Learn on PengiBig Ideas Math, Advanced 2Chapter 8: Volume and Similar Solids

Section 8.2: Volumes of Cones

In this Grade 7 lesson from Big Ideas Math Advanced 2, students learn to calculate the volume of a cone using the formula V = ⅓Bh (equivalently V = ⅓πr²h), discovering through hands-on exploration that a cone holds exactly one-third the volume of a cylinder with the same base and height. Students practice finding cone volumes and working backwards to find unknown heights when volume is given. The lesson also extends the formula to oblique cones and applies volume concepts to real-life problems.

Section 1

Volume of a cone

Property

A cone is a solid figure with one circular base and a vertex. For a cone with radius rr and height hh:

Volume: V=13πr2hV = \frac{1}{3}\pi r^2 h

Examples

  • To find the volume of a cone with a height of 6 inches and a base radius of 2 inches, use V=13πr2hV = \frac{1}{3}\pi r^2 h. With π3.14\pi \approx 3.14, the volume is V13(3.14)(22)(6)25.12V \approx \frac{1}{3}(3.14)(2^2)(6) \approx 25.12 cubic inches.

Section 2

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Book overview

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Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Section 8.1: Volumes of Cylinders

  2. Lesson 2Current

    Section 8.2: Volumes of Cones

  3. Lesson 3

    Section 8.3: Volumes of Spheres

  4. Lesson 4

    Section 8.4: Surface Areas and Volumes of Similar Solids

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Volume of a cone

Property

A cone is a solid figure with one circular base and a vertex. For a cone with radius rr and height hh:

Volume: V=13πr2hV = \frac{1}{3}\pi r^2 h

Examples

  • To find the volume of a cone with a height of 6 inches and a base radius of 2 inches, use V=13πr2hV = \frac{1}{3}\pi r^2 h. With π3.14\pi \approx 3.14, the volume is V13(3.14)(22)(6)25.12V \approx \frac{1}{3}(3.14)(2^2)(6) \approx 25.12 cubic inches.

Section 2

Relationship Between Cone and Cylinder Volumes

Property

A cone has exactly one-third the volume of a cylinder with the same base and height: Vcone=13VcylinderV_{cone} = \frac{1}{3} \cdot V_{cylinder}

If cylinder volume is Vcylinder=πr2hV_{cylinder} = \pi r^2 h, then cone volume is Vcone=13πr2hV_{cone} = \frac{1}{3}\pi r^2 h

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 8: Volume and Similar Solids

  1. Lesson 1

    Section 8.1: Volumes of Cylinders

  2. Lesson 2Current

    Section 8.2: Volumes of Cones

  3. Lesson 3

    Section 8.3: Volumes of Spheres

  4. Lesson 4

    Section 8.4: Surface Areas and Volumes of Similar Solids