Learn on PengiBig Ideas Math, Algebra 1Chapter 7: Polynomial Equations and Factoring

Lesson 7: Factoring Special Products

Property 1. $a^2 + 2ab + b^2 = (a + b)^2$.

Section 1

Factoring Special Products

Property

  1. a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2
  1. a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2
  1. a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b)

Section 2

Factor Differences of Squares

Property

If aa and bb are real numbers, a difference of squares factors to a product of conjugates using the following pattern:

a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)

To use this pattern, ensure you have a binomial where two perfect squares are being subtracted.
Write each term as a square, (a)2(b)2(a)^2 - (b)^2, then write the product of the conjugates, (ab)(a+b)(a-b)(a+b).
Note that a sum of squares, a2+b2a^2+b^2, is prime and cannot be factored.

Examples

  • To factor 9x2259x^2 - 25, rewrite the expression as a difference of squares, (3x)252(3x)^2 - 5^2. This factors into the product of conjugates (3x5)(3x+5)(3x-5)(3x+5).
  • To factor 16a281b216a^2 - 81b^2, identify the terms as (4a)2(4a)^2 and (9b)2(9b)^2. The factored form is the product of their conjugates, (4a9b)(4a+9b)(4a-9b)(4a+9b).

Book overview

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Chapter 7: Polynomial Equations and Factoring

  1. Lesson 1

    Lesson 1: Adding and Subtracting Polynomials

  2. Lesson 2

    Lesson 2: Multiplying Polynomials

  3. Lesson 3

    Lesson 3: Special Products of Polynomials

  4. Lesson 4

    Lesson 4: Solving Polynomial Equations in Factored Form

  5. Lesson 5

    Lesson 5: Factoring x² + bx + c

  6. Lesson 6

    Lesson 6: Factoring ax² + bx + c

  7. Lesson 7Current

    Lesson 7: Factoring Special Products

  8. Lesson 8

    Lesson 8: Factoring Polynomials Completely

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

Factoring Special Products

Property

  1. a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2
  1. a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2
  1. a2b2=(a+b)(ab)a^2 - b^2 = (a + b)(a - b)

Section 2

Factor Differences of Squares

Property

If aa and bb are real numbers, a difference of squares factors to a product of conjugates using the following pattern:

a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)

To use this pattern, ensure you have a binomial where two perfect squares are being subtracted.
Write each term as a square, (a)2(b)2(a)^2 - (b)^2, then write the product of the conjugates, (ab)(a+b)(a-b)(a+b).
Note that a sum of squares, a2+b2a^2+b^2, is prime and cannot be factored.

Examples

  • To factor 9x2259x^2 - 25, rewrite the expression as a difference of squares, (3x)252(3x)^2 - 5^2. This factors into the product of conjugates (3x5)(3x+5)(3x-5)(3x+5).
  • To factor 16a281b216a^2 - 81b^2, identify the terms as (4a)2(4a)^2 and (9b)2(9b)^2. The factored form is the product of their conjugates, (4a9b)(4a+9b)(4a-9b)(4a+9b).

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Polynomial Equations and Factoring

  1. Lesson 1

    Lesson 1: Adding and Subtracting Polynomials

  2. Lesson 2

    Lesson 2: Multiplying Polynomials

  3. Lesson 3

    Lesson 3: Special Products of Polynomials

  4. Lesson 4

    Lesson 4: Solving Polynomial Equations in Factored Form

  5. Lesson 5

    Lesson 5: Factoring x² + bx + c

  6. Lesson 6

    Lesson 6: Factoring ax² + bx + c

  7. Lesson 7Current

    Lesson 7: Factoring Special Products

  8. Lesson 8

    Lesson 8: Factoring Polynomials Completely