Learn on PengiBig Ideas Math, Advanced 2Chapter 14: Surface Area and Volume

Section 14.1: Surface Areas of Prisms

In this Grade 7 lesson from Big Ideas Math Advanced 2, students learn how to find the surface area of rectangular prisms, triangular prisms, and cubes using the formulas S = 2ℓw + 2ℓh + 2wh and S = 6s², as well as the general method of summing base areas and lateral face areas. Students use two-dimensional nets to visualize and calculate surface area for three-dimensional solids. The lesson is part of Chapter 14: Surface Area and Volume.

Section 1

Area of Rectangles and Triangles

Property

The calculation of areas is based on these principles:

  1. If you move a shape rigidly (without stretching or distorting it), then its area does not change.
  2. If you combine shapes without overlapping them, then the area of the resulting shape is the sum of the areas of the individual shapes.

Formulas:

  • Rectangle: With side lengths aa and bb, the area is A=abA = ab.
  • Triangle: With base bb and height hh, the area is A=12bhA = \frac{1}{2}bh.

Examples

  • A rectangular face of a box is 6 inches long and 4 inches wide. Its area is 6×4=246 \times 4 = 24 square inches.
  • A triangular face of a prism has a base of 8 centimeters and a height of 5 centimeters. Its area is 12×8×5=20\frac{1}{2} \times 8 \times 5 = 20 square centimeters.
  • The rectangular base of a prism measures 12 feet by 7 feet. Its area is 12×7=8412 \times 7 = 84 square feet.

Explanation

Area measures the total space inside a 2D shape. When finding the surface area of prisms, we need to calculate the areas of rectangular and triangular faces. We can find the area of more complex polygon faces by breaking them into rectangles and triangles, then adding their areas together.

Section 2

Surface Area Formulas for Prisms

Property

Cube whose edge is of length LL:
Surface Area =6L2= 6L^2
Rectangular Prism of length LL, height HH and width WW:
Surface Area =2(LW+LH+WH)= 2(LW + LH + WH)
Triangular Prism of height HH based on a triangle with side lengths AA, BB, CC and base area BareaB_{area}:
Surface Area =2Barea+(A+B+C)H= 2B_{area} + (A + B + C)H

Examples

  • A cube with an edge length of 4 cm has a Surface Area of 6(42)=6×16=966(4^2) = 6 \times 16 = 96 square cm.
  • A rectangular prism is 5 in long, 3 in wide, and 6 in high. Its Surface Area is 2(5×3+5×6+3×6)=2(15+30+18)=1262(5 \times 3 + 5 \times 6 + 3 \times 6) = 2(15 + 30 + 18) = 126 square in.
  • A triangular prism is 8 cm high and its base is a right triangle with legs 3 cm and 4 cm, and hypotenuse 5 cm. The base area is 12(3×4)=6\frac{1}{2}(3 \times 4) = 6 square cm. Its Surface Area is 2(6)+(3+4+5)(8)=12+96=1082(6) + (3+4+5)(8) = 12 + 96 = 108 square cm.

Explanation

Surface area measures the total area of all the outside faces of a 3D shape. Think of it as how much wrapping paper you would need to completely cover the object. For prisms, we calculate the area of all faces and add them together using these formulas.

Section 3

Lateral Surface Area of Prisms

Property

Lateral surface area is the sum of the areas of only the side faces of a prism, excluding the top and bottom bases.

For rectangular prisms: L=2h+2whL = 2\ell h + 2wh where \ell is length, ww is width, and hh is height.

Section 4

Evaluating Surface Area Formulas

Property

Evaluate expressions at specific values of their variables. Include expressions that arise from formulas used in real-world problems. Perform arithmetic operations, including those involving whole-number exponents, in the conventional order when there are no parentheses to specify a particular order (Order of Operations). For example, use the formulas V=s3V=s^3 and A=6s2A=6s^2 to find the volume and surface area of a cube.

Examples

  • Find the volume of a cube with side length s=5s = 5 cm using the formula V=s3V=s^3. Substitute s=5s=5 to get V=53=555=125V = 5^3 = 5 \cdot 5 \cdot 5 = 125 cubic cm.
  • Find the surface area of a cube with side length s=3s = 3 ft using the formula A=6s2A=6s^2. Substitute s=3s=3 to get A=6(32)=69=54A = 6 \cdot (3^2) = 6 \cdot 9 = 54 square ft.
  • The area of a square is A=s2A=s^2. If the side length ss is 1.21.2 meters, the area is A=(1.2)2=1.44A = (1.2)^2 = 1.44 square meters.

