Learn on PengiReveal Math, AcceleratedUnit 12: Area, Surface Area, and Volume

Lesson 12-2: Understand and Use Square Roots

In this Grade 7 lesson from Reveal Math, Accelerated, students learn to identify perfect squares, calculate square roots of perfect squares, and estimate the square roots of non-perfect squares using benchmark values. The lesson connects square roots to the area formula for squares and applies the concept to real-world contexts such as finding side lengths and calculating voltage. Students practice distinguishing between squares and square roots and develop strategies for narrowing decimal approximations of irrational square roots.

Section 1

Square Roots and Perfect Squares

Property

The symbol A\sqrt{A} (square root) indicates a number aa whose square is AA: a2=Aa^2 = A. The square root A\sqrt{A} is only defined for non-negative numbers AA. A positive integer whose square root is a positive integer is called a perfect square.

Examples

  • Since 82=648^2 = 64, the square root of 64 is 8. We write this as 64=8\sqrt{64} = 8. The number 64 is a perfect square.
  • The number 50 is not a perfect square. Its square root, 50\sqrt{50}, is a number that, when multiplied by itself, equals 50.
  • To find the number whose square is 121, we are looking for 121\sqrt{121}. Since 11×11=12111 \times 11 = 121, the answer is 1111.

Explanation

A square root is the opposite of squaring a number. If you know the area of a square, the square root tells you the side length. Perfect squares are special because their square roots are nice, neat whole numbers!

Section 2

Application: Finding the Side of a Square from its Area

Property

The area (AA) of a square is found by squaring its side length (ss):

A=s2A = s^2

To find the side length of a square given its area, you take the square root of the area:

s=As = \sqrt{A}

Examples

Section 3

Estimating Square Roots to the Nearest Integer

Property

To estimate the square root of a non-perfect square, first find the two perfect squares it is between. The integer whose square is closer to your number is your estimate.

Examples

  • To estimate 50\sqrt{50}, notice 50 is between 49(72)49(7^2) and 64(82)64(8^2). Since 50 is closer to 49, 507\sqrt{50} \approx 7.
  • 37\sqrt{37} is between 36=6\sqrt{36}=6 and 49=7\sqrt{49}=7. Because 37 is closer to 36, we estimate 376\sqrt{37} \approx 6.
  • 40\sqrt{40} is between the whole numbers 6 and 7, since 62=366^2=36 and 72=497^2=49.

Explanation

This is like being a number line detective! You trap the tricky, non-perfect square root between two “friendly” perfect squares. Whichever perfect neighbor it’s cozier with gives you the closest whole number guess for its value. It's a great trick for quick estimations!

Book overview

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Continue this chapter

Unit 12: Area, Surface Area, and Volume

  1. Lesson 1

    Lesson 12-1: Describe Cross Sections of Three-Dimensional Figures

  2. Lesson 2Current

    Lesson 12-2: Understand and Use Square Roots

  3. Lesson 3

    Lesson 12-3: Solve Problems Involving Area and Surface Area

  4. Lesson 4

    Lesson 12-4: Solve Problems Involving Circumference of Circles

  5. Lesson 5

    Lesson 12-5: Solve Problems Involving Area of Circles

  6. Lesson 6

    Lesson 12-6: Understand and Use Cube Roots

  7. Lesson 7

    Lesson 12-7: Solve Problems Involving Volume of Cylinders and Cones

  8. Lesson 8

    Lesson 12-8: Solve Problems Involving Volume of Spheres

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Square Roots and Perfect Squares

Property

The symbol A\sqrt{A} (square root) indicates a number aa whose square is AA: a2=Aa^2 = A. The square root A\sqrt{A} is only defined for non-negative numbers AA. A positive integer whose square root is a positive integer is called a perfect square.

Examples

  • Since 82=648^2 = 64, the square root of 64 is 8. We write this as 64=8\sqrt{64} = 8. The number 64 is a perfect square.
  • The number 50 is not a perfect square. Its square root, 50\sqrt{50}, is a number that, when multiplied by itself, equals 50.
  • To find the number whose square is 121, we are looking for 121\sqrt{121}. Since 11×11=12111 \times 11 = 121, the answer is 1111.

Explanation

A square root is the opposite of squaring a number. If you know the area of a square, the square root tells you the side length. Perfect squares are special because their square roots are nice, neat whole numbers!

Section 2

Application: Finding the Side of a Square from its Area

Property

The area (AA) of a square is found by squaring its side length (ss):

A=s2A = s^2

To find the side length of a square given its area, you take the square root of the area:

s=As = \sqrt{A}

Examples

Section 3

Estimating Square Roots to the Nearest Integer

Property

To estimate the square root of a non-perfect square, first find the two perfect squares it is between. The integer whose square is closer to your number is your estimate.

Examples

  • To estimate 50\sqrt{50}, notice 50 is between 49(72)49(7^2) and 64(82)64(8^2). Since 50 is closer to 49, 507\sqrt{50} \approx 7.
  • 37\sqrt{37} is between 36=6\sqrt{36}=6 and 49=7\sqrt{49}=7. Because 37 is closer to 36, we estimate 376\sqrt{37} \approx 6.
  • 40\sqrt{40} is between the whole numbers 6 and 7, since 62=366^2=36 and 72=497^2=49.

Explanation

This is like being a number line detective! You trap the tricky, non-perfect square root between two “friendly” perfect squares. Whichever perfect neighbor it’s cozier with gives you the closest whole number guess for its value. It's a great trick for quick estimations!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Unit 12: Area, Surface Area, and Volume

  1. Lesson 1

    Lesson 12-1: Describe Cross Sections of Three-Dimensional Figures

  2. Lesson 2Current

    Lesson 12-2: Understand and Use Square Roots

  3. Lesson 3

    Lesson 12-3: Solve Problems Involving Area and Surface Area

  4. Lesson 4

    Lesson 12-4: Solve Problems Involving Circumference of Circles

  5. Lesson 5

    Lesson 12-5: Solve Problems Involving Area of Circles

  6. Lesson 6

    Lesson 12-6: Understand and Use Cube Roots

  7. Lesson 7

    Lesson 12-7: Solve Problems Involving Volume of Cylinders and Cones

  8. Lesson 8

    Lesson 12-8: Solve Problems Involving Volume of Spheres