Learn on PengiSaxon Math, Intermediate 4Chapter 7: Lessons 61–70, Investigation 7

Lesson 64: Division with Two-Digit Answers, Part 1

In Saxon Math Intermediate 4, Grade 4 students learn a step-by-step pencil-and-paper method for dividing two-digit numbers by a one-digit number, including how to place each digit of the quotient correctly in the tens and ones places. The lesson covers the full long division process — dividing, multiplying, subtracting, and bringing down — and shows students how to verify answers using the related multiplication fact from the fact family.

Section 1

📘 Division with Two-Digit Answers, Part 1

New Concept

In this lesson we will learn a pencil-and-paper method for dividing a two-digit number by a one-digit number.

What’s next

Next, you’ll apply this step-by-step process of dividing, multiplying, subtracting, and bringing down to solve problems with two-digit answers.

Section 2

Division with two-digit answers

Property

To divide a two-digit number, we use a step-by-step process. First, divide the tens digit. Then, multiply, subtract, and bring down the ones digit. Finally, divide the new number. The process is based on the formula: Number of groups ×\times Number in each group = Total.

  • To solve 4)964 \overline{)96}: First, 9÷49 \div 4 is 2. Multiply 2×4=82 \times 4 = 8. Subtract 98=19 - 8 = 1. Bring down the 6 to make 16. Then 16÷4=416 \div 4 = 4. The answer is 24.
  • To solve 3)843 \overline{)84}: First, 8÷38 \div 3 is 2. Multiply 2×3=62 \times 3 = 6. Subtract 86=28 - 6 = 2. Bring down the 4 to make 24. Then 24÷3=824 \div 3 = 8. The answer is 28.

Think of long division as a dance with four simple steps: Divide, Multiply, Subtract, and Bring Down! You repeat this rhythm until the problem is solved. This process breaks a huge division problem into tiny, manageable chunks. It’s a super organized way to make sure you handle every digit correctly, from the tens down to the ones place.

Section 3

Divisibility rule for 3

Property

A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, for the number 87, we add the digits: 8+7=158 + 7 = 15. Since 15 is a multiple of 3, the number 87 is divisible by 3.

  • Can 75 be divided by 3? Check: 7+5=127 + 5 = 12. Since 12 is a multiple of 3, the answer is yes. 75÷3=2575 \div 3 = 25.
  • Can 92 be divided by 3? Check: 9+2=119 + 2 = 11. Since 11 is not a multiple of 3, the answer is no.
  • Can 45 be divided by 3? Check: 4+5=94 + 5 = 9. Since 9 is a multiple of 3, the answer is yes. 45÷3=1545 \div 3 = 15.

Want to know if a number can be friends with 3, meaning it divides by 3 with no leftovers? Don't guess! Just add up its digits. If that sum is in the 3-times-table, like 3, 6, 9, or 12, then the original number is too! It's a super-secret handshake that only multiples of 3 know.

Section 4

Estimating with compatible numbers

Property

To find a reasonable estimate for a division problem, replace the dividend with a nearby compatible number that divides evenly by the divisor. For 38÷438 \div 4, you can use 36 or 40 to make the division easier and find an approximate answer.

  • To estimate 53÷553 \div 5: Compatible numbers near 53 are 50 or 55. A good estimate is 50÷5=1050 \div 5 = 10 or 55÷5=1155 \div 5 = 11.
  • Estimate how many 8-dollar tickets you can buy with 43 dollars. Use 40 as a compatible number. 40÷8=540 \div 8 = 5. So, about 5 tickets.
  • To estimate 74÷574 \div 5: A compatible number near 74 is 75. 75÷5=1575 \div 5 = 15. So, a reasonable estimate is 15.

Division can be messy if the numbers don't play nice, so be a matchmaker! Instead of struggling with a tough problem, swap the main number for a nearby 'compatible' one that gets along great with your divisor. This trick gives you a quick, smart estimate without all the hard work. It's about working smarter, not harder!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

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Chapter 7: Lessons 61–70, Investigation 7

  1. Lesson 1

    Lesson 61: Remaining Fraction, Two-Step Equations

  2. Lesson 2

    Lesson 62: Multiplying Three or More Factors, Exponents

  3. Lesson 3

    Lesson 63: Polygons

  4. Lesson 4Current

    Lesson 64: Division with Two-Digit Answers, Part 1

  5. Lesson 5

    Lesson 65: Division with Two-Digit Answers, Part 2

  6. Lesson 6

    Lesson 66: Similar and Congruent Figures

  7. Lesson 7

    Lesson 67: Multiplying by Multiples of 10

  8. Lesson 8

    Lesson 68: Division with Two-Digit Answers and a Remainder

  9. Lesson 9

    Lesson 69: Millimeters

  10. Lesson 10

    Lesson 70: Word Problems About a Fraction of a Group

  11. Lesson 11

    Investigation 7: Collecting Data with Surveys, Activity Class Survey

Lesson overview

Expand to review the lesson summary and core properties.