Explanation

To evaluate an expression, you replace the variable with its given number and solve. It's like using a recipe: the formula is your instructions, the variable's value is your ingredient, and the final answer is your finished dish.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 14: Surface Area and Volume

  1. Lesson 1Current

    Section 14.1: Surface Areas of Prisms

  2. Lesson 2

    Section 14.2: Surface Areas of Pyramids

  3. Lesson 3

    Section 14.3: Surface Areas of Cylinders

  4. Lesson 4

    Section 14.4: Volumes of Prisms

  5. Lesson 5

    Section 14.5: Volumes of Pyramids

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Area of Rectangles and Triangles

Property

The calculation of areas is based on these principles:

  1. If you move a shape rigidly (without stretching or distorting it), then its area does not change.
  2. If you combine shapes without overlapping them, then the area of the resulting shape is the sum of the areas of the individual shapes.

Formulas:

  • Rectangle: With side lengths aa and bb, the area is A=abA = ab.
  • Triangle: With base bb and height hh, the area is A=12bhA = \frac{1}{2}bh.

Examples

  • A rectangular face of a box is 6 inches long and 4 inches wide. Its area is 6×4=246 \times 4 = 24 square inches.
  • A triangular face of a prism has a base of 8 centimeters and a height of 5 centimeters. Its area is 12×8×5=20\frac{1}{2} \times 8 \times 5 = 20 square centimeters.
  • The rectangular base of a prism measures 12 feet by 7 feet. Its area is 12×7=8412 \times 7 = 84 square feet.

Explanation

Area measures the total space inside a 2D shape. When finding the surface area of prisms, we need to calculate the areas of rectangular and triangular faces. We can find the area of more complex polygon faces by breaking them into rectangles and triangles, then adding their areas together.

Section 2

Surface Area Formulas for Prisms

Property

Cube whose edge is of length LL:
Surface Area =6L2= 6L^2
Rectangular Prism of length LL, height HH and width WW:
Surface Area =2(LW+LH+WH)= 2(LW + LH + WH)
Triangular Prism of height HH based on a triangle with side lengths AA, BB, CC and base area BareaB_{area}:
Surface Area =2Barea+(A+B+C)H= 2B_{area} + (A + B + C)H

Examples

  • A cube with an edge length of 4 cm has a Surface Area of 6(42)=6×16=966(4^2) = 6 \times 16 = 96 square cm.
  • A rectangular prism is 5 in long, 3 in wide, and 6 in high. Its Surface Area is 2(5×3+5×6+3×6)=2(15+30+18)=1262(5 \times 3 + 5 \times 6 + 3 \times 6) = 2(15 + 30 + 18) = 126 square in.
  • A triangular prism is 8 cm high and its base is a right triangle with legs 3 cm and 4 cm, and hypotenuse 5 cm. The base area is 12(3×4)=6\frac{1}{2}(3 \times 4) = 6 square cm. Its Surface Area is 2(6)+(3+4+5)(8)=12+96=1082(6) + (3+4+5)(8) = 12 + 96 = 108 square cm.

Explanation

Surface area measures the total area of all the outside faces of a 3D shape. Think of it as how much wrapping paper you would need to completely cover the object. For prisms, we calculate the area of all faces and add them together using these formulas.

Section 3

Lateral Surface Area of Prisms

Property

Lateral surface area is the sum of the areas of only the side faces of a prism, excluding the top and bottom bases.

For rectangular prisms: L=2h+2whL = 2\ell h + 2wh where \ell is length, ww is width, and hh is height.

Section 4

Evaluating Surface Area Formulas

Property

Evaluate expressions at specific values of their variables. Include expressions that arise from formulas used in real-world problems. Perform arithmetic operations, including those involving whole-number exponents, in the conventional order when there are no parentheses to specify a particular order (Order of Operations). For example, use the formulas V=s3V=s^3 and A=6s2A=6s^2 to find the volume and surface area of a cube.

Examples

  • Find the volume of a cube with side length s=5s = 5 cm using the formula V=s3V=s^3. Substitute s=5s=5 to get V=53=555=125V = 5^3 = 5 \cdot 5 \cdot 5 = 125 cubic cm.
  • Find the surface area of a cube with side length s=3s = 3 ft using the formula A=6s2A=6s^2. Substitute s=3s=3 to get A=6(32)=69=54A = 6 \cdot (3^2) = 6 \cdot 9 = 54 square ft.
  • The area of a square is A=s2A=s^2. If the side length ss is 1.21.2 meters, the area is A=(1.2)2=1.44A = (1.2)^2 = 1.44 square meters.

Explanation

To evaluate an expression, you replace the variable with its given number and solve. It's like using a recipe: the formula is your instructions, the variable's value is your ingredient, and the final answer is your finished dish.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 14: Surface Area and Volume

  1. Lesson 1Current

    Section 14.1: Surface Areas of Prisms

  2. Lesson 2

    Section 14.2: Surface Areas of Pyramids

  3. Lesson 3

    Section 14.3: Surface Areas of Cylinders

  4. Lesson 4

    Section 14.4: Volumes of Prisms

  5. Lesson 5

    Section 14.5: Volumes of Pyramids