Learn on PengiBig Ideas Math, Advanced 2Chapter 14: Surface Area and Volume

Section 14.4: Volumes of Prisms

In this Grade 7 lesson from Big Ideas Math Advanced 2, students learn to calculate the volume of prisms using the formula V = Bh, where B is the area of the base and h is the height. The lesson covers both rectangular and triangular prisms, including real-life applications such as finding unknown dimensions when volume is known. Students also practice connecting volume calculations to surface area in practical problem-solving contexts.

Section 1

Evaluating Volume Formulas for Prisms

Property

Evaluate expressions at specific values of their variables. Include expressions that arise from volume formulas used in real-world problems. Perform arithmetic operations, including those involving whole-number exponents, in the conventional order when there are no parentheses to specify a particular order (Order of Operations). For example, use the formulas V=s3V=s^3 for a cube and V=lwhV=lwh for a rectangular prism to find volumes.

Examples

  • Find the volume of a cube with side length s=4s = 4 cm using the formula V=s3V=s^3. Substitute s=4s=4 to get V=43=444=64V = 4^3 = 4 \cdot 4 \cdot 4 = 64 cubic cm.
  • Find the volume of a rectangular prism with length l=6l = 6 ft, width w=3w = 3 ft, and height h=2h = 2 ft using the formula V=lwhV=lwh. Substitute the values to get V=632=36V = 6 \cdot 3 \cdot 2 = 36 cubic ft.
  • The volume of a cube is V=s3V=s^3. If the side length ss is 2.52.5 meters, the volume is V=(2.5)3=2.52.52.5=15.625V = (2.5)^3 = 2.5 \cdot 2.5 \cdot 2.5 = 15.625 cubic meters.

Explanation

To evaluate a volume expression, you replace each variable with its given number and solve using order of operations. It's like using a recipe: the volume formula is your instructions, the variable values are your ingredients, and the final answer is your finished calculation. Always remember that volume is measured in cubic units.

Section 2

Volume of a Prism Using Base Area

Property

The volume of a prism is the product of the height by the area of the base.
That is, if the area of the base is BB and the height is hh, volume is V=BhV = Bh.

Examples

  • A rectangular prism with a base of 5 cm×6 cm5 \text{ cm} \times 6 \text{ cm} and a height of 12 cm12 \text{ cm} has a volume of V=(5×6)×12=360 cm3V = (5 \times 6) \times 12 = 360 \text{ cm}^3.
  • A triangular prism has a base area of 30 in230 \text{ in}^2 and a height of 7 in7 \text{ in}. Its volume is V=30×7=210 in3V = 30 \times 7 = 210 \text{ in}^3.

Section 3

Volume Calculation for Prisms

Property

The volume of any prism can be calculated using the formula V=B×hV = B \times h, where BB is the area of the base and hh is the height. Different prisms with the same base area and height will have the same volume, regardless of the shape of their base.

Examples

Book overview

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Chapter 14: Surface Area and Volume

  1. Lesson 1

    Section 14.1: Surface Areas of Prisms

  2. Lesson 2

    Section 14.2: Surface Areas of Pyramids

  3. Lesson 3

    Section 14.3: Surface Areas of Cylinders

  4. Lesson 4Current

    Section 14.4: Volumes of Prisms

  5. Lesson 5

    Section 14.5: Volumes of Pyramids

Lesson overview

Expand to review the lesson summary and core properties.

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Section 1

Evaluating Volume Formulas for Prisms

Property

Evaluate expressions at specific values of their variables. Include expressions that arise from volume formulas used in real-world problems. Perform arithmetic operations, including those involving whole-number exponents, in the conventional order when there are no parentheses to specify a particular order (Order of Operations). For example, use the formulas V=s3V=s^3 for a cube and V=lwhV=lwh for a rectangular prism to find volumes.

Examples

  • Find the volume of a cube with side length s=4s = 4 cm using the formula V=s3V=s^3. Substitute s=4s=4 to get V=43=444=64V = 4^3 = 4 \cdot 4 \cdot 4 = 64 cubic cm.
  • Find the volume of a rectangular prism with length l=6l = 6 ft, width w=3w = 3 ft, and height h=2h = 2 ft using the formula V=lwhV=lwh. Substitute the values to get V=632=36V = 6 \cdot 3 \cdot 2 = 36 cubic ft.
  • The volume of a cube is V=s3V=s^3. If the side length ss is 2.52.5 meters, the volume is V=(2.5)3=2.52.52.5=15.625V = (2.5)^3 = 2.5 \cdot 2.5 \cdot 2.5 = 15.625 cubic meters.

Explanation

To evaluate a volume expression, you replace each variable with its given number and solve using order of operations. It's like using a recipe: the volume formula is your instructions, the variable values are your ingredients, and the final answer is your finished calculation. Always remember that volume is measured in cubic units.

Section 2

Volume of a Prism Using Base Area

Property

The volume of a prism is the product of the height by the area of the base.
That is, if the area of the base is BB and the height is hh, volume is V=BhV = Bh.

Examples

  • A rectangular prism with a base of 5 cm×6 cm5 \text{ cm} \times 6 \text{ cm} and a height of 12 cm12 \text{ cm} has a volume of V=(5×6)×12=360 cm3V = (5 \times 6) \times 12 = 360 \text{ cm}^3.
  • A triangular prism has a base area of 30 in230 \text{ in}^2 and a height of 7 in7 \text{ in}. Its volume is V=30×7=210 in3V = 30 \times 7 = 210 \text{ in}^3.

Section 3

Volume Calculation for Prisms

Property

The volume of any prism can be calculated using the formula V=B×hV = B \times h, where BB is the area of the base and hh is the height. Different prisms with the same base area and height will have the same volume, regardless of the shape of their base.

Examples

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 14: Surface Area and Volume

  1. Lesson 1

    Section 14.1: Surface Areas of Prisms

  2. Lesson 2

    Section 14.2: Surface Areas of Pyramids

  3. Lesson 3

    Section 14.3: Surface Areas of Cylinders

  4. Lesson 4Current

    Section 14.4: Volumes of Prisms

  5. Lesson 5

    Section 14.5: Volumes of Pyramids