060 min=812 min=8.5 min8 \text{ min } 30 \text{ sec} = 8\frac{30}{60} \text{ min} = 8\frac{1}{2} \text{ min} = 8.5 \text{ min}
  • Convert a movie length of 2 hours and 15 minutes to hours: 2 hr 15 min=21560 hr=214 hr=2.25 hr2 \text{ hr } 15 \text{ min} = 2\frac{15}{60} \text{ hr} = 2\frac{1}{4} \text{ hr} = 2.25 \text{ hr}
  • Convert a room width of 10 ft 6 in. to feet: 10 ft 6 in.=10612 ft=10.5 ft10 \text{ ft } 6 \text{ in.} = 10\frac{6}{12} \text{ ft} = 10.5 \text{ ft}

Explanation

Stop juggling two different units! To simplify a measurement like 'feet and inches,' turn the smaller part into a fraction of the bigger one. Then, just add it to the whole number part for a clean, single-unit answer. It makes calculations so much easier when everything speaks the same language.

Section 2

Method 1: Decomposition (The Addition Method)

Property

Decomposition means breaking an irregular figure into smaller, non-overlapping shapes that you already know.
Total Area = Area of Shape 1 + Area of Shape 2 + ...

Examples

  • L-Shape: An L-shaped room can be split into two rectangles. If one rectangle measures 12 by 4 units (Area = 48) and the other is 2 by 6 units (Area = 12), the total area is 48 + 12 = 60 square units.
  • House Shape: A shape looks like a house. It is formed by a rectangle (8 by 4 units, Area = 32) with a triangle on top (base 8, height 3, Area = 12). The total area is 32 + 12 = 44 square units.

Explanation

Think of this method like building with LEGOs! You break down a strangely shaped room or garden into simple blocks like rectangles and triangles. Calculate the area of each individual block, and then simply add them all together to get the total area.

Book overview

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Continue this chapter

Unit 12: Area, Surface Area, and Volume

  1. Lesson 1

    Lesson 12-1: Describe Cross Sections of Three-Dimensional Figures

  2. Lesson 2

    Lesson 12-2: Understand and Use Square Roots

  3. Lesson 3Current

    Lesson 12-3: Solve Problems Involving Area and Surface Area

  4. Lesson 4

    Lesson 12-4: Solve Problems Involving Circumference of Circles

  5. Lesson 5

    Lesson 12-5: Solve Problems Involving Area of Circles

  6. Lesson 6

    Lesson 12-6: Understand and Use Cube Roots

  7. Lesson 7

    Lesson 12-7: Solve Problems Involving Volume of Cylinders and Cones

  8. Lesson 8

    Lesson 12-8: Solve Problems Involving Volume of Spheres

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Converting mixed-unit to single-unit measures

Property

To express a mixed-unit measurement like height in a single unit, convert the smaller unit into a fraction or decimal of the larger unit. For example, to convert 6 ft 3 in. to feet:

6 ft 3 in.=6312 ft=614 ft=6.25 ft 6 \text{ ft } 3 \text{ in.} = 6\frac{3}{12} \text{ ft} = 6\frac{1}{4} \text{ ft} = 6.25 \text{ ft}

Examples

  • Convert a run time of 8 minutes and 30 seconds to minutes: 8 min 30 sec=83060 min=812 min=8.5 min8 \text{ min } 30 \text{ sec} = 8\frac{30}{60} \text{ min} = 8\frac{1}{2} \text{ min} = 8.5 \text{ min}
  • Convert a movie length of 2 hours and 15 minutes to hours: 2 hr 15 min=21560 hr=214 hr=2.25 hr2 \text{ hr } 15 \text{ min} = 2\frac{15}{60} \text{ hr} = 2\frac{1}{4} \text{ hr} = 2.25 \text{ hr}
  • Convert a room width of 10 ft 6 in. to feet: 10 ft 6 in.=10612 ft=10.5 ft10 \text{ ft } 6 \text{ in.} = 10\frac{6}{12} \text{ ft} = 10.5 \text{ ft}

Explanation

Stop juggling two different units! To simplify a measurement like 'feet and inches,' turn the smaller part into a fraction of the bigger one. Then, just add it to the whole number part for a clean, single-unit answer. It makes calculations so much easier when everything speaks the same language.

Section 2

Method 1: Decomposition (The Addition Method)

Property

Decomposition means breaking an irregular figure into smaller, non-overlapping shapes that you already know.
Total Area = Area of Shape 1 + Area of Shape 2 + ...

Examples

  • L-Shape: An L-shaped room can be split into two rectangles. If one rectangle measures 12 by 4 units (Area = 48) and the other is 2 by 6 units (Area = 12), the total area is 48 + 12 = 60 square units.
  • House Shape: A shape looks like a house. It is formed by a rectangle (8 by 4 units, Area = 32) with a triangle on top (base 8, height 3, Area = 12). The total area is 32 + 12 = 44 square units.

Explanation

Think of this method like building with LEGOs! You break down a strangely shaped room or garden into simple blocks like rectangles and triangles. Calculate the area of each individual block, and then simply add them all together to get the total area.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Unit 12: Area, Surface Area, and Volume

  1. Lesson 1

    Lesson 12-1: Describe Cross Sections of Three-Dimensional Figures

  2. Lesson 2

    Lesson 12-2: Understand and Use Square Roots

  3. Lesson 3Current

    Lesson 12-3: Solve Problems Involving Area and Surface Area

  4. Lesson 4

    Lesson 12-4: Solve Problems Involving Circumference of Circles

  5. Lesson 5

    Lesson 12-5: Solve Problems Involving Area of Circles

  6. Lesson 6

    Lesson 12-6: Understand and Use Cube Roots

  7. Lesson 7

    Lesson 12-7: Solve Problems Involving Volume of Cylinders and Cones

  8. Lesson 8

    Lesson 12-8: Solve Problems Involving Volume of Spheres