Learn on PengiOpenStax Algebra and TrigonometryChapter 7: The Unit Circle: Sine and Cosine Functions

Lesson 7.2 : Right Triangle Trigonometry

In this Grade 7 lesson from OpenStax Algebra and Trigonometry, students learn to define and evaluate all six trigonometric functions — sine, cosine, tangent, secant, cosecant, and cotangent — using the ratios of sides in a right triangle, including the mnemonic SohCahToa. The lesson covers finding exact function values for special angles such as 30°, 45°, and 60°, and applying cofunction relationships for complementary angles. Students also use right-triangle trigonometry to solve real-world problems, such as measuring heights and distances.

Section 1

📘 Right Triangle Trigonometry

New Concept

Right triangle trigonometry defines functions like sine and cosine as ratios of a triangle's sides (e.g., sint=oppositehypotenuse\operatorname{sin} t = \frac{\text{opposite}}{\text{hypotenuse}}). This powerful tool helps us find unknown side lengths and angles, and solve practical problems like measuring heights.

What’s next

Next, you’ll master these concepts through a series of practice cards, tackling everything from special angles to real-world challenge problems.

Section 2

Right Triangle Trigonometric Functions

Property

Given a right triangle with an acute angle of tt, the first three trigonometric functions are listed.

FunctionDefinition
Sinesint=oppositehypotenuse\sin t = \dfrac{\text{opposite}}{\text{hypotenuse}}
Cosinecost=adjacenthypotenuse\cos t = \dfrac{\text{adjacent}}{\text{hypotenuse}}
Tangenttant=oppositeadjacent\tan t = \dfrac{\text{opposite}}{\text{adjacent}}

A common mnemonic for remembering these relationships is SohCahToa, formed from the first letters of “Sine is opposite over hypotenuse, Cosine is adjacent over hypotenuse, Tangent is opposite over adjacent.” The adjacent side is the side closest to the angle. The opposite side is the side across from the angle. The hypotenuse is the side of the triangle opposite the right angle.

Section 3

Reciprocal Trigonometric Functions

Property

In addition to sine, cosine, and tangent, there are three more functions. These too are defined in terms of the sides of the triangle.

FunctionDefinition
Secantsect=hypotenuseadjacent\sec t = \dfrac{\text{hypotenuse}}{\text{adjacent}}
Cosecantcsct=hypotenuseopposite\csc t = \dfrac{\text{hypotenuse}}{\text{opposite}}
Cotangentcott=adjacentopposite\cot t = \dfrac{\text{adjacent}}{\text{opposite}}

These functions are the reciprocals of the first three functions:

Section 4

Functions of Special Angles

Property

When dealing with right triangles, we can evaluate trigonometric functions of special angles using side length ratios. A 30,60,9030^\circ, 60^\circ, 90^\circ triangle, also known as a π6,π3,π2\frac{\pi}{6}, \frac{\pi}{3}, \frac{\pi}{2} triangle, has side lengths in the relation s,s3,2ss, s\sqrt{3}, 2s. A 45,45,9045^\circ, 45^\circ, 90^\circ triangle, also known as a π4,π4,π2\frac{\pi}{4}, \frac{\pi}{4}, \frac{\pi}{2} triangle, has side lengths in the relation s,s,s2s, s, s\sqrt{2}. We can use these ratios to find exact values.

Examples

  • To find the value of sin(45)\sin(45^\circ), we use the side ratios of a 45459045^\circ-45^\circ-90^\circ triangle (s,s,s2s, s, s\sqrt{2}). Thus, sin(45)=oppositehypotenuse=ss2=12=22\sin(45^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{s}{s\sqrt{2}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}.
  • To evaluate cos(60)\cos(60^\circ), we use a 30609030^\circ-60^\circ-90^\circ triangle. The side adjacent to the 6060^\circ angle is ss and the hypotenuse is 2s2s. So, cos(60)=adjacenthypotenuse=s2s=12\cos(60^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{s}{2s} = \frac{1}{2}.

Section 5

Cofunction Identities

Property

If any two angles are complementary, the sine of one is the cosine of the other, and vice versa. This is because in a right triangle, the side opposite one acute angle is the side adjacent to the other. The cofunction identities in radians are:

cost=sin(π2t)\cos t = \sin\left(\dfrac{\pi}{2} - t\right)sint=cos(π2t)\sin t = \cos\left(\dfrac{\pi}{2} - t\right)
tant=cot(π2t)\tan t = \cot\left(\dfrac{\pi}{2} - t\right)cott=tan(π2t)\cot t = \tan\left(\dfrac{\pi}{2} - t\right)
sect=csc(π2t)\sec t = \csc\left(\dfrac{\pi}{2} - t\right)csct=sec(π2t)\csc t = \sec\left(\dfrac{\pi}{2} - t\right)

Examples

  • If you are given that sin(15)0.259\sin(15^\circ) \approx 0.259, you can immediately know the cosine of its complement. Since 9015=7590^\circ - 15^\circ = 75^\circ, then cos(75)0.259\cos(75^\circ) \approx 0.259.