Expand

Section 1

📘 Division with Two-Digit Answers, Part 1

New Concept

In this lesson we will learn a pencil-and-paper method for dividing a two-digit number by a one-digit number.

What’s next

Next, you’ll apply this step-by-step process of dividing, multiplying, subtracting, and bringing down to solve problems with two-digit answers.

Section 2

Division with two-digit answers

Property

To divide a two-digit number, we use a step-by-step process. First, divide the tens digit. Then, multiply, subtract, and bring down the ones digit. Finally, divide the new number. The process is based on the formula: Number of groups ×\times Number in each group = Total.

  • To solve 4)964 \overline{)96}: First, 9÷49 \div 4 is 2. Multiply 2×4=82 \times 4 = 8. Subtract 98=19 - 8 = 1. Bring down the 6 to make 16. Then 16÷4=416 \div 4 = 4. The answer is 24.
  • To solve 3)843 \overline{)84}: First, 8÷38 \div 3 is 2. Multiply 2×3=62 \times 3 = 6. Subtract 86=28 - 6 = 2. Bring down the 4 to make 24. Then 24÷3=824 \div 3 = 8. The answer is 28.

Think of long division as a dance with four simple steps: Divide, Multiply, Subtract, and Bring Down! You repeat this rhythm until the problem is solved. This process breaks a huge division problem into tiny, manageable chunks. It’s a super organized way to make sure you handle every digit correctly, from the tens down to the ones place.

Section 3

Divisibility rule for 3

Property

A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, for the number 87, we add the digits: 8+7=158 + 7 = 15. Since 15 is a multiple of 3, the number 87 is divisible by 3.

  • Can 75 be divided by 3? Check: 7+5=127 + 5 = 12. Since 12 is a multiple of 3, the answer is yes. 75÷3=2575 \div 3 = 25.
  • Can 92 be divided by 3? Check: 9+2=119 + 2 = 11. Since 11 is not a multiple of 3, the answer is no.
  • Can 45 be divided by 3? Check: 4+5=94 + 5 = 9. Since 9 is a multiple of 3, the answer is yes. 45÷3=1545 \div 3 = 15.

Want to know if a number can be friends with 3, meaning it divides by 3 with no leftovers? Don't guess! Just add up its digits. If that sum is in the 3-times-table, like 3, 6, 9, or 12, then the original number is too! It's a super-secret handshake that only multiples of 3 know.

Section 4

Estimating with compatible numbers

Property

To find a reasonable estimate for a division problem, replace the dividend with a nearby compatible number that divides evenly by the divisor. For 38÷438 \div 4, you can use 36 or 40 to make the division easier and find an approximate answer.

  • To estimate 53÷553 \div 5: Compatible numbers near 53 are 50 or 55. A good estimate is 50÷5=1050 \div 5 = 10 or 55÷5=1155 \div 5 = 11.
  • Estimate how many 8-dollar tickets you can buy with 43 dollars. Use 40 as a compatible number. 40÷8=540 \div 8 = 5. So, about 5 tickets.
  • To estimate 74÷574 \div 5: A compatible number near 74 is 75. 75÷5=1575 \div 5 = 15. So, a reasonable estimate is 15.

Division can be messy if the numbers don't play nice, so be a matchmaker! Instead of struggling with a tough problem, swap the main number for a nearby 'compatible' one that gets along great with your divisor. This trick gives you a quick, smart estimate without all the hard work. It's about working smarter, not harder!

Book overview

Jump across lessons in the current chapter without opening the full course modal.

Continue this chapter

Chapter 7: Lessons 61–70, Investigation 7

  1. Lesson 1

    Lesson 61: Remaining Fraction, Two-Step Equations

  2. Lesson 2

    Lesson 62: Multiplying Three or More Factors, Exponents

  3. Lesson 3

    Lesson 63: Polygons

  4. Lesson 4Current

    Lesson 64: Division with Two-Digit Answers, Part 1

  5. Lesson 5

    Lesson 65: Division with Two-Digit Answers, Part 2

  6. Lesson 6

    Lesson 66: Similar and Congruent Figures

  7. Lesson 7

    Lesson 67: Multiplying by Multiples of 10

  8. Lesson 8

    Lesson 68: Division with Two-Digit Answers and a Remainder

  9. Lesson 9

    Lesson 69: Millimeters

  10. Lesson 10

    Lesson 70: Word Problems About a Fraction of a Group

  11. Lesson 11

    Investigation 7: Collecting Data with Surveys, Activity Class Survey