Learn on PengiOpenstax Elementary Algebra 2EChapter 1: Foundations

Lesson 1.4: Multiply and Divide Integers

Students learn to multiply and divide integers using signed number rules, including how same signs produce a positive result and different signs produce a negative result. The lesson also covers simplifying and evaluating variable expressions with integers, and translating English phrases into algebraic expressions. This content is from Lesson 1.4 of OpenStax Elementary Algebra 2E, Chapter 1: Foundations.

Section 1

πŸ“˜ Multiply and Divide Integers

New Concept

Master multiplying and dividing integers using one simple rule: same signs yield a positive result, while different signs yield a negative. This skill is key to simplifying expressions, evaluating variables, and solving real-world application problems.

What’s next

Next, you'll apply these rules through interactive examples and practice cards, building your confidence to solve more complex algebraic problems.

Section 2

Multiplication of Signed Numbers

Property

For multiplication of two signed numbers:

  • If the signs are the same, the product is positive.
  • If the signs are different, the product is negative.

Same Signs (Product is Positive)

  • Two positives: 7β‹…4=287 \cdot 4 = 28
  • Two negatives: βˆ’8(βˆ’6)=48-8(-6) = 48

Different Signs (Product is Negative)

  • Positive β‹…\cdot negative: 7(βˆ’9)=βˆ’637(-9) = -63
  • Negative β‹…\cdot positive: βˆ’5β‹…10=βˆ’50-5 \cdot 10 = -50

Section 3

Division of Signed Numbers

Property

Division is the inverse operation of multiplication. For division of two signed numbers, the rules are the same as for multiplication:

  • If the signs are the same, the result is positive.
  • If the signs are different, the result is negative.

Examples

  • To divide βˆ’45Γ·9-45 \div 9, the signs are different, so the quotient is negative. The result is βˆ’5-5.
  • To divide βˆ’72Γ·(βˆ’8)-72 \div (-8), the signs are the same, so the quotient is positive. The result is 99.
  • To divide 100Γ·(βˆ’25)100 \div (-25), the signs are different, so the quotient is negative. The result is βˆ’4-4.

Explanation

Division uses the exact same sign rules as multiplication. If you know that a negative times a negative is a positive, then you also know that a negative divided by a negative is a positive. The rules are consistent!

Section 4

Simplify Expressions with Integers

Property

The order of operations (PEMDAS/BODMAS) still applies when integers are included. When simplifying expressions, perform operations in the correct sequence: Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

Be aware of the difference with exponents:

  • (βˆ’a)n(-a)^n means the base is βˆ’a-a.
  • βˆ’an-a^n means the base is aa, and you find the opposite of the result.

Examples

  • To simplify 15βˆ’4(2βˆ’9)15 - 4(2 - 9), first solve the parenthesis: 15βˆ’4(βˆ’7)15 - 4(-7). Then multiply: 15βˆ’(βˆ’28)15 - (-28). Finally, subtract: 15+28=4315 + 28 = 43.
  • To simplify (βˆ’5)2βˆ’30Γ·(10βˆ’4)(-5)^2 - 30 \div (10-4), handle the exponent and parenthesis first: 25βˆ’30Γ·625 - 30 \div 6. Then divide: 25βˆ’5=2025 - 5 = 20.
  • To simplify 9(βˆ’4)Γ·(βˆ’2)39(-4) \div (-2)^3, first evaluate the exponent: 9(βˆ’4)Γ·(βˆ’8)9(-4) \div (-8). Then multiply: βˆ’36Γ·(βˆ’8)=4.5-36 \div (-8) = 4.5.

Section 5

Evaluate Variable Expressions

Property

To evaluate a variable expression means to substitute a number for the variable in the expression and then simplify the resulting expression. When substituting negative numbers, it is often helpful to use parentheses to ensure the operations are performed correctly.