Section 6

Finding Missing Side Lengths

Property

Given a right triangle, the length of one side, and the measure of one acute angle, we can find the remaining sides. The process is as follows:

  1. For each side, select the trigonometric function that has the unknown side as either the numerator or the denominator. The known side will in turn be the denominator or the numerator.
  2. Write an equation setting the function value of the known angle equal to the ratio of the corresponding sides.
  3. Using the value of the trigonometric function and the known side length, solve for the missing side length.

Examples

  • In a right triangle with a 5050^\circ angle and a hypotenuse of 12, find the side xx opposite the angle. Use sine: sin(50)=x12\sin(50^\circ) = \frac{x}{12}, which gives x=12sin(50)9.19x = 12 \cdot \sin(50^\circ) \approx 9.19.
  • A right triangle has a 7070^\circ angle and the adjacent side is 4 units long. To find the opposite side yy, use tangent: tan(70)=y4\tan(70^\circ) = \frac{y}{4}, so y=4tan(70)10.99y = 4 \cdot \tan(70^\circ) \approx 10.99.

Section 7

Applied Problems with Right Triangles

Property

Right-triangle trigonometry can be used to measure heights and distances indirectly. Two key concepts are:

  • Angle of Elevation: The angle between the horizontal and the line from an object to an observer’s eye. It is used when an observer is looking up.
  • Angle of Depression: The angle between the horizontal and the line from an object to an observer’s eye. It is used when an observer is looking down.

Examples

  • A person stands 100 feet from the base of a tower. The angle of elevation to the top of the tower is 4040^\circ. The height hh is found using tan(40)=h100\tan(40^\circ) = \frac{h}{100}, so h=100tan(40)83.9h = 100 \cdot \tan(40^\circ) \approx 83.9 feet.
  • From the top of a 150-foot cliff, the angle of depression to a boat on the water is 2020^\circ. The distance dd from the base of the cliff to the boat is found using tan(20)=150d\tan(20^\circ) = \frac{150}{d}, so d=150tan(20)412.1d = \frac{150}{\tan(20^\circ)} \approx 412.1 feet.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: The Unit Circle: Sine and Cosine Functions

  1. Lesson 1

    Lesson 7.1 : Angles

  2. Lesson 2Current

    Lesson 7.2 : Right Triangle Trigonometry

  3. Lesson 3

    Lesson 7.3 : Unit Circle

  4. Lesson 4

    Lesson 7.4 : The Other Trigonometric Functions

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Right Triangle Trigonometry

New Concept

Right triangle trigonometry defines functions like sine and cosine as ratios of a triangle's sides (e.g., sint=oppositehypotenuse\operatorname{sin} t = \frac{\text{opposite}}{\text{hypotenuse}}). This powerful tool helps us find unknown side lengths and angles, and solve practical problems like measuring heights.

What’s next

Next, you’ll master these concepts through a series of practice cards, tackling everything from special angles to real-world challenge problems.

Section 2

Right Triangle Trigonometric Functions

Property

Given a right triangle with an acute angle of tt, the first three trigonometric functions are listed.

FunctionDefinition
Sinesint=oppositehypotenuse\sin t = \dfrac{\text{opposite}}{\text{hypotenuse}}
Cosinecost=adjacenthypotenuse\cos t = \dfrac{\text{adjacent}}{\text{hypotenuse}}
Tangenttant=oppositeadjacent\tan t = \dfrac{\text{opposite}}{\text{adjacent}}

A common mnemonic for remembering these relationships is SohCahToa, formed from the first letters of “Sine is opposite over hypotenuse, Cosine is adjacent over hypotenuse, Tangent is opposite over adjacent.” The adjacent side is the side closest to the angle. The opposite side is the side across from the angle. The hypotenuse is the side of the triangle opposite the right angle.

Section 3

Reciprocal Trigonometric Functions

Property

In addition to sine, cosine, and tangent, there are three more functions. These too are defined in terms of the sides of the triangle.

FunctionDefinition
Secantsect=hypotenuseadjacent\sec t = \dfrac{\text{hypotenuse}}{\text{adjacent}}
Cosecantcsct=hypotenuseopposite\csc t = \dfrac{\text{hypotenuse}}{\text{opposite}}
Cotangentcott=adjacentopposite\cot t = \dfrac{\text{adjacent}}{\text{opposite}}

These functions are the reciprocals of the first three functions:

Section 4

Functions of Special Angles

Property

When dealing with right triangles, we can evaluate trigonometric functions of special angles using side length ratios. A 30,60,9030^\circ, 60^\circ, 90^\circ triangle, also known as a π6,π3,π2\frac{\pi}{6}, \frac{\pi}{3}, \frac{\pi}{2} triangle, has side lengths in the relation s,s3,2ss, s\sqrt{3}, 2s. A 45,45,9045^\circ, 45^\circ, 90^\circ triangle, also known as a π4,π4,π2\frac{\pi}{4}, \frac{\pi}{4}, \frac{\pi}{2} triangle, has side lengths in the relation s,s,s2s, s, s\sqrt{2}. We can use these ratios to find exact values.

