Learn on PengienVision, Algebra 1Chapter 9: Solving Quadratic Equations

Lesson 7: Solving Nonlinear Systems of Equations

In this Grade 11 Algebra 1 lesson from enVision Chapter 9, students learn how to solve linear-quadratic systems of equations — systems that pair one linear equation with one quadratic equation — using graphing, elimination, and substitution methods. Students explore why a line and a parabola can intersect at 0, 1, or 2 points, connecting this to the number of real solutions a system can have. The lesson applies these techniques to real-world contexts such as modeling projected sales data.

Section 1

Linear-Quadratic System Definition

Property

A linear-quadratic system of equations consists of one linear equation and one quadratic equation. The general form of such a system is:

{y=ax2+bx+cy=mx+d\begin{cases} y = ax^2 + bx + c \\ y = mx + d \end{cases}

Examples

  • A system with a parabola and a line:
{y=x24x+5y=x+1\begin{cases} y = x^2 - 4x + 5 \\ y = x + 1 \end{cases}
  • A system where the linear equation is not in slope-intercept form:
{y=x2+62x+y=3\begin{cases} y = -x^2 + 6 \\ 2x + y = 3 \end{cases}

Explanation

A linear-quadratic system pairs a quadratic equation, which graphs as a parabola, with a linear equation, which graphs as a straight line. The solutions to the system are the points where the parabola and the line intersect. Because a line can cross a parabola in at most two places, there can be zero, one, or two real solutions. These systems model situations where a linear path or rate interacts with a parabolic trajectory.

Section 2

Solve Linear-Quadratic Systems by Graphing

Property

To solve a linear-quadratic system by graphing:

Step 1. Identify that one equation is linear and one is quadratic.
Step 2. Graph the linear equation (line).
Step 3. Graph the quadratic equation (parabola) on the same coordinate system.
Step 4. Determine whether the graphs intersect.
Step 5. Identify the points of intersection.
Step 6. Check that each ordered pair satisfies both original equations.

Section 3

Solve Linear-Quadratic Systems by Substitution

Property

To solve a linear-quadratic system by substitution:

Step 1. Identify which equation is linear and which is quadratic.
Step 2. Solve the linear equation for either variable.
Step 3. Substitute the expression from Step 2 into the quadratic equation.
Step 4. Solve the resulting quadratic equation.
Step 5. Substitute each solution from Step 4 into the linear equation to find the other variable.
Step 6. Write each solution as an ordered pair and check it in both original equations.

Section 4

Solve Linear-Quadratic Systems by Elimination

Property

To solve a linear-quadratic system by elimination:

Step 1. Write both equations in standard form.
Step 2. If needed, multiply one or both equations so that the coefficients of one variable are opposites.
Step 3. Add or subtract the equations to eliminate one variable.
Step 4. Solve the resulting equation for the remaining variable.
Step 5. Substitute each solution back into either original equation to find the other variable.
Step 6. Write the solutions as ordered pairs and check in both original equations.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Solving Quadratic Equations

  1. Lesson 1

    Lesson 1: Solving Quadratic Equations Using Graphs and Tables

  2. Lesson 2

    Lesson 2: Solving Quadratic Equations by Factoring

  3. Lesson 3

    Lesson 3: Rewriting Radical Expressions

  4. Lesson 4

    Lesson 4: Solving Quadratic Equations Using Square Roots

  5. Lesson 5

    Lesson 5: Completing the Square

  6. Lesson 6

    Lesson 6: The Quadratic Formula and the Discriminant

  7. Lesson 7Current

    Lesson 7: Solving Nonlinear Systems of Equations

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Linear-Quadratic System Definition

Property

A linear-quadratic system of equations consists of one linear equation and one quadratic equation. The general form of such a system is:

{y=ax2+bx+cy=mx+d\begin{cases} y = ax^2 + bx + c \\ y = mx + d \end{cases}

Examples

  • A system with a parabola and a line:
{y=x24x+5y=x+1\begin{cases} y = x^2 - 4x + 5 \\ y = x + 1 \end{cases}
  • A system where the linear equation is not in slope-intercept form:
{y=x2+62x+y=3\begin{cases} y = -x^2 + 6 \\ 2x + y = 3 \end{cases}

Explanation

A linear-quadratic system pairs a quadratic equation, which graphs as a parabola, with a linear equation, which graphs as a straight line. The solutions to the system are the points where the parabola and the line intersect. Because a line can cross a parabola in at most two places, there can be zero, one, or two real solutions. These systems model situations where a linear path or rate interacts with a parabolic trajectory.

Section 2

Solve Linear-Quadratic Systems by Graphing

Property

To solve a linear-quadratic system by graphing:

Step 1. Identify that one equation is linear and one is quadratic.
Step 2. Graph the linear equation (line).
Step 3. Graph the quadratic equation (parabola) on the same coordinate system.
Step 4. Determine whether the graphs intersect.
Step 5. Identify the points of intersection.
Step 6. Check that each ordered pair satisfies both original equations.

Section 3

Solve Linear-Quadratic Systems by Substitution

Property

To solve a linear-quadratic system by substitution:

Step 1. Identify which equation is linear and which is quadratic.
Step 2. Solve the linear equation for either variable.
Step 3. Substitute the expression from Step 2 into the quadratic equation.
Step 4. Solve the resulting quadratic equation.
Step 5. Substitute each solution from Step 4 into the linear equation to find the other variable.
Step 6. Write each solution as an ordered pair and check it in both original equations.

Section 4

Solve Linear-Quadratic Systems by Elimination

Property

To solve a linear-quadratic system by elimination:

Step 1. Write both equations in standard form.
Step 2. If needed, multiply one or both equations so that the coefficients of one variable are opposites.
Step 3. Add or subtract the equations to eliminate one variable.
Step 4. Solve the resulting equation for the remaining variable.
Step 5. Substitute each solution back into either original equation to find the other variable.
Step 6. Write the solutions as ordered pairs and check in both original equations.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 9: Solving Quadratic Equations

  1. Lesson 1

    Lesson 1: Solving Quadratic Equations Using Graphs and Tables

  2. Lesson 2

    Lesson 2: Solving Quadratic Equations by Factoring

  3. Lesson 3

    Lesson 3: Rewriting Radical Expressions

  4. Lesson 4

    Lesson 4: Solving Quadratic Equations Using Square Roots

  5. Lesson 5

    Lesson 5: Completing the Square

  6. Lesson 6

    Lesson 6: The Quadratic Formula and the Discriminant

  7. Lesson 7Current

    Lesson 7: Solving Nonlinear Systems of Equations