Examples

  • To evaluate 3x2+5xβˆ’13x^2 + 5x - 1 when x=βˆ’2x = -2, substitute to get 3(βˆ’2)2+5(βˆ’2)βˆ’13(-2)^2 + 5(-2) - 1. This simplifies to 3(4)βˆ’10βˆ’1=12βˆ’10βˆ’1=13(4) - 10 - 1 = 12 - 10 - 1 = 1.
  • To evaluate (a+b)2(a+b)^2 when a=βˆ’10a = -10 and b=7b = 7, substitute to get (βˆ’10+7)2(-10+7)^2. This simplifies to (βˆ’3)2=9(-3)^2 = 9.
  • To evaluate 50βˆ’y50 - y when y=βˆ’15y = -15, substitute to get 50βˆ’(βˆ’15)50 - (-15). This simplifies to 50+15=6550 + 15 = 65.

Explanation

Evaluating an expression is like plugging a specific value into a template. The variable is a placeholder, and you replace it with the given number. Using parentheses, especially for negative numbers, prevents mistakes with signs and exponents.

Section 6

Translate Phrases to Expressions

Property

Translating English phrases to algebra involves recognizing keywords for operations. Key words for multiplication and division include:

  • Product: Indicates multiplication (e.g., 'the product of aa and bb' is aβ‹…ba \cdot b).
  • Quotient: Indicates division (e.g., 'the quotient of aa and bb' is aΓ·ba \div b or ab\frac{a}{b}).

Be careful with subtraction order: 'the difference of aa and bb' is aβˆ’ba-b, but 'bb subtracted from aa' is also aβˆ’ba-b.

Examples

  • The phrase 'the product of βˆ’8-8 and 1212' translates to the expression (βˆ’8)(12)(-8)(12), which simplifies to βˆ’96-96.
  • The phrase 'the quotient of βˆ’100-100 and βˆ’4-4' translates to the expression βˆ’100Γ·(βˆ’4)-100 \div (-4), which simplifies to 2525.
  • The phrase 'the sum of βˆ’5-5 and 33, increased by 1010' translates to [βˆ’5+3]+10[-5 + 3] + 10, which simplifies to βˆ’2+10=8-2 + 10 = 8.

Explanation

This skill is like translating from one language to another. Words like 'product' and 'quotient' are direct signals for multiplication and division. Reading carefully helps put the numbers and operations in the correct order to match the phrase.

Section 7

Solving Integer Applications

Property

To solve applications with integers, use a structured approach:

  1. Read the problem to understand all words and ideas.
  2. Identify what you are asked to find.
  3. Write a phrase that gives the information to find it.
  4. Translate the phrase into a mathematical expression.
  5. Simplify the expression.
  6. Answer the question with a complete sentence.

Examples

  • A scuba diver descends 20 feet per minute for 5 minutes. To find her change in depth, translate '5 times a 20-foot descent' to 5(βˆ’20)5(-20). The change is βˆ’100-100 feet.
  • A company had a total loss of 6,000 dollars over 4 months. To find the average monthly loss, translate 'the quotient of βˆ’6000-6000 and 44' to βˆ’6000Γ·4-6000 \div 4. The average loss was 1,500 dollars per month.
  • The temperature at noon was 5∘5^\circC. By midnight, it dropped to βˆ’11∘-11^\circC. The difference is 5βˆ’(βˆ’11)=16∘5 - (-11) = 16^\circC.

Explanation

This six-step plan turns a word problem into a straightforward math problem. It helps you organize your thoughts, translate the situation into an expression, solve it, and then state the answer clearly in the context of the original problem.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Foundations

  1. Lesson 1

    Lesson 1.1: Introduction to Whole Numbers

  2. Lesson 2

    Lesson 1.2: Use the Language of Algebra

  3. Lesson 3

    Lesson 1.3: Add and Subtract Integers

  4. Lesson 4Current

    Lesson 1.4: Multiply and Divide Integers

  5. Lesson 5

    Lesson 1.5: Visualize Fractions

  6. Lesson 6

    Lesson 1.6: Add and Subtract Fractions

  7. Lesson 7

    Lesson 1.7: Decimals

  8. Lesson 8

    Lesson 1.8: The Real Numbers

  9. Lesson 9

    Lesson 1.9: Properties of Real Numbers

  10. Lesson 10

    Lesson 1.10: Systems of Measurement

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

πŸ“˜ Multiply and Divide Integers

New Concept

Master multiplying and dividing integers using one simple rule: same signs yield a positive result, while different signs yield a negative. This skill is key to simplifying expressions, evaluating variables, and solving real-world application problems.