Examples

  • To find the value of sin(45)\sin(45^\circ), we use the side ratios of a 45459045^\circ-45^\circ-90^\circ triangle (s,s,s2s, s, s\sqrt{2}). Thus, sin(45)=oppositehypotenuse=ss2=12=22\sin(45^\circ) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{s}{s\sqrt{2}} = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}.
  • To evaluate cos(60)\cos(60^\circ), we use a 30609030^\circ-60^\circ-90^\circ triangle. The side adjacent to the 6060^\circ angle is ss and the hypotenuse is 2s2s. So, cos(60)=adjacenthypotenuse=s2s=12\cos(60^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{s}{2s} = \frac{1}{2}.

Section 5

Cofunction Identities

Property

If any two angles are complementary, the sine of one is the cosine of the other, and vice versa. This is because in a right triangle, the side opposite one acute angle is the side adjacent to the other. The cofunction identities in radians are:

cost=sin(π2t)\cos t = \sin\left(\dfrac{\pi}{2} - t\right)sint=cos(π2t)\sin t = \cos\left(\dfrac{\pi}{2} - t\right)
tant=cot(π2t)\tan t = \cot\left(\dfrac{\pi}{2} - t\right)cott=tan(π2t)\cot t = \tan\left(\dfrac{\pi}{2} - t\right)
sect=csc(π2t)\sec t = \csc\left(\dfrac{\pi}{2} - t\right)csct=sec(π2t)\csc t = \sec\left(\dfrac{\pi}{2} - t\right)

Examples

  • If you are given that sin(15)0.259\sin(15^\circ) \approx 0.259, you can immediately know the cosine of its complement. Since 9015=7590^\circ - 15^\circ = 75^\circ, then cos(75)0.259\cos(75^\circ) \approx 0.259.

Section 6

Finding Missing Side Lengths

Property

Given a right triangle, the length of one side, and the measure of one acute angle, we can find the remaining sides. The process is as follows:

  1. For each side, select the trigonometric function that has the unknown side as either the numerator or the denominator. The known side will in turn be the denominator or the numerator.
  2. Write an equation setting the function value of the known angle equal to the ratio of the corresponding sides.
  3. Using the value of the trigonometric function and the known side length, solve for the missing side length.

Examples

  • In a right triangle with a 5050^\circ angle and a hypotenuse of 12, find the side xx opposite the angle. Use sine: sin(50)=x12\sin(50^\circ) = \frac{x}{12}, which gives x=12sin(50)9.19x = 12 \cdot \sin(50^\circ) \approx 9.19.
  • A right triangle has a 7070^\circ angle and the adjacent side is 4 units long. To find the opposite side yy, use tangent: tan(70)=y4\tan(70^\circ) = \frac{y}{4}, so y=4tan(70)10.99y = 4 \cdot \tan(70^\circ) \approx 10.99.

Section 7

Applied Problems with Right Triangles

Property

Right-triangle trigonometry can be used to measure heights and distances indirectly. Two key concepts are:

  • Angle of Elevation: The angle between the horizontal and the line from an object to an observer’s eye. It is used when an observer is looking up.
  • Angle of Depression: The angle between the horizontal and the line from an object to an observer’s eye. It is used when an observer is looking down.

Examples

  • A person stands 100 feet from the base of a tower. The angle of elevation to the top of the tower is 4040^\circ. The height hh is found using tan(40)=h100\tan(40^\circ) = \frac{h}{100}, so h=100tan(40)83.9h = 100 \cdot \tan(40^\circ) \approx 83.9 feet.
  • From the top of a 150-foot cliff, the angle of depression to a boat on the water is 2020^\circ. The distance dd from the base of the cliff to the boat is found using tan(20)=150d\tan(20^\circ) = \frac{150}{d}, so d=150tan(20)412.1d = \frac{150}{\tan(20^\circ)} \approx 412.1 feet.

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: The Unit Circle: Sine and Cosine Functions

  1. Lesson 1

    Lesson 7.1 : Angles

  2. Lesson 2Current

    Lesson 7.2 : Right Triangle Trigonometry

  3. Lesson 3

    Lesson 7.3 : Unit Circle

  4. Lesson 4

    Lesson 7.4 : The Other Trigonometric Functions