Learn on PengiSaxon Math, Course 2Chapter 7: Lessons 61-70, Investigation 7

Lesson 70: Volume

New Concept Volume describes the space an object occupies, measured in cubic units. The formula for the volume ($V$) of a rectangular prism is: $$V = lwh$$ What’s next To start, we'll explore volume more deeply. Next, you’ll apply the volume formula in worked examples and practice problems involving rectangular prisms and other solids.

Section 1

📘 Volume

New Concept

Volume describes the space an object occupies, measured in cubic units. The formula for the volume (VV) of a rectangular prism is:

V=lwhV = lwh

What’s next

To start, we'll explore volume more deeply. Next, you’ll apply the volume formula in worked examples and practice problems involving rectangular prisms and other solids.

Section 2

Volume

Property

Volume is the space occupied by a shape. We measure it using cubic units, such as 1 cm31 \text{ cm}^3 (one cubic centimeter), 1 ft31 \text{ ft}^3 (one cubic foot), or 1 m31 \text{ m}^3 (one cubic meter).

Examples

A rectangular prism constructed with 4 layers of cubes, where each layer has 3 rows of 5 cubes, has a volume of 4×(3×5)=604 \times (3 \times 5) = 60 cubes.
A box that holds 25 cubes on its base and is 4 layers high has a volume of 25×4=10025 \times 4 = 100 cubes.

Explanation

Think of volume as counting how many tiny building blocks, or unit cubes, fit inside a 3D shape. First, you figure out how many cubes cover the bottom layer, then you multiply that by the number of layers. It's like stacking pancakes, but with cubes! A shape's volume is its total cube count.

Section 3

Volume of a Rectangular Prism

Property

The formula to find the volume (VV) of a rectangular prism with length (ll), width (ww), and height (hh) is:

V=lwhV = lwh

Examples

A box with dimensions 6 cm long, 4 cm wide, and 2 cm high has a volume of V=6 cm×4 cm×2 cm=48 cm3V = 6 \text{ cm} \times 4 \text{ cm} \times 2 \text{ cm} = 48 \text{ cm}^3.
A prism with dimensions 10 feet, 5 feet, and 4 feet has a volume of V=10 ft×5 ft×4 ft=200 ft3V = 10 \text{ ft} \times 5 \text{ ft} \times 4 \text{ ft} = 200 \text{ ft}^3.

Explanation

Forget counting every single cube! Just multiply the three key measurements: length, width, and height. This formula is a super-fast shortcut to find the total number of cubes that would fill up any box-shaped object. It's the ultimate secret code for finding the space inside a rectangular prism. It is truly math magic!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Lessons 61-70, Investigation 7

  1. Lesson 1

    Lesson 61: Area of a Parallelogram, Angles of a Parallelogram

  2. Lesson 2

    Lesson 62: Classifying Triangles

  3. Lesson 3

    Lesson 63: Symbols of Inclusion

  4. Lesson 4

    Lesson 64: Adding Positive and Negative Numbers

  5. Lesson 5

    Lesson 65: Circumference and Pi

  6. Lesson 6

    Lesson 66: Ratio Problems Involving Totals

  7. Lesson 7

    Lesson 67: Geometric Solids

  8. Lesson 8

    Lesson 68: Algebraic Addition

  9. Lesson 9

    Lesson 69: Proper Form of Scientific Notation

  10. Lesson 10Current

    Lesson 70: Volume

  11. Lesson 11

    Investigation 7: Balanced Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Volume

New Concept

Volume describes the space an object occupies, measured in cubic units. The formula for the volume (VV) of a rectangular prism is:

V=lwhV = lwh

What’s next

To start, we'll explore volume more deeply. Next, you’ll apply the volume formula in worked examples and practice problems involving rectangular prisms and other solids.

Section 2

Volume

Property

Volume is the space occupied by a shape. We measure it using cubic units, such as 1 cm31 \text{ cm}^3 (one cubic centimeter), 1 ft31 \text{ ft}^3 (one cubic foot), or 1 m31 \text{ m}^3 (one cubic meter).

Examples

A rectangular prism constructed with 4 layers of cubes, where each layer has 3 rows of 5 cubes, has a volume of 4×(3×5)=604 \times (3 \times 5) = 60 cubes.
A box that holds 25 cubes on its base and is 4 layers high has a volume of 25×4=10025 \times 4 = 100 cubes.

Explanation

Think of volume as counting how many tiny building blocks, or unit cubes, fit inside a 3D shape. First, you figure out how many cubes cover the bottom layer, then you multiply that by the number of layers. It's like stacking pancakes, but with cubes! A shape's volume is its total cube count.

Section 3

Volume of a Rectangular Prism

Property

The formula to find the volume (VV) of a rectangular prism with length (ll), width (ww), and height (hh) is:

V=lwhV = lwh

Examples

A box with dimensions 6 cm long, 4 cm wide, and 2 cm high has a volume of V=6 cm×4 cm×2 cm=48 cm3V = 6 \text{ cm} \times 4 \text{ cm} \times 2 \text{ cm} = 48 \text{ cm}^3.
A prism with dimensions 10 feet, 5 feet, and 4 feet has a volume of V=10 ft×5 ft×4 ft=200 ft3V = 10 \text{ ft} \times 5 \text{ ft} \times 4 \text{ ft} = 200 \text{ ft}^3.

Explanation

Forget counting every single cube! Just multiply the three key measurements: length, width, and height. This formula is a super-fast shortcut to find the total number of cubes that would fill up any box-shaped object. It's the ultimate secret code for finding the space inside a rectangular prism. It is truly math magic!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Lessons 61-70, Investigation 7

  1. Lesson 1

    Lesson 61: Area of a Parallelogram, Angles of a Parallelogram

  2. Lesson 2

    Lesson 62: Classifying Triangles

  3. Lesson 3

    Lesson 63: Symbols of Inclusion

  4. Lesson 4

    Lesson 64: Adding Positive and Negative Numbers

  5. Lesson 5

    Lesson 65: Circumference and Pi

  6. Lesson 6

    Lesson 66: Ratio Problems Involving Totals

  7. Lesson 7

    Lesson 67: Geometric Solids

  8. Lesson 8

    Lesson 68: Algebraic Addition

  9. Lesson 9

    Lesson 69: Proper Form of Scientific Notation

  10. Lesson 10Current

    Lesson 70: Volume

  11. Lesson 11

    Investigation 7: Balanced Equations