What’s next

Next, you'll apply these rules through interactive examples and practice cards, building your confidence to solve more complex algebraic problems.

Section 2

Multiplication of Signed Numbers

Property

For multiplication of two signed numbers:

  • If the signs are the same, the product is positive.
  • If the signs are different, the product is negative.

Same Signs (Product is Positive)

  • Two positives: 7β‹…4=287 \cdot 4 = 28
  • Two negatives: βˆ’8(βˆ’6)=48-8(-6) = 48

Different Signs (Product is Negative)

  • Positive β‹…\cdot negative: 7(βˆ’9)=βˆ’637(-9) = -63
  • Negative β‹…\cdot positive: βˆ’5β‹…10=βˆ’50-5 \cdot 10 = -50

Section 3

Division of Signed Numbers

Property

Division is the inverse operation of multiplication. For division of two signed numbers, the rules are the same as for multiplication:

  • If the signs are the same, the result is positive.
  • If the signs are different, the result is negative.

Examples

  • To divide βˆ’45Γ·9-45 \div 9, the signs are different, so the quotient is negative. The result is βˆ’5-5.
  • To divide βˆ’72Γ·(βˆ’8)-72 \div (-8), the signs are the same, so the quotient is positive. The result is 99.
  • To divide 100Γ·(βˆ’25)100 \div (-25), the signs are different, so the quotient is negative. The result is βˆ’4-4.

Explanation

Division uses the exact same sign rules as multiplication. If you know that a negative times a negative is a positive, then you also know that a negative divided by a negative is a positive. The rules are consistent!

Section 4

Simplify Expressions with Integers

Property

The order of operations (PEMDAS/BODMAS) still applies when integers are included. When simplifying expressions, perform operations in the correct sequence: Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

Be aware of the difference with exponents:

  • (βˆ’a)n(-a)^n means the base is βˆ’a-a.
  • βˆ’an-a^n means the base is aa, and you find the opposite of the result.

Examples

  • To simplify 15βˆ’4(2βˆ’9)15 - 4(2 - 9), first solve the parenthesis: 15βˆ’4(βˆ’7)15 - 4(-7). Then multiply: 15βˆ’(βˆ’28)15 - (-28). Finally, subtract: 15+28=4315 + 28 = 43.
  • To simplify (βˆ’5)2βˆ’30Γ·(10βˆ’4)(-5)^2 - 30 \div (10-4), handle the exponent and parenthesis first: 25βˆ’30Γ·625 - 30 \div 6. Then divide: 25βˆ’5=2025 - 5 = 20.
  • To simplify 9(βˆ’4)Γ·(βˆ’2)39(-4) \div (-2)^3, first evaluate the exponent: 9(βˆ’4)Γ·(βˆ’8)9(-4) \div (-8). Then multiply: βˆ’36Γ·(βˆ’8)=4.5-36 \div (-8) = 4.5.

Section 5

Evaluate Variable Expressions

Property

To evaluate a variable expression means to substitute a number for the variable in the expression and then simplify the resulting expression. When substituting negative numbers, it is often helpful to use parentheses to ensure the operations are performed correctly.

Examples

  • To evaluate 3x2+5xβˆ’13x^2 + 5x - 1 when x=βˆ’2x = -2, substitute to get 3(βˆ’2)2+5(βˆ’2)βˆ’13(-2)^2 + 5(-2) - 1. This simplifies to 3(4)βˆ’10βˆ’1=12βˆ’10βˆ’1=13(4) - 10 - 1 = 12 - 10 - 1 = 1.
  • To evaluate (a+b)2(a+b)^2 when a=βˆ’10a = -10 and b=7b = 7, substitute to get (βˆ’10+7)2(-10+7)^2. This simplifies to (βˆ’3)2=9(-3)^2 = 9.
  • To evaluate 50βˆ’y50 - y when y=βˆ’15y = -15, substitute to get 50βˆ’(βˆ’15)50 - (-15). This simplifies to 50+15=6550 + 15 = 65.

Explanation

Evaluating an expression is like plugging a specific value into a template. The variable is a placeholder, and you replace it with the given number. Using parentheses, especially for negative numbers, prevents mistakes with signs and exponents.

Section 6

Translate Phrases to Expressions

Property

Translating English phrases to algebra involves recognizing keywords for operations. Key words for multiplication and division include:

  • Product: Indicates multiplication (e.g., 'the product of aa and bb' is aβ‹…ba \cdot b).
  • Quotient: Indicates division (e.g., 'the quotient of aa and bb' is aΓ·ba \div b or ab\frac{a}{b}).

Be careful with subtraction order: 'the difference of aa and bb' is aβˆ’ba-b, but 'bb subtracted from aa' is also aβˆ’ba-b.

Examples

  • The phrase 'the product of βˆ’8-8 and 1212' translates to the expression (βˆ’8)(12)(-8)(12), which simplifies to βˆ’96-96.
  • The phrase 'the quotient of βˆ’100-100 and βˆ’4-4' translates to the expression βˆ’100Γ·(βˆ’4)-100 \div (-4), which simplifies to 2525.
  • The phrase 'the sum of βˆ’5-5 and 33, increased by 1010' translates to [βˆ’5+3]+10[-5 + 3] + 10, which simplifies to βˆ’2+10=8-2 + 10 = 8.

Explanation

This skill is like translating from one language to another. Words like 'product' and 'quotient' are direct signals for multiplication and division. Reading carefully helps put the numbers and operations in the correct order to match the phrase.

Section 7

Solving Integer Applications

Property

To solve applications with integers, use a structured approach:

  1. Read the problem to understand all words and ideas.
  2. Identify what you are asked to find.
  3. Write a phrase that gives the information to find it.
  4. Translate the phrase into a mathematical expression.
  5. Simplify the expression.
  6. Answer the question with a complete sentence.

Examples

  • A scuba diver descends 20 feet per minute for 5 minutes. To find her change in depth, translate '5 times a 20-foot descent' to 5(βˆ’20)5(-20). The change is βˆ’100-100 feet.
  • A company had a total loss of 6,000 dollars over 4 months. To find the average monthly loss, translate 'the quotient of βˆ’6000-6000 and 44' to βˆ’6000Γ·4-6000 \div 4. The average loss was 1,500 dollars per month.
  • The temperature at noon was 5∘5^\circC. By midnight, it dropped to βˆ’11∘-11^\circC. The difference is 5βˆ’(βˆ’11)=16∘5 - (-11) = 16^\circC.

Explanation

This six-step plan turns a word problem into a straightforward math problem. It helps you organize your thoughts, translate the situation into an expression, solve it, and then state the answer clearly in the context of the original problem.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 1: Foundations

  1. Lesson 1

    Lesson 1.1: Introduction to Whole Numbers

  2. Lesson 2

    Lesson 1.2: Use the Language of Algebra

  3. Lesson 3

    Lesson 1.3: Add and Subtract Integers

  4. Lesson 4Current

    Lesson 1.4: Multiply and Divide Integers

  5. Lesson 5

    Lesson 1.5: Visualize Fractions

  6. Lesson 6

    Lesson 1.6: Add and Subtract Fractions

  7. Lesson 7

    Lesson 1.7: Decimals

  8. Lesson 8

    Lesson 1.8: The Real Numbers

  9. Lesson 9

    Lesson 1.9: Properties of Real Numbers

  10. Lesson 10

    Lesson 1.10: Systems of Measurement